結果
問題 | No.1494 LCS on Tree |
ユーザー | fastmath |
提出日時 | 2021-04-30 22:10:03 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 131 ms / 2,000 ms |
コード長 | 3,560 bytes |
コンパイル時間 | 1,338 ms |
コンパイル使用メモリ | 130,304 KB |
最終ジャッジ日時 | 2025-01-21 03:09:23 |
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 47 |
ソースコード
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cmath> #include <vector> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <queue> #include <ctime> #include <cassert> #include <complex> #include <string> #include <cstring> #include <chrono> #include <random> #include <bitset> #include <fstream> using namespace std; #define int long long #define ii pair <int, int> #define app push_back #define all(a) a.begin(), a.end() #define bp __builtin_popcountll #define ll long long #define mp make_pair #define x first #define y second #define Time (double)clock()/CLOCKS_PER_SEC #define debug(x) std::cerr << #x << ": " << x << '\n'; #define FOR(i, n) for (int i = 0; i < n; ++i) #define FORN(i, n) for (int i = 1; i <= n; ++i) #define pb push_back #define trav(a, x) for (auto& a : x) using vi = vector<int>; template <typename T> std::istream& operator >>(std::istream& input, std::vector<T>& data) { for (T& x : data) input >> x; return input; } template <typename T> std::ostream& operator <<(std::ostream& output, const pair <T, T> & data) { output << "(" << data.x << "," << data.y << ")"; return output; } template <typename T> std::ostream& operator <<(std::ostream& output, const std::vector<T>& data) { for (const T& x : data) output << x << " "; return output; } ll div_up(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up ll div_down(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down ll math_mod(ll a, ll b) { return a - b * div_down(a, b); } #define tcT template<class T #define tcTU tcT, class U tcT> using V = vector<T>; tcT> void re(V<T>& x) { trav(a, x) cin >> a; } tcT> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } // set a = min(a,b) tcT> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll gcd(ll a, ll b) { while (b) { tie(a, b) = mp(b, a % b); } return a; } const int N = 2007; int pref[N][N], suf[N][N]; int n, len; string s; V <pair <int, char> > g[N]; int ans = 0; void dfs(int u, int p, char c) { trav (e, g[u]) { int v = e.x; char go = e.y; if (v != p) { dfs(v, u, go); FOR (i, len + 1) { ckmax(ans, pref[u][i] + suf[v][len - i]); ckmax(ans, pref[v][i] + suf[u][len - i]); } FOR (i, len + 1) { ckmax(pref[u][i], pref[v][i]); ckmax(suf[u][i], suf[v][i]); } } } if (u != 1) { for (int i = len - 1; i >= 0; --i) { if (s[i] == c) { ckmax(pref[u][i + 1], pref[u][i] + 1); } } FOR (i, len) { ckmax(pref[u][i + 1], pref[u][i]); } for (int i = len - 1; i >= 0; --i) { int p = len - 1 - i; if (s[p] == c) { ckmax(suf[u][i + 1], suf[u][i] + 1); } } FOR (i, len) { ckmax(suf[u][i + 1], suf[u][i]); } } FOR (i, len + 1) { ckmax(ans, pref[u][i]); ckmax(ans, suf[u][i]); } } signed main() { #ifdef LOCAL #else #define endl '\n' ios_base::sync_with_stdio(0); cin.tie(0); #endif cin >> n; cin >> s; len = s.size(); FOR (i, n - 1) { int u, v; char c; cin >> u >> v >> c; g[u].app(mp(v, c)); g[v].app(mp(u, c)); } dfs(1, 1, 0); cout << ans << endl; }