結果

問題 No.1522 Unfairness
ユーザー leaf_1415leaf_1415
提出日時 2021-05-28 20:53:01
言語 C++11
(gcc 11.4.0)
結果
AC  
実行時間 47 ms / 2,000 ms
コード長 7,183 bytes
コンパイル時間 833 ms
コンパイル使用メモリ 89,556 KB
実行使用メモリ 73,896 KB
最終ジャッジ日時 2024-11-19 06:08:50
合計ジャッジ時間 2,201 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
6,820 KB
testcase_01 AC 1 ms
6,816 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 13 ms
26,092 KB
testcase_04 AC 6 ms
20,272 KB
testcase_05 AC 6 ms
21,668 KB
testcase_06 AC 11 ms
26,156 KB
testcase_07 AC 17 ms
31,188 KB
testcase_08 AC 24 ms
46,508 KB
testcase_09 AC 7 ms
21,432 KB
testcase_10 AC 13 ms
29,780 KB
testcase_11 AC 6 ms
18,304 KB
testcase_12 AC 9 ms
20,220 KB
testcase_13 AC 23 ms
48,708 KB
testcase_14 AC 4 ms
10,684 KB
testcase_15 AC 46 ms
73,896 KB
testcase_16 AC 47 ms
73,864 KB
testcase_17 AC 46 ms
73,824 KB
testcase_18 AC 47 ms
73,860 KB
testcase_19 AC 47 ms
73,892 KB
testcase_20 AC 46 ms
73,836 KB
testcase_21 AC 1 ms
6,820 KB
testcase_22 AC 1 ms
6,820 KB
testcase_23 AC 2 ms
6,816 KB
testcase_24 AC 2 ms
6,820 KB
testcase_25 AC 1 ms
6,820 KB
testcase_26 AC 2 ms
6,816 KB
testcase_27 AC 2 ms
6,816 KB
testcase_28 AC 1 ms
6,816 KB
testcase_29 AC 2 ms
6,820 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <iostream>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#define rep(x, s, t) for(llint (x) = (s); (x) <= (t); (x)++)
#define per(x, s, t) for(llint (x) = (s); (x) >= (t); (x)--)
#define reps(x, s) for(llint (x) = 0; (x) < (llint)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define ceil(x, y) (((x)+(y)-1) / (y))
#define all(x) (x).begin(),(x).end()
#define outl(...) dump_func(__VA_ARGS__)
#define inf 1e18

using namespace std;

typedef long long llint;
typedef long long ll;
typedef pair<ll, ll> P;

struct edge{
	ll to, cost;
	edge(){}
	edge(ll a, ll b){ to = a, cost = b;}
};
const ll dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};

const ll mod = 1000000007;
//const ll mod = 998244353;

struct mint{
	ll x = 0;
	mint(ll y = 0){x = y; if(x < 0 || x >= mod) x = (x%mod+mod)%mod;}
	mint(const mint &ope) {x = ope.x;}
	
	mint operator-(){return mint(-x);}
	mint operator+(const mint &ope){return mint(x) += ope;}
	mint operator-(const mint &ope){return mint(x) -= ope;}
	mint operator*(const mint &ope){return mint(x) *= ope;}
	mint operator/(const mint &ope){return mint(x) /= ope;}
	mint& operator+=(const mint &ope){
		x += ope.x;
		if(x >= mod) x -= mod;
		return *this;
	}
	mint& operator-=(const mint &ope){
		x += mod - ope.x;
		if(x >= mod) x -= mod;
		return *this;
	}
	mint& operator*=(const mint &ope){
		x *= ope.x, x %= mod;
		return *this;
	}
	mint& operator/=(const mint &ope){
		ll n = mod-2; mint mul = ope;
		while(n){
			if(n & 1) *this *= mul;
			mul *= mul;
			n >>= 1;
		}
		return *this;
	}
	mint inverse(){return mint(1) / *this;}
	bool operator ==(const mint &ope){return x == ope.x;}
	bool operator !=(const mint &ope){return x != ope.x;}
};
mint modpow(mint a, ll n){
	if(n == 0) return mint(1);
	if(n % 2) return a * modpow(a, n-1);
	else return modpow(a*a, n/2);
}
istream& operator >>(istream &is, mint &ope){
	ll t; is >> t, ope.x = t;
	return is;
}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}

bool exceed(ll x, ll y, ll m){return x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "YES" << endl; }
void no(){ cout << "NO" << endl; }
ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;}
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll lcm(ll a, ll b){return a/gcd(a, b)*b;}
ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;}
ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;}
string lltos(ll x){string ret; for(;x;x/=10) ret += x % 10 + '0'; reverse(ret.begin(), ret.end()); return ret;}
ll stoll(string &s){ll ret = 0; for(auto c : s) ret *= 10, ret += c - '0'; return ret;}
template<typename T>
void uniq(T &vec){ sort(vec.begin(), vec.end()); vec.erase(unique(vec.begin(), vec.end()), vec.end());}

template<typename T>
ostream& operator << (ostream& os, vector<T>& vec) {
	for(int i = 0; i < vec.size(); i++) os << vec[i] << (i + 1 == vec.size() ? "" : " ");
	return os;
}
template<typename T>
ostream& operator << (ostream& os, deque<T>& deq) {
	for(int i = 0; i < deq.size(); i++) os << deq[i] << (i + 1 == deq.size() ? "" : " ");
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, pair<T, U>& pair_var) {
	os << "(" << pair_var.first << ", " << pair_var.second << ")";
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, const pair<T, U>& pair_var) {
	os << "(" << pair_var.first << ", " << pair_var.second << ")";
	return os;
}
template<typename T, typename U>
ostream& operator << (ostream& os, map<T, U>& map_var) {
	for(typename map<T, U>::iterator itr = map_var.begin(); itr != map_var.end(); itr++) {
		os << "(" << itr->first << ", " << itr->second << ")";
		itr++; if(itr != map_var.end()) os << ","; itr--;
	}
	return os;
}
template<typename T>
ostream& operator << (ostream& os, set<T>& set_var) {
	for(typename set<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
		os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
	}
	return os;
}
template<typename T>
ostream& operator << (ostream& os, multiset<T>& set_var) {
	for(typename multiset<T>::iterator itr = set_var.begin(); itr != set_var.end(); itr++) {
		os << *itr; ++itr; if(itr != set_var.end()) os << " "; itr--;
	}
	return os;
}
template<typename T>
void outa(T a[], ll s, ll t){
	for(ll i = s; i <= t; i++){ cout << a[i]; if(i < t) cout << " ";}
	cout << endl;
}
void dump_func() {cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail) {
	cout << head;
	if(sizeof...(Tail) > 0) cout << " ";
	dump_func(std::move(tail)...);
}


struct Matrix{
	typedef mint T;
	
	int h, w;
	vector<T> mat;
	Matrix(){h = w = 0;}
	Matrix(int h, int w){
		this->h = h, this->w = w;
		mat.resize(h*w);
	}
	
	T addope(T a, T b){ return a+b; } //加法作用素
		static T addIdent(){ return mint(0);} //加法単位元
	T mulope(T a, T b){ return a*b; } //乗法作用素
		static T mulIdent(){ return mint(1); } //乗法単位元
	
	T& at(int i, int j){ return mat[w*(i-1)+(j-1)];}
	static Matrix Ident(int size){
		Matrix ret(size, size);
		for(int i = 1; i <= size; i++){
			for(int j = 1; j <= size; j++){
				if(i == j) ret.at(i, j) = mulIdent();
				else ret.at(i, j) = addIdent();
			}
		}
		return ret;
	}
	Matrix operator+(Matrix& ope){
		Matrix ret(h, w);
		for(int i = 1; i <= h; i++){
			for(int j = 1; j <= w; j++){
				ret.at(i, j) = at(i, j) + ope.at(i, j);
			}
		}
		return ret;
	}
	Matrix operator*(Matrix& ope){
		Matrix ret(h, ope.w);
		for(int i = 1; i <= h; i++){
			for(int j = 1; j <= ope.w; j++){
				ret.at(i, j) = addIdent();
				for(int k = 1; k <= w; k++){
					ret.at(i, j) = addope(ret.at(i, j), mulope(at(i, k), ope.at(k, j)));
				}
			}
		}
		return ret;
	}
	Matrix pow(llint n){
		if(n == 0) return Ident(h);
		if(n % 2) return pow(n-1) * (*this);
		else{
			Matrix tmp = pow(n/2);
			return tmp * tmp;
		}
	}
};
ostream& operator << (ostream& os, Matrix& mat) {
	for(int i = 1; i <= mat.h; i++){
		for(int j = 1; j <= mat.w; j++) os << mat.mat[mat.w*(i-1)+(j-1)] << " "; cout << endl;
	}
	return os;
}
ostream& operator << (ostream& os, const Matrix& mat) {
	for(int i = 1; i <= mat.h; i++){
		for(int j = 1; j <= mat.w; j++) os << mat.mat[mat.w*(i-1)+(j-1)] << " "; cout << endl;
	}
	return os;
}

ll n, m;
ll a[3005];
ll dp[3005][3005];

int main(void)
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cin >> n >> m;
	rep(i, 1, n) cin >> a[i];
	sort(a+1, a+n+1), reverse(a+1, a+n+1);
	
	rep(i, 0, n) rep(j, 0, m) dp[i][j] = -inf;
	dp[0][0] = 0;
	
	rep(i, 0, n-1) rep(j, 0, m){
		chmax(dp[i+1][j], dp[i][j]);
		if(i+2 <= n && j+a[i+1]-a[i+2] <= m) chmax(dp[i+2][j+a[i+1]-a[i+2]], dp[i][j] + a[i+1]);
	}
	
	ll ans = 0;
	rep(j, 0, m) chmax(ans, dp[n][j]);
	outl(ans);
	
	return 0;
}
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