結果
問題 | No.1516 simple 門松列 problem Re:MASTER |
ユーザー | fuppy_kyopro |
提出日時 | 2021-05-21 23:42:37 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 244 ms / 6,000 ms |
コード長 | 6,297 bytes |
コンパイル時間 | 2,940 ms |
コンパイル使用メモリ | 235,472 KB |
実行使用メモリ | 13,056 KB |
最終ジャッジ日時 | 2024-10-10 10:18:11 |
合計ジャッジ時間 | 4,819 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,820 KB |
testcase_01 | AC | 5 ms
6,816 KB |
testcase_02 | AC | 137 ms
8,832 KB |
testcase_03 | AC | 2 ms
6,820 KB |
testcase_04 | AC | 2 ms
6,820 KB |
testcase_05 | AC | 2 ms
6,820 KB |
testcase_06 | AC | 5 ms
6,816 KB |
testcase_07 | AC | 19 ms
6,816 KB |
testcase_08 | AC | 29 ms
6,820 KB |
testcase_09 | AC | 2 ms
6,820 KB |
testcase_10 | AC | 3 ms
6,816 KB |
testcase_11 | AC | 2 ms
6,816 KB |
testcase_12 | AC | 2 ms
6,816 KB |
testcase_13 | AC | 2 ms
6,820 KB |
testcase_14 | AC | 244 ms
13,056 KB |
testcase_15 | AC | 112 ms
10,240 KB |
testcase_16 | AC | 48 ms
7,168 KB |
testcase_17 | AC | 19 ms
6,816 KB |
testcase_18 | AC | 7 ms
6,820 KB |
testcase_19 | AC | 4 ms
6,820 KB |
testcase_20 | AC | 237 ms
12,928 KB |
testcase_21 | AC | 233 ms
12,928 KB |
ソースコード
/* #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") //*/ #include <bits/stdc++.h> // #include <atcoder/all> using namespace std; // using namespace atcoder; #define DEBUG(x) cerr << #x << ": " << x << endl; #define DEBUG_VEC(v) \ cerr << #v << ":"; \ for (int iiiiiiii = 0; iiiiiiii < v.size(); iiiiiiii++) \ cerr << " " << v[iiiiiiii]; \ cerr << endl; #define DEBUG_MAT(v) \ cerr << #v << endl; \ for (int i = 0; i < v.size(); i++) { \ for (int j = 0; j < v[i].size(); j++) { \ cerr << v[i][j] << " "; \ } \ cerr << endl; \ } typedef long long ll; // #define int ll #define vi vector<int> #define vl vector<ll> #define vii vector<vector<int>> #define vll vector<vector<ll>> #define vs vector<string> #define pii pair<int, int> #define pis pair<int, string> #define psi pair<string, int> #define pll pair<ll, ll> template <class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first + t.first, s.second + t.second); } template <class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t) { return pair<S, T>(s.first - t.first, s.second - t.second); } template <class S, class T> ostream &operator<<(ostream &os, pair<S, T> p) { os << "(" << p.first << ", " << p.second << ")"; return os; } #define X first #define Y second #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define rep1(i, n) for (int i = 1; i <= (int)(n); i++) #define rrep(i, n) for (int i = (int)(n)-1; i >= 0; i--) #define rrep1(i, n) for (int i = (int)(n); i > 0; i--) #define REP(i, a, b) for (int i = a; i < b; i++) #define in(x, a, b) (a <= x && x < b) #define all(c) c.begin(), c.end() void YES(bool t = true) { cout << (t ? "YES" : "NO") << endl; } void Yes(bool t = true) { cout << (t ? "Yes" : "No") << endl; } void yes(bool t = true) { cout << (t ? "yes" : "no") << endl; } void NO(bool t = true) { cout << (t ? "NO" : "YES") << endl; } void No(bool t = true) { cout << (t ? "No" : "Yes") << endl; } void no(bool t = true) { cout << (t ? "no" : "yes") << endl; } template <class T> bool chmax(T &a, const T &b) { if (a < b) { a = b; return 1; } return 0; } template <class T> bool chmin(T &a, const T &b) { if (a > b) { a = b; return 1; } return 0; } #define UNIQUE(v) v.erase(std::unique(v.begin(), v.end()), v.end()); const ll inf = 1000000001; const ll INF = (ll)1e18 + 1; const long double pi = 3.1415926535897932384626433832795028841971L; int popcount(ll t) { return __builtin_popcountll(t); } // int dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1}; // int dx2[8] = { 1,1,0,-1,-1,-1,0,1 }, dy2[8] = { 0,1,1,1,0,-1,-1,-1 }; vi dx = {0, 1, 0, -1}, dy = {-1, 0, 1, 0}; // vi dx2 = { 1,1,0,-1,-1,-1,0,1 }, dy2 = { 0,1,1,1,0,-1,-1,-1 }; struct Setup_io { Setup_io() { ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0); cout << fixed << setprecision(25); } } setup_io; // const ll MOD = 1000000007; const ll MOD = 998244353; // #define mp make_pair //#define endl '\n' using vlll = vector<vll>; using vllll = vector<vlll>; using P = pair<vllll, vllll>; unordered_map<int, P> memo; ll k; P solve(int n) { if (memo.count(n)) return memo[n]; DEBUG(n); int l = n / 2; int r = n - l; auto dp1 = solve(l + 1); auto dp2 = solve(r + 1); memo[n].first = vllll(k, vlll(k, vll(k, vl(k)))); memo[n].second = vllll(k, vlll(k, vll(k, vl(k)))); rep(u1, k) rep(v1, k) rep(w1, k) rep(x1, k) { if (dp1.first[u1][v1][w1][x1] == 0 && dp1.second[u1][v1][w1][x1] == 0) continue; rep(w2, k) rep(x2, k) { int u2 = w1, v2 = x1; if (dp2.first[u2][v2][w2][x2] == 0 && dp2.second[u2][v2][w2][x2] == 0) continue; // if (x1 == u2) continue; // if (w1 == u2) continue; // if (x1 == v2) continue; // { // int mi = min({w1, x1, u2}), ma = max({w1, x1, u2}); // if (mi != x1 && ma != x1) continue; // } // { // int mi = min({x1, u2, v2}), ma = max({x1, u2, v2}); // if (mi != u2 && ma != u2) continue; // } (memo[n].first[u1][v1][w2][x2] += dp1.first[u1][v1][w1][x1] * dp2.first[u2][v2][w2][x2]) %= MOD; (memo[n].second[u1][v1][w2][x2] += dp1.first[u1][v1][w1][x1] * dp2.second[u2][v2][w2][x2] + dp1.second[u1][v1][w1][x1] * dp2.first[u2][v2][w2][x2] - (w1 + x1) * dp1.first[u1][v1][w1][x1] % MOD * dp2.first[u2][v2][w2][x2]) %= MOD; } } return memo[n]; } void dfs(vi &state, int n) { if (state.size() >= 3) { int u = state[0], v = state[1], w = state[state.size() - 2], x = state[state.size() - 1]; int sum = 0; rep(i, state.size()) sum += state[i]; memo[state.size()].first[u][v][w][x]++; (memo[state.size()].second[u][v][w][x] += sum) %= MOD; } if (state.size() == min(n, 8)) { return; } rep(x, k) { if (state.size() > 0 && state.back() == x) continue; if (state.size() > 1 && state[state.size() - 2] == x) continue; if (state.size() > 1) { int u = state[state.size() - 2], v = state[state.size() - 1]; int mi = min({u, v, x}), ma = max({u, v, x}); if (mi != v && ma != v) continue; } state.push_back(x); dfs(state, n); state.pop_back(); } } signed main() { int n; cin >> n >> k; for (int x = 3; x <= 8; x++) { memo[x].first = vllll(k, vlll(k, vll(k, vl(k)))); memo[x].second = vllll(k, vlll(k, vll(k, vl(k)))); } vi state; dfs(state, n); P ans = solve(n); ll ans1 = 0, ans2 = 0; rep(i, k) rep(j, k) rep(l, k) rep(m, k) { ans1 += ans.first[i][j][l][m]; ans2 += ans.second[i][j][l][m]; } cout << (ans1 % MOD + MOD) % MOD << " " << (ans2 % MOD + MOD) % MOD << endl; }