結果

問題 No.310 2文字しりとり
ユーザー pekempey
提出日時 2015-12-13 15:23:41
言語 C++11（廃止可能性あり）
(gcc 13.3.0)
結果
WA  
実行時間 -
コード長 3,850 bytes
コンパイル時間 2,860 ms
コンパイル使用メモリ 170,500 KB
実行使用メモリ 634,240 KB
最終ジャッジ日時 2024-09-15 11:42:40
合計ジャッジ時間 9,881 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 14 WA * 7 MLE * 1 -- * 6
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In member function ‘std::vector<long long int> SparseDeterminant::minpoly_vector(std::vector<std::vector<long long int> >)’:
main.cpp:60:9: warning: no return statement in function returning non-void [-Wreturn-type]
   60 |         }
      |         ^
main.cpp: In member function ‘std::vector<long long int> SparseDeterminant::minpoly_matrix(std::vector<std::vector<long long int> >)’:
main.cpp:64:9: warning: no return statement in function returning non-void [-Wreturn-type]
   64 |         }
      |         ^

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define GET_MACRO(a, b, c, NAME, ...) NAME
#define rep(...) GET_MACRO(__VA_ARGS__, rep3, rep2)(__VA_ARGS__)
#define rep2(i, a) rep3 (i, 0, a)
#define rep3(i, a, b) for (int i = (a); i < (b); i++)
#define repr(...) GET_MACRO(__VA_ARGS__, repr3, repr2)(__VA_ARGS__)
#define repr2(i, a) repr3 (i, 0, a)
#define repr3(i, a, b) for (int i = (b) - 1; i >= (a); i--)
template<class T1, class T2> inline bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); }
template<class T1, class T2> inline bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }
using namespace std;
typedef long long ll;
const ll mod = 1e9 + 7;
struct SparseDeterminant {
    unsigned long long xor64() {
        static unsigned long long x = time(NULL);
        x ^= x << 13; x ^= x >> 7; x ^= x << 17;
        return x;
    }
    vector<ll> random_vector(int n) {
        vector<ll> res(n);
        rep (i, n) res[i] = xor64() % mod;
        return res;
    }
    // Berlekamp-Massey algorithm
    vector<ll> minpoly(vector<ll> a) {
        const int N = a.size();
        vector<ll> b(N), c(N), t(N);
        b[0] = 1;
        c[0] = 1;
        int l = 0;
        int m = -1;
        for (int n = 0; n < N; n++) {
            int d = 0;
            for (int i = 0; i <= l; i++) {
                (d += c[i] * a[n - i]) %= mod;
            }
            if (d == 1) {
                t = c;
                int N_M = n - m;
                for (int j = 0; j < N - N_M; j++) {
                    (c[N_M + j] += b[j]) %= mod;
                }
                if (l <= n / 2) {
                    l = n + 1 - l;
                    m = n;
                    b = t;
                }
            }
        }
        return c;
    }
    vector<ll> minpoly_vector(vector<vector<ll>> b) {
        // TODO: implement
    }
    vector<ll> minpoly_matrix(vector<vector<ll>> A) {
        // TODO: implement
    }
};
ll F[5050];
ll modpow(ll a, ll b, ll mod) {
    ll res = 1;
    while (b) {
        if (b & 1) (res *= a) %= mod;
        (a *= a) %= mod;
        b /= 2;
    }
    return res;
}
ll modinv(ll a, ll mod) {
    return modpow(a, mod - 2, mod);
}
void show(vector<vector<ll>> A) {
    rep (i, A.size()) {
        rep (j, A[0].size()) {
            cout << A[i][j] << " ";
        }
        cout << endl;
    }
    cout << endl;
}
ll det(vector<vector<ll>> A) {
    int n = A.size();
    rep (j, n) {
        rep (i, j, n) {
            if (A[i][j] != 0) {
                swap(A[j], A[i]);
                break;
            }
        }
        ll inv = modinv(A[j][j], mod);
        rep (i, j + 1, n) {
            repr (k, j, n) {
                A[i][k] -= A[i][j] * A[j][k] % mod * inv % mod;
                if (A[i][k] < 0) A[i][k] += mod;
            }
        }
    }
    ll res = 1;
    rep (i, n) (res *= A[i][i]) %= mod;
    return res;
}
vector<vector<ll>> remove(vector<vector<ll>> A, int y, int x) {
    int N = A.size();
    rep (i, N) {
        rep (j, x, N - 1) A[i][j] = A[i][j + 1];
    }
    rep (j, N) {
        rep (i, y, N - 1) A[i][j] = A[i + 1][j];
    }
    rep (i, N) A[i].resize(N - 1);
    A.resize(N - 1);
    return A;
}
int main() {
    F[0] = 1;
    rep (i, 1, 5050) F[i] = i * F[i - 1] % mod;
    int N, M;
    cin >> N >> M;
    vector<vector<ll>> L(N, vector<ll>(N)); // laplacian matrix
    vector<vector<ll>> A(N, vector<ll>(N)); // adjacent matrix
    vector<vector<ll>> D(N, vector<ll>(N)); // degree matrix
    vector<int> outdeg(N, N), indeg(N, N);
    rep (i, N) rep (j, N) A[i][j] = 1;
    rep (i, N) D[i][i] = N;
    rep (i, M) {
        int u, v;
        cin >> u >> v;
        u--; v--;
        D[u][u]--;
        A[u][v] = 0;
        outdeg[u]--;
        indeg[v]--;
    }
    int u = -1, v = -1;
    rep (i, N) {
        if (indeg[i] == outdeg[i] - 1) {
            if (u == -1) {
                u = i;
            } else {
                cout << 0 << endl;
                return 0;
            }
        } else if (indeg[i] == outdeg[i] + 1) {
            if (v == -1) {
                v = i;
            } else {
                cout << 0 << endl;
                return 0;
            }
        } else if (indeg[i] != outdeg[i]) {
            cout << 0 << endl;
            return 0;
        }
    }
    bool cycle = false;
    if (u == -1 && v == -1) {
        u = 0, v = 0;
        cycle = true;
    } else if (u != -1 ^ v != -1) {
        cout << 0 << endl;
        return 0;
    }
    rep (i, N) rep (j, N) L[i][j] = D[i][j] - A[i][j];
    auto Lw = remove(L, u, u);
    ll d = det(Lw);
    ll ans = d;
    rep (i, N) (ans *= F[outdeg[i] - 1]) %= mod;
    if (cycle) (ans *= N * N - M) %= mod;
    cout << ans << endl;
    return 0;
}
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