結果

問題 No.1513 simple 門松列 problem
コンテスト
ユーザー tamato
提出日時 2021-05-21 23:11:36
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 553 ms / 3,000 ms
コード長 2,790 bytes
記録
記録タグの例:
初AC ショートコード 純ショートコード 純主流ショートコード 最速実行時間
コンパイル時間 266 ms
コンパイル使用メモリ 82,492 KB
実行使用メモリ 326,956 KB
最終ジャッジ日時 2024-10-10 10:05:59
合計ジャッジ時間 4,577 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge1
このコードへのチャレンジ
（要ログイン）
ファイルパターン 結果
sample AC * 3
other AC * 18
権限があれば一括ダウンロードができます

ソースコード

diff #
raw source code 

mod = 998244353
eps = 10**-9


def main():
    import sys
    input = sys.stdin.readline

    N, K = map(int, input().split())

    dp1 = [[0] * (K*K) for _ in range(N)]
    dp2 = [[0] * (K*K) for _ in range(N)]
    for k1 in range(K):
        for k2 in range(k1):
            dp1[1][k1*K+k2] = 1
            dp2[1][k1*K+k2] = k1+k2
    for i in range(2, N):
        if not i&1:
            for k2 in range(K):
                S1 = 0
                S2 = 0
                for k1 in range(K-1, k2, -1):
                    S1 = (S1 + dp1[i-1][k1*K+k2])%mod
                    S2 = (S2 + dp2[i-1][k1*K+k2])%mod
                for k3 in range(k2+1, K):
                    dp1[i][k2*K+k3] = (S1 - dp1[i-1][k3*K+k2])%mod
                    dp2[i][k2*K+k3] = ((S2 - dp2[i-1][k3*K+k2])%mod + (k3 * dp1[i][k2*K+k3])%mod)%mod
        else:
            for k2 in range(K):
                S1 = 0
                S2 = 0
                for k1 in range(k2):
                    S1 = (S1 + dp1[i-1][k1*K+k2])%mod
                    S2 = (S2 + dp2[i-1][k1*K+k2])%mod
                for k3 in range(k2):
                    dp1[i][k2*K+k3] = (S1 - dp1[i-1][k3*K+k2])%mod
                    dp2[i][k2*K+k3] = ((S2 - dp2[i-1][k3*K+k2])%mod + (k3 * dp1[i][k2*K+k3])%mod)%mod
    ans1 = ans2 = 0
    for k1 in range(K):
        for k2 in range(K):
            ans1 = (ans1 + dp1[-1][k1*K+k2])%mod
            ans2 = (ans2 + dp2[-1][k1*K+k2])%mod


    dp1 = [[0] * (K*K) for _ in range(N)]
    dp2 = [[0] * (K*K) for _ in range(N)]
    for k1 in range(K):
        for k2 in range(k1 + 1, K):
            dp1[1][k1*K+k2] = 1
            dp2[1][k1*K+k2] = k1+k2
    for i in range(2, N):
        if i&1:
            for k2 in range(K):
                S1 = 0
                S2 = 0
                for k1 in range(K-1, k2, -1):
                    S1 = (S1 + dp1[i-1][k1*K+k2])%mod
                    S2 = (S2 + dp2[i-1][k1*K+k2])%mod
                for k3 in range(k2+1, K):
                    dp1[i][k2*K+k3] = (S1 - dp1[i-1][k3*K+k2])%mod
                    dp2[i][k2*K+k3] = ((S2 - dp2[i-1][k3*K+k2])%mod + (k3 * dp1[i][k2*K+k3])%mod)%mod
        else:
            for k2 in range(K):
                S1 = 0
                S2 = 0
                for k1 in range(k2):
                    S1 = (S1 + dp1[i-1][k1*K+k2])%mod
                    S2 = (S2 + dp2[i-1][k1*K+k2])%mod
                for k3 in range(k2):
                    dp1[i][k2*K+k3] = (S1 - dp1[i-1][k3*K+k2])%mod
                    dp2[i][k2*K+k3] = ((S2 - dp2[i-1][k3*K+k2])%mod + (k3 * dp1[i][k2*K+k3])%mod)%mod
    for k1 in range(K):
        for k2 in range(K):
            ans1 = (ans1 + dp1[-1][k1*K+k2])%mod
            ans2 = (ans2 + dp2[-1][k1*K+k2])%mod

    print(ans1, ans2)


if __name__ == '__main__':
    main()
0