結果
| 問題 |
No.1488 Max Score of the Tree
|
| コンテスト | |
| ユーザー |
tamato
|
| 提出日時 | 2021-04-23 21:43:45 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 1,403 bytes |
| コンパイル時間 | 345 ms |
| コンパイル使用メモリ | 82,688 KB |
| 実行使用メモリ | 148,736 KB |
| 最終ジャッジ日時 | 2024-07-04 07:48:37 |
| 合計ジャッジ時間 | 6,471 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 12 WA * 17 |
ソースコード
mod = 1000000007
eps = 10**-9
def main():
import sys
from collections import deque
input = sys.stdin.readline
N, K = map(int, input().split())
adj = [[] for _ in range(N+1)]
for _ in range(N-1):
a, b, c = map(int, input().split())
adj[a].append((b, c))
adj[b].append((a, c))
que = deque()
que.append(1)
seen = [-1] * (N+1)
seen[1] = 0
par = [None] * (N+1)
child = [[] for _ in range(N+1)]
seq = []
depth = [0] * (N+1)
while que:
v = que.popleft()
seq.append(v)
for u, c in adj[v]:
if seen[u] == -1:
seen[u] = seen[v] + 1
par[u] = (v, c)
child[v].append(u)
que.append(u)
depth[u] = depth[v] + c
seq.reverse()
D = 0
for v in seq:
if child[v]:
continue
D += depth[v]
dp = [[D] * (K+1) for _ in range(N+1)]
L = [0] * (N+1)
for v in seq:
if not child[v]:
L[v] = 1
else:
for u in child[v]:
L[v] += L[u]
if v != 1:
p, c = par[v]
for j in range(K+1):
dp[p][j] = max(dp[p][j], dp[v][j])
if j + c <= K:
dp[p][j+c] = max(dp[p][j+c], dp[v][j] + c * L[v])
print(max(dp[1]))
if __name__ == '__main__':
main()
tamato