結果
| 問題 |
No.1612 I hate Construct a Palindrome
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2021-05-22 23:59:18 |
| 言語 | C (gcc 13.3.0) |
| 結果 |
AC
|
| 実行時間 | 69 ms / 2,000 ms |
| コード長 | 2,694 bytes |
| コンパイル時間 | 348 ms |
| コンパイル使用メモリ | 32,896 KB |
| 実行使用メモリ | 10,228 KB |
| 最終ジャッジ日時 | 2024-07-17 15:08:29 |
| 合計ジャッジ時間 | 4,275 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 36 |
ソースコード
#include <stdio.h>
typedef struct List {
struct List *next;
int v, id;
} list;
int is_palindrome(char S[])
{
int i, j;
for (j = 0; S[j] != 0; j++);
for (i = 0, j--; i < j; i++, j--) if (S[i] != S[j]) break;
if (i < j) return 0;
else return 1;
}
int is_unique(char S[])
{
int i;
for (i = 1; S[i] != 0; i++) if (S[i] != S[0]) break;
if (S[i] != 0) return 0;
else return 1;
}
int solve(int N, int M, list* adj[], char c[], int ans[])
{
int i, j, k, u, w, par[2][100001] = {}, q[100001], head, tail;
list *p;
for (i = 2; i <= M; i++) if (c[i] != c[1]) break;
if (i > M) return -1;
par[0][N] = -N;
q[0] = N;
for (head = 0, tail = 1; head < tail; head++) {
u = q[head];
for (p = adj[u]; p != NULL; p = p->next) {
w = p->v;
if (par[0][w] == 0) {
par[0][w] = u;
par[1][w] = p->id;
q[tail++] = w;
}
}
}
if (par[0][1] == 0) return -1;
char S[200001], T[200001];
for (u = 1, k = 0; u != N; u = -par[0][u], k++) {
S[k] = c[par[1][u]];
ans[k] = par[1][u];
q[k] = u;
par[0][u] *= -1;
}
S[k] = 0;
if (is_palindrome(S) == 0) return k;
else if (is_unique(S) == 0) {
ans[k] = ans[k-1];
ans[k+1] = ans[k];
return k + 2;
}
q[k++] = N;
for (u = 1; u < N; u++) if (par[0][u] > 0) par[0][u] = 0;
for (head = 0, tail = k; head < tail; head++) {
u = q[head];
for (p = adj[u]; p != NULL; p = p->next) {
w = p->v;
if (c[p->id] != S[0]) break;
else if (par[0][w] == 0) {
par[0][w] = u;
par[1][w] = p->id;
q[tail++] = w;
}
}
if (p != NULL) break;
}
if (head == tail) return -1;
int tmp[200001];
T[0] = c[p->id];
tmp[0] = p->id;
for (j = 1; par[0][u] > 0; u = par[0][u], j++) {
T[j] = c[par[1][u]];
tmp[j] = par[1][u];
}
for (w = u, u = 1, k = 0; u != w; u = -par[0][u], k++) {
S[k] = c[par[1][u]];
ans[k] = par[1][u];
}
for (i = j - 1; i >= 0; i--, k++) {
S[k] = T[i];
ans[k] = tmp[i];
}
for (i = 0; i < j; i++, k++) {
S[k] = T[i];
ans[k] = tmp[i];
}
for (; u != N; u = -par[0][u], k++) {
S[k] = c[par[1][u]];
ans[k] = par[1][u];
}
S[k] = 0;
if (is_palindrome(S) == 0) return k;
else {
ans[k] = ans[k-1];
ans[k+1] = ans[k];
return k + 2;
}
}
int main()
{
int i, N, M, u, w;
char c[200001];
list *adj[100001] = {}, e[400001];
scanf("%d %d", &N, &M);
for (i = 0; i < M; i++) {
scanf("%d %d %c ", &u, &w, &(c[i+1]));
e[i*2].v = w;
e[i*2+1].v = u;
e[i*2].id = i + 1;
e[i*2+1].id = i + 1;
e[i*2].next = adj[u];
e[i*2+1].next = adj[w];
adj[u] = &(e[i*2]);
adj[w] = &(e[i*2+1]);
}
int ans[200001], k = solve(N, M, adj, c, ans);
printf("%d\n", k);
if (k >= 0) for (i = 0; i < k; i++) printf("%d\n", ans[i]);
fflush(stdout);
return 0;
}