結果

問題 No.1513 simple 門松列 problem
ユーザー iiljjiiljj
提出日時 2021-05-21 22:46:28
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 334 ms / 3,000 ms
コード長 12,688 bytes
コンパイル時間 1,600 ms
コンパイル使用メモリ 147,916 KB
実行使用メモリ 131,968 KB
最終ジャッジ日時 2024-10-10 09:28:57
合計ジャッジ時間 3,851 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,820 KB
testcase_01 AC 2 ms
6,820 KB
testcase_02 AC 334 ms
131,968 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,816 KB
testcase_05 AC 2 ms
6,816 KB
testcase_06 AC 2 ms
6,816 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 2 ms
6,820 KB
testcase_09 AC 2 ms
6,820 KB
testcase_10 AC 2 ms
6,816 KB
testcase_11 AC 2 ms
6,820 KB
testcase_12 AC 2 ms
6,816 KB
testcase_13 AC 2 ms
6,816 KB
testcase_14 AC 296 ms
129,536 KB
testcase_15 AC 309 ms
130,048 KB
testcase_16 AC 333 ms
131,328 KB
testcase_17 AC 194 ms
83,712 KB
testcase_18 AC 72 ms
30,464 KB
testcase_19 AC 6 ms
6,820 KB
testcase_20 AC 32 ms
20,096 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

/* #region Head */

// #include <bits/stdc++.h>
#include <algorithm>
#include <array>
#include <bitset>
#include <cassert> // assert.h
#include <cmath>   // math.h
#include <cstring>
#include <ctime>
#include <deque>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <list>
#include <map>
#include <memory>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <vector>
using namespace std;

using ll = long long;
using ull = unsigned long long;
using ld = long double;
using pll = pair<ll, ll>;
template <class T> using vc = vector<T>;
template <class T> using vvc = vc<vc<T>>;
using vll = vc<ll>;
using vvll = vvc<ll>;
using vld = vc<ld>;
using vvld = vvc<ld>;
using vs = vc<string>;
using vvs = vvc<string>;
template <class T, class U> using um = unordered_map<T, U>;
template <class T> using pq = priority_queue<T>;
template <class T> using pqa = priority_queue<T, vc<T>, greater<T>>;
template <class T> using us = unordered_set<T>;

#define TREP(T, i, m, n) for (T i = (m), i##_len = (T)(n); i < i##_len; ++(i))
#define TREPM(T, i, m, n) for (T i = (m), i##_max = (T)(n); i <= i##_max; ++(i))
#define TREPR(T, i, m, n) for (T i = (m), i##_min = (T)(n); i >= i##_min; --(i))
#define TREPD(T, i, m, n, d) for (T i = (m), i##_len = (T)(n); i < i##_len; i += (d))
#define TREPMD(T, i, m, n, d) for (T i = (m), i##_max = (T)(n); i <= i##_max; i += (d))

#define REP(i, m, n) for (ll i = (m), i##_len = (ll)(n); i < i##_len; ++(i))
#define REPM(i, m, n) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; ++(i))
#define REPR(i, m, n) for (ll i = (m), i##_min = (ll)(n); i >= i##_min; --(i))
#define REPD(i, m, n, d) for (ll i = (m), i##_len = (ll)(n); i < i##_len; i += (d))
#define REPMD(i, m, n, d) for (ll i = (m), i##_max = (ll)(n); i <= i##_max; i += (d))
#define REPI(itr, ds) for (auto itr = ds.begin(); itr != ds.end(); itr++)
#define REPIR(itr, ds) for (auto itr = ds.rbegin(); itr != ds.rend(); itr++)
#define ALL(x) begin(x), end(x)
#define SIZE(x) ((ll)(x).size())
#define PERM(c)                                                                                                        \
    sort(ALL(c));                                                                                                      \
    for (bool c##p = 1; c##p; c##p = next_permutation(ALL(c)))
#define UNIQ(v) v.erase(unique(ALL(v)), v.end());
#define CEIL(a, b) (((a) + (b)-1) / (b))

#define endl '\n'

constexpr ll INF = 1'010'000'000'000'000'017LL;
constexpr int IINF = 1'000'000'007LL;
// constexpr ll MOD = 1'000'000'007LL; // 1e9 + 7
constexpr ll MOD = 998244353;
constexpr ld EPS = 1e-12;
constexpr ld PI = 3.14159265358979323846;

template <typename T> istream &operator>>(istream &is, vc<T> &vec) { // vector 入力
    for (T &x : vec) is >> x;
    return is;
}
template <typename T> ostream &operator<<(ostream &os, const vc<T> &vec) { // vector 出力 (for dump)
    os << "{";
    REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "" : ", ");
    os << "}";
    return os;
}
template <typename T> ostream &operator>>(ostream &os, const vc<T> &vec) { // vector 出力 (inline)
    REP(i, 0, SIZE(vec)) os << vec[i] << (i == i_len - 1 ? "\n" : " ");
    return os;
}

template <typename T, size_t _Nm> istream &operator>>(istream &is, array<T, _Nm> &arr) { // array 入力
    REP(i, 0, SIZE(arr)) is >> arr[i];
    return is;
}
template <typename T, size_t _Nm> ostream &operator<<(ostream &os, const array<T, _Nm> &arr) { // array 出力 (for dump)
    os << "{";
    REP(i, 0, SIZE(arr)) os << arr[i] << (i == i_len - 1 ? "" : ", ");
    os << "}";
    return os;
}

template <typename T, typename U> istream &operator>>(istream &is, pair<T, U> &pair_var) { // pair 入力
    is >> pair_var.first >> pair_var.second;
    return is;
}
template <typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &pair_var) { // pair 出力
    os << "(" << pair_var.first << ", " << pair_var.second << ")";
    return os;
}

// map, um, set, us 出力
template <class T> ostream &out_iter(ostream &os, const T &map_var) {
    os << "{";
    REPI(itr, map_var) {
        os << *itr;
        auto itrcp = itr;
        if (++itrcp != map_var.end()) os << ", ";
    }
    return os << "}";
}
template <typename T, typename U> ostream &operator<<(ostream &os, const map<T, U> &map_var) {
    return out_iter(os, map_var);
}
template <typename T, typename U> ostream &operator<<(ostream &os, const um<T, U> &map_var) {
    os << "{";
    REPI(itr, map_var) {
        auto [key, value] = *itr;
        os << "(" << key << ", " << value << ")";
        auto itrcp = itr;
        if (++itrcp != map_var.end()) os << ", ";
    }
    os << "}";
    return os;
}
template <typename T> ostream &operator<<(ostream &os, const set<T> &set_var) { return out_iter(os, set_var); }
template <typename T> ostream &operator<<(ostream &os, const us<T> &set_var) { return out_iter(os, set_var); }
template <typename T> ostream &operator<<(ostream &os, const pq<T> &pq_var) {
    pq<T> pq_cp(pq_var);
    os << "{";
    if (!pq_cp.empty()) {
        os << pq_cp.top(), pq_cp.pop();
        while (!pq_cp.empty()) os << ", " << pq_cp.top(), pq_cp.pop();
    }
    return os << "}";
}

void pprint() { cout << endl; }
template <class Head, class... Tail> void pprint(Head &&head, Tail &&...tail) {
    cout << head;
    if (sizeof...(Tail) > 0) cout << ' ';
    pprint(move(tail)...);
}

// dump
#define DUMPOUT cerr
void dump_func() { DUMPOUT << endl; }
template <class Head, class... Tail> void dump_func(Head &&head, Tail &&...tail) {
    DUMPOUT << head;
    if (sizeof...(Tail) > 0) DUMPOUT << ", ";
    dump_func(move(tail)...);
}

// chmax (更新「される」かもしれない値が前)
template <typename T, typename U, typename Comp = less<>> bool chmax(T &xmax, const U &x, Comp comp = {}) {
    if (comp(xmax, x)) {
        xmax = x;
        return true;
    }
    return false;
}

// chmin (更新「される」かもしれない値が前)
template <typename T, typename U, typename Comp = less<>> bool chmin(T &xmin, const U &x, Comp comp = {}) {
    if (comp(x, xmin)) {
        xmin = x;
        return true;
    }
    return false;
}

// ローカル用
#ifndef ONLINE_JUDGE
#define DEBUG_
#endif

#ifdef DEBUG_
#define DEB
#define dump(...)                                                                                                      \
    DUMPOUT << "  " << string(#__VA_ARGS__) << ": "                                                                    \
            << "[" << to_string(__LINE__) << ":" << __FUNCTION__ << "]" << endl                                        \
            << "    ",                                                                                                 \
        dump_func(__VA_ARGS__)
#else
#define DEB if (false)
#define dump(...)
#endif

#define VAR(type, ...)                                                                                                 \
    type __VA_ARGS__;                                                                                                  \
    cin >> __VA_ARGS__;

template <typename T> istream &operator,(istream &is, T &rhs) { return is >> rhs; }
template <typename T> ostream &operator,(ostream &os, const T &rhs) { return os << ' ' << rhs; }

struct AtCoderInitialize {
    static constexpr int IOS_PREC = 15;
    static constexpr bool AUTOFLUSH = false;
    AtCoderInitialize() {
        ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
        cout << fixed << setprecision(IOS_PREC);
        if (AUTOFLUSH) cout << unitbuf;
    }
} ATCODER_INITIALIZE;

void Yn(bool p) { cout << (p ? "Yes" : "No") << endl; }
void YN(bool p) { cout << (p ? "YES" : "NO") << endl; }

/* #endregion */

// #include <atcoder/all>
// using namespace atcoder;

/* #region mint */

// 自動で MOD を取る整数
struct mint {
    ll x;
    mint(ll x = 0) : x((x % MOD + MOD) % MOD) {}
    mint &operator+=(const mint a) {
        if ((x += a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint &operator-=(const mint a) {
        if ((x += MOD - a.x) >= MOD) x -= MOD;
        return *this;
    }
    mint &operator*=(const mint a) {
        (x *= a.x) %= MOD;
        return *this;
    }
    mint operator+(const mint a) const {
        mint res(*this);
        return res += a;
    }
    mint operator-(const mint a) const {
        mint res(*this);
        return res -= a;
    }
    mint operator*(const mint a) const {
        mint res(*this);
        return res *= a;
    }
    // O(log(t))
    mint pow_rec(ll t) const {
        if (!t) return 1;
        mint a = pow(t >> 1); // ⌊t/2⌋ 乗
        a *= a;               // ⌊t/2⌋*2 乗
        if (t & 1)            // ⌊t/2⌋*2 == t-1 のとき
            a *= *this;       // ⌊t/2⌋*2+1 乗 => t 乗
        return a;
    }

    mint pow(ll t) const {
        mint a(*this);
        mint res = 1;
        while (t) {
            if (t & 1) res *= a;
            t >>= 1, a *= a;
        }
        return res;
    }

    // for prime mod
    mint inv_prime() const {
        return pow(MOD - 2); // オイラーの定理から, x^(-1) ≡ x^(p-2)
    }
    mint inv() const {
        ll a = this->x, b = MOD, u = 1, v = 0, t;
        mint res;
        while (b) {
            t = a / b;
            a -= t * b;
            swap(a, b);
            u -= t * v;
            swap(u, v);
        }
        if (u < 0) u += MOD;
        res = u;
        return res;
    }
    mint &operator/=(const mint a) { return (*this) *= a.inv(); }
    mint operator/(const mint a) const {
        mint res(*this);
        return res /= a;
    }
    bool operator==(const mint a) const { return this->x == a.x; }
    bool operator==(const ll a) const { return this->x == a; }
    bool operator!=(const mint a) const { return this->x != a.x; }
    bool operator!=(const ll a) const { return this->x != a; }

    // mint 入力
    friend istream &operator>>(istream &is, mint &x) {
        is >> x.x;
        return is;
    }

    // mint 出力
    friend ostream &operator<<(ostream &os, const mint x) {
        os << x.x;
        return os;
    }
};

/* #endregion */

// Problem
void solve() {
    VAR(ll, n, k); //

    // dp[i][j][h] := i 番目まで見て,最後の 2 つの要素が j->h の順になるような場合の数
    vc<vc<vc<mint>>> dp(n, vc<vc<mint>>(k, vc<mint>(k, 0)));
    vc<vc<vc<mint>>> dp2(n, vc<vc<mint>>(k, vc<mint>(k, 0)));
    REP(j, 0, k) REP(h, 0, k) if (j != h) {
        dp[1][j][h] = 1;
        dp2[1][j][h] = j + h;
    }
    // dump(dp2[1]);
    REP(i, 2, n) {
        vc<vc<mint>> cum(k + 1, vc<mint>(k, 0));
        vc<vc<mint>> cum2(k + 1, vc<mint>(k, 0));
        REP(j, 0, k) REP(jp, 0, k) {
            cum[jp + 1][j] += cum[jp][j] + dp[i - 1][jp][j];    //
            cum2[jp + 1][j] += cum2[jp][j] + dp2[i - 1][jp][j]; //
        }
        const auto sumcum = [&cum](const int l, const int r, const int j) -> mint {
            return cum[r][j] - cum[l][j]; // 半開区間
        };
        const auto sumcum2 = [&cum2](const int l, const int r, const int j) -> mint {
            return cum2[r][j] - cum2[l][j]; // 半開区間
        };
        TREP(int, j, 0, k) TREP(int, h, 0, k) {
            if (j > h) {
                // 今回は下るので,前回は登っている必要がある
                // dp[i][j][h] = sum dp[i-1][0<=j'<j][j] s.t. h != j'
                //             = (sum dp[i-1][0<=j'<j][j]) - dp[i-1][h][j]
                // dp2[i][j][h] = (sum dp2[i-1][0<=j'<j][j] - dp2[i-1][h][j]) + (dp[i][j][h] * h)
                dp[i][j][h] = sumcum(0, j, j) - dp[i - 1][h][j];
                dp2[i][j][h] = (sumcum2(0, j, j) - dp2[i - 1][h][j]) + (dp[i][j][h] * h);
            } else if (j < h) {
                // 今回は登るので,前回は下っている必要がある
                // dp[i][j][h] = sum dp[i-1][j<j'<k][j] s.t. h != j'
                //             = (sum dp[i-1][j<j'<k][j]) - dp[i-1][h][j]
                // dp2[i][j][h] = (sum dp2[i-1][j<j'<k][j] - dp2[i-1][h][j]) + (dp[i][j][h] * h)
                dp[i][j][h] = sumcum(j + 1, k, j) - dp[i - 1][h][j];
                dp2[i][j][h] = (sumcum2(j + 1, k, j) - dp2[i - 1][h][j]) + (dp[i][j][h] * h);
            }
        }
        // dump(dp2[i]);
    }
    mint ans1 = 0;
    mint ans2 = 0;
    REP(j, 0, k) REP(h, 0, k) {
        ans1 += dp[n - 1][j][h];
        ans2 += dp2[n - 1][j][h];
    }
    pprint(ans1, ans2);
}

// entry point
int main() {
    solve();
    return 0;
}
0