結果

問題 No.1615 Double Down
ユーザー 👑 ygussany
提出日時 2021-05-23 01:02:19
言語 C
(gcc 13.3.0)
結果
WA  
実行時間 -
コード長 8,037 bytes
コンパイル時間 457 ms
コンパイル使用メモリ 36,012 KB
実行使用メモリ 10,348 KB
最終ジャッジ日時 2024-07-17 15:10:23
合計ジャッジ時間 39,687 ms
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 24 WA * 30
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ソースコード

diff #
プレゼンテーションモードにする

#include <stdio.h>
#include <stdlib.h>
typedef struct {
long long key;
int id;
} data;
typedef struct {
data *obj;
int size;
} min_heap;
void push(data x, min_heap* h)
{
int i = ++(h->size), j = i >> 1;
data tmp;
h->obj[i] = x;
while (j > 0) {
if (h->obj[i].key < h->obj[j].key) {
tmp = h->obj[j];
h->obj[j] = h->obj[i];
h->obj[i] = tmp;
i = j;
j >>= 1;
} else break;
}
}
data pop(min_heap* h)
{
int i = 1, j = 2;
data output = h->obj[1], tmp;
h->obj[1] = h->obj[(h->size)--];
while (j <= h->size) {
if (j < h->size && h->obj[j^1].key < h->obj[j].key) j ^= 1;
if (h->obj[j].key < h->obj[i].key) {
tmp = h->obj[j];
h->obj[j] = h->obj[i];
h->obj[i] = tmp;
i = j;
j <<= 1;
} else break;
}
return output;
}
typedef struct {
int id, head, tail, flow, cap, cost;
} edge;
typedef struct List {
struct List *next;
edge *e;
} list;
const int sup_int = 1 << 30;
const long long sup = 1LL << 60, inf = -(1LL << 60);
void chmin(int* a, int b)
{
if (*a > b) *a = b;
}
int DFS(list *aux[], edge f[], int par[], int u)
{
int i, w, c, argmin;
for (; aux[u] != NULL; aux[u] = aux[u]->next) {
if (aux[u]->e->flow == aux[u]->e->cap) continue;
w = aux[u]->e->head;
if (par[w] == -3) {
for (i = aux[u]->e->id, c = sup_int; par[w] != -2; i = par[w]) {
chmin(&c, f[i].cap - f[i].flow);
w = f[i].tail;
if (f[i].cap - f[i].flow == c) argmin = w;
}
for (i = aux[u]->e->id, w = aux[u]->e->head; par[w] != -2; i = par[w]) {
f[i].flow += c;
w = f[i].tail;
}
if (argmin != u) {
par[u] = -1;
return argmin;
}
} else if (par[w] == -1) {
par[w] = aux[u]->e->id;
w = DFS(aux, f, par, w);
if (w > 0 && w != u) {
par[u] = -1;
return w;
}
}
}
return 0;
}
int Dinic(int N, int M, list* adj[], edge e[], int s, int t)
{
int i, u, w, ans = 0, add, *par = (int*)malloc(sizeof(int) * (N + 1)), *dist = (int*)malloc(sizeof(int) * (N + 1)), *q = (int*)malloc(sizeof(int)
        * (N + 1)), head, tail;
list **aux = (list**)malloc(sizeof(list*) * (N + 1)), *df = (list*)malloc(sizeof(list) * (M + 1)), *p;
edge *f = (edge*)malloc(sizeof(edge) * (M + 1));
for (i = 0; i < M; i++) f[i].flow = 0;
do {
for (u = 1; u <= N; u++) {
dist[u] = -1;
aux[u] = NULL;
}
dist[s] = 0;
q[0] = s;
for (head = 0, tail = 1; head < tail; head++) {
u = q[head];
for (p = adj[u]; p != NULL; p = p->next) {
if (p->e->flow == p->e->cap) continue;
w = p->e->head;
if (dist[w] == -1) {
dist[w] = dist[u] + 1;
q[tail++] = w;
}
if (dist[w] == dist[u] + 1) {
i = p->e->id;
f[i].id = i;
f[i].tail = u;
f[i].head = w;
f[i].flow = 0;
f[i].cap = p->e->cap - p->e->flow;
df[i].e = &(f[i]);
df[i].next = aux[u];
aux[u] = &(df[i]);
}
}
}
for (u = 1; u <= N; u++) par[u] = -1;
par[s] = -2;
par[t] = -3;
DFS(aux, f, par, s);
for (i = 0, add = 0; i < M; i++) {
if (e[i].flow == e[i].cap || dist[e[i].head] != dist[e[i].tail] + 1 || f[i].flow == 0) continue;
if (f[i].tail == s) add += f[i].flow;
if (e[i^1].flow > 0) {
e[i^1].flow -= f[i].flow;
e[i].cap -= f[i].flow;
} else {
e[i].flow += f[i].flow;
e[i^1].cap += f[i].flow;
}
}
ans += add;
} while (add != 0);
free(par);
free(dist);
free(q);
free(aux);
free(df);
free(f);
return ans;
}
long long succesive_shortest_path(int N, int M, list* adj[], edge e[], int b[])
{
int i, j, k, u, w, *flag = (int*)malloc(sizeof(int) * (N + 1)), *def = (int*)malloc(sizeof(int) * (N + 1));
long long ans = 0, tmp = 0, *dist = (long long*)malloc(sizeof(long long) * (N + 1)), *pi = (long long*)malloc(sizeof(long long) * (N + 1));
edge **prev = (edge**)malloc(sizeof(edge*) * (N + 1));
list *p;
data d;
min_heap h_def, h_dist;
h_def.size = 0;
h_def.obj = (data*)malloc(sizeof(data) * (N + 1));
h_dist.obj = (data*)malloc(sizeof(data) * (M * 2 + 1));
for (i = 1; i <= N; i++) pi[i] = sup;
for (i = 1; i <= N; i++) {
for (p = adj[i], def[i] = b[i]; p != NULL; p = p->next) def[i] += p->e->flow - e[(p->e->id)^1].flow;
if (def[i] < 0) {
d.key = def[i];
d.id = i;
push(d, &h_def);
if (pi[i] == sup) {
pi[i] = 0;
for (j = 1; j <= N; j++) {
for (k = 0, flag[0] = 0; k < M; k++) {
if (e[k].flow == e[k].cap) continue;
u = e[k].tail;
w = e[k].head;
if (pi[u] != sup && pi[w] > pi[u] + e[k].cost) {
flag[0] = 1;
pi[w] = pi[u] + e[k].cost;
}
}
if (flag[0] == 0) break;
}
if (j > N) return inf;
}
}
}
int s, t, min;
while (h_def.size > 0) {
d = pop(&h_def);
s = d.id;
for (u = 1; u <= N; u++) {
flag[u] = 0;
dist[u] = sup;
prev[u] = NULL;
}
dist[s] = 0;
h_dist.size = 0;
d.key = 0;
d.id = s;
push(d, &h_dist);
while (h_dist.size > 0) {
d = pop(&h_dist);
u = d.id;
if (flag[u] != 0) continue;
else flag[u] = 1;
for (p = adj[u]; p != NULL; p = p->next) {
w = p->e->head;
if (p->e->flow == p->e->cap) continue;
else if (dist[w] > dist[u] + p->e->cost + pi[u] - pi[w]) {
dist[w] = dist[u] + p->e->cost + pi[u] - pi[w];
prev[w] = p->e;
d.key = dist[w];
d.id = w;
push(d, &h_dist);
}
}
}
for (t = 1; t <= N; t++) if (dist[t] != sup && def[t] > 0) break;
if (t > N) return sup;
for (u = t, min = (-def[s] < def[t])? -def[s]: def[t]; prev[u] != NULL; u = prev[u]->tail) {
if (min > prev[u]->cap - prev[u]->flow) min = prev[u]->cap - prev[u]->flow;
}
for (u = t; prev[u] != NULL; u = prev[u]->tail) {
i = prev[u]->id;
if (e[i^1].flow > 0) {
e[i^1].flow -= min;
e[i].cap -= min;
} else {
e[i].flow += min;
e[i^1].cap += min;
}
tmp += (long long)e[i].cost * min;
}
if (ans > tmp) ans = tmp;
for (i = 1; i <= N; i++) if (dist[i] != sup) pi[i] += dist[i];
def[s] += min;
def[t] -= min;
if (def[s] < 0) {
d.key = def[s];
d.id = s;
push(d, &h_def);
}
}
free(flag);
free(dist);
free(def);
free(pi);
free(prev);
free(h_def.obj);
free(h_dist.obj);
return ans;
}
long long solve_by_MCF(int N, int M, int K, int L, int X[], int Y[], int Z[])
{
int i, k = 0, u, w, s = N + M + 1, t = N + M + 2, bit[31];
list *adj[10003] = {}, d[220001], *p;
edge e[220001];
for (i = 1, bit[0] = 1; i <= K; i++) bit[i] = bit[i-1] << 1;
for (i = 1; i <= L; i++) {
u = X[i];
w = Y[i] + N;
e[k].id = k;
e[k].tail = u;
e[k].head = w;
e[k].flow = 0;
e[k].cap = 1;
e[k].cost = -bit[Z[i]];
d[k].e = &(e[k]);
d[k].next = adj[u];
adj[u] = &(d[k++]);
e[k].id = k;
e[k].tail = w;
e[k].head = u;
e[k].flow = 0;
e[k].cap = 0;
e[k].cost = bit[Z[i]];
d[k].e = &(e[k]);
d[k].next = adj[w];
adj[w] = &(d[k++]);
}
for (i = 1; i <= N; i++) {
u = s;
w = i;
e[k].id = k;
e[k].tail = u;
e[k].head = w;
e[k].flow = 0;
e[k].cap = 1;
e[k].cost = 0;
d[k].e = &(e[k]);
d[k].next = adj[u];
adj[u] = &(d[k++]);
e[k].id = k;
e[k].tail = w;
e[k].head = u;
e[k].flow = 0;
e[k].cap = 0;
e[k].cost = 0;
d[k].e = &(e[k]);
d[k].next = adj[w];
adj[w] = &(d[k++]);
}
for (i = 1; i <= M; i++) {
u = i + N;
w = t;
e[k].id = k;
e[k].tail = u;
e[k].head = w;
e[k].flow = 0;
e[k].cap = 1;
e[k].cost = 0;
d[k].e = &(e[k]);
d[k].next = adj[u];
adj[u] = &(d[k++]);
e[k].id = k;
e[k].tail = w;
e[k].head = u;
e[k].flow = 0;
e[k].cap = 0;
e[k].cost = 0;
d[k].e = &(e[k]);
d[k].next = adj[w];
adj[w] = &(d[k++]);
}
int b[10003] = {};
b[t] = Dinic(t, k, adj, e, s, t);
b[s] = -b[t];
for (i = 0; i < k; i += 2) {
e[i].flow = 0;
e[i].cap = 1;
e[i^1].flow = 0;
e[i^1].cap = 0;
}
return -succesive_shortest_path(t, k, adj, e, b);
}
int main()
{
int i, j, N, M, K, L, r, X[100001], Y[100001], Z[100001];
scanf("%d %d %d %d", &N, &M, &K, &L);
if (N + M >= 10000) return 0;
for (i = 1; i <= L; i++) scanf("%d %d %d", &(X[i]), &(Y[i]), &(Z[i]));
printf("%lld\n", solve_by_MCF(N, M, K, L, X, Y, Z));
fflush(stdout);
return 0;
}
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