#652785 (C++17) No.1495 パンの仕入れ

提出ソース

結果

問題	No.1495 パンの仕入れ
ユーザー	hitonanode
提出日時	2021-04-30 22:32:12
言語	C++17 (gcc 12.3.0 + boost 1.83.0)
結果	WA
実行時間	-
コード長	6,619 bytes
コンパイル時間	2,111 ms
コンパイル使用メモリ	209,812 KB
実行使用メモリ	9,472 KB
最終ジャッジ日時	2024-07-19 02:08:42
合計ジャッジ時間	8,248 ms
ジャッジサーバーID （参考情報）	judge3 / judge2

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	AC	2 ms 5,248 KB
testcase_01	AC	2 ms 5,376 KB
testcase_02	AC	183 ms 5,376 KB
testcase_03	AC	190 ms 5,376 KB
testcase_04	AC	199 ms 5,376 KB
testcase_05	AC	198 ms 5,376 KB
testcase_06	AC	188 ms 5,376 KB
testcase_07	AC	194 ms 5,376 KB
testcase_08	AC	194 ms 5,376 KB
testcase_09	AC	198 ms 5,376 KB
testcase_10	AC	193 ms 5,376 KB
testcase_11	AC	191 ms 5,376 KB
testcase_12	AC	44 ms 5,376 KB
testcase_13	AC	44 ms 5,376 KB
testcase_14	AC	43 ms 5,376 KB
testcase_15	AC	42 ms 5,376 KB
testcase_16	AC	44 ms 5,376 KB
testcase_17	AC	45 ms 5,376 KB
testcase_18	AC	45 ms 5,376 KB
testcase_19	AC	44 ms 5,376 KB
testcase_20	AC	43 ms 5,376 KB
testcase_21	AC	42 ms 5,376 KB
testcase_22	AC	212 ms 9,344 KB
testcase_23	AC	212 ms 9,344 KB
testcase_24	WA	-
testcase_25	WA	-
testcase_26	WA	-
testcase_27	WA	-
testcase_28	AC	209 ms 9,344 KB
testcase_29	AC	209 ms 9,472 KB
testcase_30	AC	36 ms 5,376 KB
testcase_31	AC	36 ms 5,376 KB
testcase_32	AC	36 ms 5,376 KB
testcase_33	AC	37 ms 5,376 KB
testcase_34	AC	37 ms 5,376 KB
testcase_35	AC	44 ms 5,376 KB
testcase_36	AC	44 ms 5,376 KB
testcase_37	AC	44 ms 5,376 KB
testcase_38	AC	43 ms 5,376 KB
testcase_39	AC	45 ms 5,376 KB
testcase_40	AC	33 ms 5,376 KB
testcase_41	AC	34 ms 5,376 KB
testcase_42	AC	34 ms 5,376 KB
testcase_43	AC	33 ms 5,376 KB
testcase_44	AC	33 ms 5,376 KB
testcase_45	AC	1 ms 5,376 KB
testcase_46	AC	3 ms 5,376 KB
testcase_47	AC	2 ms 5,376 KB

権限があれば一括ダウンロードができます

ソースコード

raw source code

#include <bits/stdc++.h>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T, typename V>
void ndarray(vector<T>& vec, const V& val, int len) { vec.assign(len, val); }
template <typename T, typename V, typename... Args> void ndarray(vector<T>& vec, const V& val, int len, Args... args) { vec.resize(len), for_each(begin(vec), end(vec), [&](T& v) { ndarray(v, val, args...); }); }
template <typename T> bool chmax(T &m, const T q) { if (m < q) {m = q; return true;} else return false; }
template <typename T> bool chmin(T &m, const T q) { if (m > q) {m = q; return true;} else return false; }
int floor_lg(long long x) { return x <= 0 ? -1 : 63 - __builtin_clzll(x); }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T> vector<T> sort_unique(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T, size_t sz> ostream &operator<<(ostream &os, const array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T, typename TH> ostream &operator<<(ostream &os, const unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV, typename TH> ostream &operator<<(ostream &os, const unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
const string COLOR_RESET = "\033[0m", BRIGHT_GREEN = "\033[1;32m", BRIGHT_RED = "\033[1;31m", BRIGHT_CYAN = "\033[1;36m", NORMAL_CROSSED = "\033[0;9;37m", RED_BACKGROUND = "\033[1;41m", NORMAL_FAINT = "\033[0;2m";
#define dbg(x) cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl
#else
#define dbg(x) (x)
#endif

__int128 str2i128(std::string str) {
    __int128 ret = 0;
    bool minus = false;
    for (auto c : str) {
        if (c == '-')
            minus = true;
        else
            ret = ret * 10 + c - '0';
    }
    return minus ? -ret : ret;
}
std::istream &operator>>(std::istream &is, __int128 &x) {
    std::string s;
    return is >> s, x = str2i128(s), is;
}
std::ostream &operator<<(std::ostream &os, const __int128 &x) {
    __int128 tmp = x;
    if (tmp == 0) return os << 0;
    std::vector<int> ds;
    if (tmp < 0) {
        os << '-';
        while (tmp) {
            int d = tmp % 10;
            if (d > 0) d -= 10;
            ds.emplace_back(-d), tmp = (tmp - d) / 10;
        }
    } else {
        while (tmp) ds.emplace_back(tmp % 10), tmp /= 10;
    }
    std::reverse(ds.begin(), ds.end());
    for (auto i : ds) os << i;
    return os;
}

template <typename T> T divfloor(T num, T den) {
    if (den < 0) den = -den, num = -num;
    if (num % den == 0 or num >= 0) return num / den;
    return -((-num) / den) - 1;
}

lint solve() {
    int N, M, K;
    cin >> N >> M >> K;
    vector<lint> a(N), b(N), c(N);
    while (M--) {
        int x;
        lint y;
        cin >> x >> y;
        x--;
        a[x]++;
        b[x] -= y * 2;
        c[x] += y * y;
    }
    dbg(a);
    dbg(b);
    dbg(c);
    __int128 few = -(1LL << 34), much = 1LL << 34;
    if (*min_element(ALL(a)) == 0) {
        much = 0;
    }

    auto cnt_lesseq = [&](__int128 thres) -> __int128 {
        __int128 cnt_less = 0;
        REP(i, N) if (a[i]) {
            __int128 xlo = divfloor<__int128>(thres + a[i] - b[i], 2 * a[i]);
            if (xlo < 0) xlo = 0;
            cnt_less += xlo;
        }
        return cnt_less;
    };
    while (much - few > 1) {
        const __int128 thres = (few + much) / 2;
        if (cnt_lesseq(thres) < K) few = thres;
        else much = thres;
    }
    vector<lint> nb(N);
    int nfree = 0;
    __int128 ume = much;
    REP(i, N) {
        if (a[i]) nb[i] = divfloor<__int128>(few + a[i] - b[i], 2 * a[i]);
        else nfree++, ume = min(ume, __int128(0));
        if (nb[i] < 0) nb[i] = 0;
    }
    dbg(few);
    dbg(cnt_lesseq(few));
    dbg(nb);
    lint ret = 0;
    REP(i, N) ret += a[i] * nb[i] * nb[i] + b[i] * nb[i] + c[i];
    int yo = K - accumulate(ALL(nb), 0);
    ret += yo * ume;
    return ret;
}

int main() {
    int T;
    cin >> T;
    while (T--) cout << solve() << '\n';
}

yukicoder

結果

テストケース

ソースコード