結果
| 問題 | No.1514 Squared Matching |
| コンテスト | |
| ユーザー |
keijak
|
| 提出日時 | 2021-05-21 22:43:22 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 3,281 bytes |
| コンパイル時間 | 1,938 ms |
| コンパイル使用メモリ | 195,948 KB |
| 最終ジャッジ日時 | 2025-01-21 15:54:07 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 9 TLE * 17 |
ソースコード
#include <bits/stdc++.h>
#define REP_(i, a_, b_, a, b, ...) \
for (int i = (a), END_##i = (b); i < END_##i; ++i)
#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)
#define ALL(x) std::begin(x), std::end(x)
using i64 = long long;
template <typename T, typename U>
inline bool chmax(T &a, U b) {
return a < b and ((a = std::move(b)), true);
}
template <typename T, typename U>
inline bool chmin(T &a, U b) {
return a > b and ((a = std::move(b)), true);
}
template <typename T>
inline int ssize(const T &a) {
return (int)std::size(a);
}
template <typename T>
std::istream &operator>>(std::istream &is, std::vector<T> &a) {
for (auto &x : a) is >> x;
return is;
}
template <typename T, typename U>
std::ostream &operator<<(std::ostream &os, const std::pair<T, U> &a) {
return os << "(" << a.first << ", " << a.second << ")";
}
template <typename Container>
std::ostream &print_seq(const Container &a, std::string_view sep = " ",
std::string_view ends = "\n",
std::ostream &os = std::cout) {
auto b = std::begin(a), e = std::end(a);
for (auto it = std::begin(a); it != e; ++it) {
if (it != b) os << sep;
os << *it;
}
return os << ends;
}
template <typename T, typename = void>
struct is_iterable : std::false_type {};
template <typename T>
struct is_iterable<T, std::void_t<decltype(std::begin(std::declval<T>())),
decltype(std::end(std::declval<T>()))>>
: std::true_type {};
template <typename T, typename = std::enable_if_t<
is_iterable<T>::value &&
!std::is_same<T, std::string_view>::value &&
!std::is_same<T, std::string>::value>>
std::ostream &operator<<(std::ostream &os, const T &a) {
return print_seq(a, ", ", "", (os << "{")) << "}";
}
#ifdef ENABLE_DEBUG
#include "debug_dump.hpp"
#else
#define DUMP(...)
#endif
using namespace std;
// Returns a vector that maps x to x's smallest prime factor (> 1).
// O(n log log n)
std::vector<int> sieve_smallest_prime_factors(int n) {
std::vector<int> res(n + 1);
for (int i = 1; i <= n; ++i) res[i] = i;
for (int i = 2; i <= n; i += 2) res[i] = 2;
for (int i = 3; i * i <= n; i += 2) {
if (res[i] != i) continue;
for (int j = i * i; j <= n; j += i) {
if (res[j] == j) res[j] = i;
}
}
return res;
}
// Quick factorization.
i64 quick_factorize(int n, const std::vector<int> &spf) {
// assert(0 < n and n < int(spf.size()));
// std::vector<std::pair<int, int>> res;
i64 b = 1;
for (;;) {
const int p = spf[n];
if (p == 1) break;
int count = 0;
do {
n /= p;
++count;
} while (n % p == 0);
if (count & 1) {
b *= p;
}
}
return b;
}
auto solve() {
i64 n;
cin >> n;
auto spf = sieve_smallest_prime_factors(n);
i64 ans = 0;
for (i64 x = 1; x <= n; ++x) {
i64 b = quick_factorize(x, spf);
i64 ub = n / b;
i64 tv = 1, fv = n + 1;
while (fv - tv > 1) {
i64 mid = (tv + fv) / 2;
if (mid * mid <= ub) {
tv = mid;
} else {
fv = mid;
}
}
ans += tv;
}
return ans;
}
int main() {
ios_base::sync_with_stdio(false), cin.tie(nullptr);
cout << solve() << "\n";
}
keijak