結果
| 問題 | No.1488 Max Score of the Tree | 
| コンテスト | |
| ユーザー |  tamato | 
| 提出日時 | 2021-04-23 21:48:39 | 
| 言語 | PyPy3 (7.3.15) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 297 ms / 2,000 ms | 
| コード長 | 1,480 bytes | 
| コンパイル時間 | 143 ms | 
| コンパイル使用メモリ | 82,432 KB | 
| 実行使用メモリ | 144,896 KB | 
| 最終ジャッジ日時 | 2024-07-04 07:53:59 | 
| 合計ジャッジ時間 | 6,102 ms | 
| ジャッジサーバーID (参考情報) | judge3 / judge2 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 29 | 
ソースコード
mod = 1000000007
eps = 10**-9
def main():
    import sys
    from collections import deque
    input = sys.stdin.readline
    N, K = map(int, input().split())
    adj = [[] for _ in range(N+1)]
    for _ in range(N-1):
        a, b, c = map(int, input().split())
        adj[a].append((b, c))
        adj[b].append((a, c))
    que = deque()
    que.append(1)
    seen = [-1] * (N+1)
    seen[1] = 0
    par = [None] * (N+1)
    child = [[] for _ in range(N+1)]
    seq = []
    depth = [0] * (N+1)
    while que:
        v = que.popleft()
        seq.append(v)
        for u, c in adj[v]:
            if seen[u] == -1:
                seen[u] = seen[v] + 1
                par[u] = (v, c)
                child[v].append(u)
                que.append(u)
                depth[u] = depth[v] + c
    seq.reverse()
    D = 0
    for v in seq:
        if child[v]:
            continue
        D += depth[v]
    dp = [[D] * (K+1) for _ in range(N)]
    L = [0] * (N+1)
    E = []
    for v in seq:
        if not child[v]:
            L[v] = 1
        else:
            for u in child[v]:
                L[v] += L[u]
        if v != 1:
            p, c = par[v]
            E.append((c, c * L[v]))
    for i in range(N-1):
        w, v = E[i]
        for j in range(K+1):
            dp[i+1][j] = max(dp[i+1][j], dp[i][j])
            if j + w <= K:
                dp[i+1][j+w] = max(dp[i+1][j+w], dp[i][j] + v)
    print(max(dp[-1]))
if __name__ == '__main__':
    main()
            
            
            
        