結果

問題 No.1488 Max Score of the Tree
ユーザー stoq
提出日時 2021-05-14 04:07:36
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 102 ms / 2,000 ms
コード長 3,307 bytes
コンパイル時間 2,535 ms
コンパイル使用メモリ 206,624 KB
最終ジャッジ日時 2025-01-21 10:51:01
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 29
権限があれば一括ダウンロードができます

ソースコード

diff # 

#define MOD_TYPE 2

#pragma region Macros

#include <bits/stdc++.h>
using namespace std;

#if 0
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif
#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif
using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;

constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353);
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr ld PI = acos(-1.0);
constexpr ld EPS = 1e-7;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};

#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";

struct io_init
{
  io_init()
  {
    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << setprecision(30) << setiosflags(ios::fixed);
  };
} io_init;
template <typename T>
inline bool chmin(T &a, T b)
{
  if (a > b)
  {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
inline bool chmax(T &a, T b)
{
  if (a < b)
  {
    a = b;
    return true;
  }
  return false;
}
inline ll CEIL(ll a, ll b)
{
  return (a + b - 1) / b;
}
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T &val)
{
  fill((T *)array, (T *)(array + N), val);
}
template <typename T, typename U>
constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept
{
  is >> p.first >> p.second;
  return is;
}
template <typename T, typename U>
constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept
{
  os << p.first << " " << p.second;
  return os;
}
#pragma endregion

// --------------------------------------

int n, k;
vector<pii> E[110];
int leaves[110] = {};
vector<pll> vec;
ll sum = 0;

int dfs0(int v, int p)
{
  if (E[v].size() == 1 and v != 0)
    return leaves[v] = 1;
  for (auto [c, l] : E[v])
  {
    if (c == p)
      continue;
    leaves[v] += dfs0(c, v);
    vec.push_back({leaves[c], l});
    sum += leaves[c] * l;
  }
  return leaves[v];
}

ll dp[110][100010] = {};

void solve()
{
  cin >> n >> k;
  rep(i, n - 1)
  {
    int a, b, c;
    cin >> a >> b >> c;
    a--, b--;
    E[a].push_back({b, c});
    E[b].push_back({a, c});
  }
  dfs0(0, -1);
  rep(i, n - 1) rep(j, k + 1)
  {
    auto [a, b] = vec[i];
    chmax(dp[i + 1][j], dp[i][j]);
    if (j + b <= k)
      chmax(dp[i + 1][j + b], dp[i][j] + a * b);
  }
  ll ans = 0;
  rep(j, k + 1) chmax(ans, dp[n - 1][j]);
  ans += sum;
  cout << ans << "\n";
}

int main()
{
  solve();
}
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