結果
問題 | No.1508 Avoid being hit |
ユーザー |
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提出日時 | 2021-05-15 20:10:40 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 25 ms / 3,000 ms |
コード長 | 5,202 bytes |
コンパイル時間 | 2,111 ms |
コンパイル使用メモリ | 198,996 KB |
最終ジャッジ日時 | 2025-01-21 13:03:27 |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 43 |
ソースコード
#define LOCAL #include <bits/stdc++.h> using namespace std; #pragma region Macros typedef long long ll; typedef __int128_t i128; typedef unsigned int uint; typedef unsigned long long ull; #define ALL(x) (x).begin(), (x).end() template <typename T> istream& operator>>(istream& is, vector<T>& v) { for (T& x : v) is >> x; return is; } template <typename T> ostream& operator<<(ostream& os, const vector<T>& v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << (i + 1 == (int)v.size() ? "" : " "); } return os; } template <typename T, typename U> ostream& operator<<(ostream& os, const pair<T, U>& p) { os << '(' << p.first << ',' << p.second << ')'; return os; } template <typename T, typename U, typename V> ostream& operator<<(ostream& os, const tuple<T, U, V>& t) { os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ')'; return os; } template <typename T, typename U, typename V, typename W> ostream& operator<<(ostream& os, const tuple<T, U, V, W>& t) { os << '(' << get<0>(t) << ',' << get<1>(t) << ',' << get<2>(t) << ',' << get<3>(t) << ')'; return os; } template <typename T, typename U> ostream& operator<<(ostream& os, const map<T, U>& m) { os << '{'; for (auto itr = m.begin(); itr != m.end();) { os << '(' << itr->first << ',' << itr->second << ')'; if (++itr != m.end()) os << ','; } os << '}'; return os; } template <typename T, typename U> ostream& operator<<(ostream& os, const unordered_map<T, U>& m) { os << '{'; for (auto itr = m.begin(); itr != m.end();) { os << '(' << itr->first << ',' << itr->second << ')'; if (++itr != m.end()) os << ','; } os << '}'; return os; } template <typename T> ostream& operator<<(ostream& os, const set<T>& s) { os << '{'; for (auto itr = s.begin(); itr != s.end();) { os << *itr; if (++itr != s.end()) os << ','; } os << '}'; return os; } template <typename T> ostream& operator<<(ostream& os, const multiset<T>& s) { os << '{'; for (auto itr = s.begin(); itr != s.end();) { os << *itr; if (++itr != s.end()) os << ','; } os << '}'; return os; } template <typename T> ostream& operator<<(ostream& os, const unordered_set<T>& s) { os << '{'; for (auto itr = s.begin(); itr != s.end();) { os << *itr; if (++itr != s.end()) os << ','; } os << '}'; return os; } template <typename T> ostream& operator<<(ostream& os, const deque<T>& v) { for (int i = 0; i < (int)v.size(); i++) { os << v[i] << (i + 1 == (int)v.size() ? "" : " "); } return os; } void debug_out() { cerr << '\n'; } template <class Head, class... Tail> void debug_out(Head&& head, Tail&&... tail) { cerr << head; if (sizeof...(Tail) > 0) cerr << ", "; debug_out(move(tail)...); } #ifdef LOCAL #define debug(...) \ cerr << " "; \ cerr << #__VA_ARGS__ << " :[" << __LINE__ << ":" << __FUNCTION__ << "]" << '\n'; \ cerr << " "; \ debug_out(__VA_ARGS__) #else #define debug(...) 42 #endif template <typename T> T gcd(T x, T y) { return y != 0 ? gcd(y, x % y) : x; } template <typename T> T lcm(T x, T y) { return x / gcd(x, y) * y; } template <class T1, class T2> inline bool chmin(T1& a, T2 b) { if (a > b) { a = b; return true; } return false; } template <class T1, class T2> inline bool chmax(T1& a, T2 b) { if (a < b) { a = b; return true; } return false; } #pragma endregion const int INF = 1e9; const long long IINF = 1e18; const int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1}; const char dir[4] = {'D', 'R', 'U', 'L'}; const long long MOD = 1000000007; // const long long MOD = 998244353; int main() { cin.tie(0); ios::sync_with_stdio(false); int N, Q; cin >> N >> Q; vector<int> A(Q), B(Q); for (int& x : A) cin >> x, x--; for (int& x : B) cin >> x, x--; vector<int> L(Q + 1), R(Q + 1); L[0] = 0, R[0] = N; for (int i = 0; i < Q; i++) { if (A[i] > B[i]) swap(A[i], B[i]); int l = L[i] - 1, r = R[i] + 1; while (l < 0 || l == A[i] || l == B[i]) { l++; if (l >= N) break; } while (r > N || r == A[i] + 1 || r == B[i] + 1) { r--; if (r == 0) break; } if (l >= r) { cout << "NO" << '\n'; return 0; } L[i + 1] = l, R[i + 1] = r; } vector<int> ans; ans.emplace_back(L[Q]); for (int i = Q - 1; i >= 0; i--) { int cur = ans.back(), nxt = -1; for (int pre : {cur - 1, cur, cur + 1}) { if (pre < L[i] || R[i] <= pre) continue; if (i && (pre == A[i - 1] || pre == B[i - 1])) continue; nxt = pre; } ans.emplace_back(nxt); } reverse(ans.begin(), ans.end()); cout << "YES" << '\n'; for (int& x : ans) cout << x + 1 << '\n'; return 0; }