結果
| 問題 |
No.1516 simple 門松列 problem Re:MASTER
|
| コンテスト | |
| ユーザー |
ansain
|
| 提出日時 | 2021-05-04 03:59:36 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 3,674 ms / 6,000 ms |
| コード長 | 3,001 bytes |
| コンパイル時間 | 367 ms |
| コンパイル使用メモリ | 82,124 KB |
| 実行使用メモリ | 88,480 KB |
| 最終ジャッジ日時 | 2024-10-09 04:27:14 |
| 合計ジャッジ時間 | 17,939 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 19 |
ソースコード
import sys
from collections import defaultdict, Counter, deque
from itertools import permutations, combinations, product, combinations_with_replacement, groupby, accumulate
import operator
from math import sqrt, gcd, factorial
# from math import isqrt, prod,comb # python3.8用(notpypy)
#from bisect import bisect_left,bisect_right
#from functools import lru_cache,reduce
#from heapq import heappush,heappop,heapify,heappushpop,heapreplace
#import numpy as np
#import networkx as nx
#from networkx.utils import UnionFind
#from numba import njit, b1, i1, i4, i8, f8
#from scipy.sparse import csr_matrix
#from scipy.sparse.csgraph import shortest_path, floyd_warshall, dijkstra, bellman_ford, johnson, NegativeCycleError
# numba例 @njit(i1(i4[:], i8[:, :]),cache=True) 引数i4配列、i8 2次元配列,戻り値i1
def input(): return sys.stdin.readline().rstrip()
def divceil(n, k): return 1+(n-1)//k # n/kの切り上げを返す
def yn(hantei, yes='Yes', no='No'): print(yes if hantei else no)
def check(a):
return a[0] != a[1] and a[1] != a[2] and a[2] != a[0] and a[1] in [max(a), min(a)]
def dot(a, b, MOD=10**9+7):
n=len(a)
ret = [[0] * n for _ in range(n)]
for i in range(n):
for j in range(n):
ret[i][j] = sum(a[i][k] * b[k][j] for k in range(n)) % MOD
return ret
def dot2(a, b, MOD=10**9+7):
n=len(a)
ret = [0] * n
for j in range(n):
ret[j] = sum(a[k] * b[k][j] for k in range(n)) % MOD
return ret
def matrix_multiplication(a, n, k, mod=10**9+7): # n次正方行列a^k
ans = [[int(i==j) for i in range(n)] for j in range(n)]
while k:
k, i = divmod(k, 2)
if i:
ans = dot(ans, a ,mod)
a = dot(a, a, mod)
return ans
def main():
mod = 10**9+7
mod2 = 998244353
n, k = map(int, input().split())
mat = [[0]*2*k*k for i in range(2*k*k)]
ans = [0]*2*k*k
for a in range(k):
for b in range(k):
for c in range(k):
if check([a, b, c]):
mat[a*k+b][b*k+c] += 1
mat[a*k+b+k**2][b*k+c+k**2] += 1
mat[a*k+b][b*k+c+k**2] += a
if a != b:
ans[a*k+b] += 1
ans[a*k+b+k**2] += a+b
newmat=[]
newans=[]
for x in range(2):
for a in range(k):
for b in range(k):
if a!=b:
tmp=[]
for y in range(2):
for c in range(k):
for d in range(k):
if c!=d:
tmp.append(mat[a*k+b+x*k**2][c*k+d+y*k**2])
newmat.append(tmp)
newans.append(ans[a*k+b+x*k**2])
mat2=matrix_multiplication(newmat, 2*k*(k-1), n-2, mod2)
ans2=dot2(newans,mat2,mod2)
#print(ans2[:k*k])
#print(ans2[k*k:])
print(sum(ans2[:k*(k-1)])%mod2,sum(ans2[k*(k-1):])%mod2)
if __name__ == '__main__':
main()
ansain