結果

問題 No.318 学学学学学
ユーザー universatouniversato
提出日時 2021-05-18 11:29:15
言語 Ruby
(3.3.0)
結果
TLE  
実行時間 -
コード長 4,345 bytes
コンパイル時間 124 ms
コンパイル使用メモリ 7,680 KB
実行使用メモリ 41,888 KB
最終ジャッジ日時 2024-10-08 09:25:08
合計ジャッジ時間 7,203 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 323 ms
19,328 KB
testcase_01 AC 583 ms
16,768 KB
testcase_02 AC 699 ms
16,640 KB
testcase_03 AC 461 ms
15,488 KB
testcase_04 AC 611 ms
16,640 KB
testcase_05 TLE -
testcase_06 -- -
testcase_07 -- -
testcase_08 -- -
testcase_09 -- -
testcase_10 -- -
testcase_11 -- -
testcase_12 -- -
testcase_13 -- -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
testcase_26 -- -
testcase_27 -- -
testcase_28 -- -
権限があれば一括ダウンロードができます
コンパイルメッセージ
Syntax OK

ソースコード

diff #

# Segment tree with Lazy propagation
class LazySegtree
  attr_reader :d, :lz, :e, :id
  attr_accessor :op, :mapping, :composition

  # new(v, op, e, mapping, composition, id)
  # new(v, e, id, op, mapping, composition)
  # new(v, e, id){ |x, y|  }
  def initialize(v, a1, a2, a3 = nil, a4 = nil, a5 = nil, &op_block)
    if a1.is_a?(Proc)
      @op, @e, @mapping, @composition, @id = a1, a2, a3, a4, a5
    else
      @e, @id, @op, @mapping, @composition = a1, a2, a3, a4, a5
      @op ||= op_block
    end
    v = Array.new(v, @e) if v.is_a?(Integer)

    @n  = v.size

    @log  = (@n - 1).bit_length
    @size = 1 << @log
    @d    = Array.new(2 * @size, e)
    @lz   = Array.new(@size, id)

    @n.times { |i| @d[@size + i] = v[i] }
    (@size - 1).downto(1) { |i| update(i) }
  end

  def set_mapping(&mapping)
    @mapping = mapping
  end

  def set_composition(&composition)
    @composition = composition
  end

  def set(pos, x)
    pos += @size
    @log.downto(1) { |i| push(pos >> i) }
    @d[pos] = x
    1.upto(@log) { |i| update(pos >> i) }
  end
  alias []= set

  def get(pos)
    pos += @size
    @log.downto(1) { |i| push(pos >> i) }
    @d[pos]
  end
  alias [] get

  def prod(l, r)
    return @e if l == r

    l += @size
    r += @size

    @log.downto(1) do |i|
      push(l >> i) if (l >> i) << i != l
      push(r >> i) if (r >> i) << i != r
    end

    sml = @e
    smr = @e
    while l < r
      if l.odd?
        sml = @op.call(sml, @d[l])
        l += 1
      end
      if r.odd?
        r -= 1
        smr = @op.call(@d[r], smr)
      end
      l >>= 1
      r >>= 1
    end

    @op.call(sml, smr)
  end

  def all_prod
    @d[1]
  end

  # apply(pos, f)
  # apply(l, r, f) -> range_apply(l, r, f)
  def apply(pos, f, fr = nil)
    return range_apply(pos, f, fr) if fr

    pos += @size
    @log.downto(1) { |i| push(pos >> i) }
    @d[pos] = @mapping.call(f, @d[pos])
    1.upto(@log) { |i| update(pos >> i) }
  end

  def range_apply(l, r, f)
    return if l == r

    l += @size
    r += @size

    @log.downto(1) do |i|
      push(l >> i) if (l >> i) << i != l
      push((r - 1) >> i) if (r >> i) << i != r
    end

    l2 = l
    r2 = r
    while l < r
      (all_apply(l, f); l += 1) if l.odd?
      (r -= 1; all_apply(r, f)) if r.odd?
      l >>= 1
      r >>= 1
    end
    l = l2
    r = r2

    1.upto(@log) do |i|
      update(l >> i)       if (l >> i) << i != l
      update((r - 1) >> i) if (r >> i) << i != r
    end
  end

  def max_right(l, &g)
    return @n if l == @n

    l += @size
    @log.downto(1) { |i| push(l >> i) }
    sm = @e

    loop do
      while l.even?
        l >>= 1
      end
      unless g.call(@op.call(sm, @d[l]))
        while l < @size
          push(l)
          l <<= 1
          if g.call(@op.call(sm, @d[l]))
            sm = @op.call(sm, @d[l])
            l += 1
          end
        end
        return l - @size
      end
      sm = @op.call(sm, @d[l])
      l += 1
      break if l & -l == l
    end
    @n
  end

  def min_left(r, &g)
    return 0 if r == 0

    r += @size
    @log.downto(1) { |i| push((r - 1) >> i) }
    sm = @e

    loop do
      r -= 1
      while r > 1 && r.odd?
        r /= 2
      end
      unless g.call(@op.call(@d[r], sm))
        while r < @size
          push(r)
          r = r * 2 + 1
          if g.call(@op.call(@d[r], sm))
            sm = @op.call(@d[r], sm)
            r -= 1
          end
        end
        return r + 1 - @size
      end
      sm = @op.call(@d[r], sm)
      break if (r & -r) == r
    end
    0
  end

  def update(k)
    @d[k] = @op.call(@d[2 * k], @d[2 * k + 1])
  end

  def all_apply(k, f)
    @d[k]  = @mapping.call(f, @d[k])
    @lz[k] = @composition.call(f, @lz[k]) if k < @size
  end

  def push(k)
    all_apply(2 * k,     @lz[k])
    all_apply(2 * k + 1, @lz[k])
    @lz[k] = @id
  end
end

n = gets.to_s.to_i
a = gets.to_s.split.map{ |e| e.to_i }

h = Hash.new{ |h, k| h[k] = [] }
a.each_with_index{ |k, i| h[k].empty? ? h[k] << i : h[k][1] = i }

e = 0
op = ->(x, y){  }
id = 9**18
mapping = ->(f, x){ f == id ? x : f }
composition = ->(g, x){ g == id ? x : g }

st = LazySegtree.new(a, op, e, mapping, composition, id)

h.sort_by{ |k, _| k }.each do |k, indexes|
  l, r = indexes
  if r
    st.apply(l, r + 1, k)
  else
    st.set(l, k)
  end
end

puts (0...n).map{ |i| st[i] }.join(' ')
0