結果
問題 | No.1117 数列分割 |
ユーザー |
![]() |
提出日時 | 2021-05-19 02:16:32 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 1,073 ms / 3,000 ms |
コード長 | 2,371 bytes |
コンパイル時間 | 1,464 ms |
コンパイル使用メモリ | 124,808 KB |
最終ジャッジ日時 | 2025-01-21 13:50:17 |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 26 |
ソースコード
#include <iostream>#include <algorithm>#include <iomanip>#include <vector>#include <queue>#include <set>#include <map>#include <tuple>#include <cmath>#include <numeric>#include <functional>#include <cassert>#include <deque>#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }using namespace std;typedef long long ll;template <class T>class SlidingMaximum{public:deque<T> dq;vector<T> a;SlidingMaximum(int sz){a.resize(sz);}void push_right(int r, T x){a[r] = x;while(!dq.empty() && a[dq.back()] <= x) dq.pop_back();dq.push_back(r);}void pop_left(int l){while(!dq.empty() && dq.front() <= l) dq.pop_front();}T query(){return a[dq.front()];}};const ll INF = 1e18;ll dp[3001][3001];int main(){ios::sync_with_stdio(false);cin.tie(0);cout << setprecision(10) << fixed;int n, k, m; cin >> n >> k >> m;vector<ll> a(n+1), a_cumsum(n+2);for(int i = 1; i <= n; i++) {cin >> a[i];a_cumsum[i+1] = a_cumsum[i]+a[i];}for(int i = 0; i <= n; i++){for(int j = 0; j <= k; j++){dp[i][j] = -INF;}}dp[0][0] = 0;vector<SlidingMaximum<ll>> sm_pos(k+1, SlidingMaximum<ll>(n+1));vector<SlidingMaximum<ll>> sm_neg(k+1, SlidingMaximum<ll>(n+1));auto sect_sum = [&](int l, int r){ return a_cumsum[r]-a_cumsum[l]; };for(int i = 1; i <= n; i++){for(int j = 1; j <= k; j++){// [max(0, i-m), i)int l = max(0, i-m), r = i-1;// cout << dp[r][j-1] << endl;sm_pos[j-1].push_right(r, dp[r][j-1]+sect_sum(r+1, n+1));sm_pos[j-1].pop_left(l-1);sm_neg[j-1].push_right(r, dp[r][j-1]-sect_sum(r+1, n+1));sm_neg[j-1].pop_left(l-1);dp[i][j] = max(sm_pos[j-1].query()-sect_sum(i+1, n+1),sm_neg[j-1].query()+sect_sum(i+1, n+1));}}cout << dp[n][k] << endl;}