結果
| 問題 |
No.1094 木登り / Climbing tree
|
| ユーザー |
mkawa2
|
| 提出日時 | 2021-06-10 18:44:59 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,141 ms / 2,000 ms |
| コード長 | 2,502 bytes |
| コンパイル時間 | 335 ms |
| コンパイル使用メモリ | 82,176 KB |
| 実行使用メモリ | 249,180 KB |
| 最終ジャッジ日時 | 2024-11-08 07:22:01 |
| 合計ジャッジ時間 | 26,280 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 26 |
ソースコード
import sys
# sys.setrecursionlimit(10**6)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.buffer.readline())
def LI(): return list(map(int, sys.stdin.buffer.readline().split()))
def LI1(): return list(map(int1, sys.stdin.buffer.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def BI(): return sys.stdin.buffer.readline().rstrip()
def SI(): return sys.stdin.buffer.readline().rstrip().decode()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
dij = [(0, 1), (1, 0), (1, 1), (1, -1)]
inf = 10**16
md = 998244353
# md = 10**9+7
class SparseTableMin:
def __init__(self, aa):
w = len(aa)
h = (w-1).bit_length()
table = [aa]+[[-1]*w for _ in range(h-1)]
tablei1 = table[0]
for i in range(1, h):
tablei = table[i]
for j in range(w-(1 << i)+1):
rj = j+(1 << i-1)
tablei[j] = min(tablei1[j], tablei1[rj])
tablei1 = tablei
self.table = table
def min(self, l, r):
i = (r-l).bit_length()-1
tablei = self.table[i]
Lmin = tablei[l]
Rmin = tablei[r-(1 << i)]
if Lmin < Rmin: Rmin = Lmin
return Rmin
class LCA:
def __init__(self, et, depth, first):
n = len(depth)
self.sp = SparseTableMin([(depth[u], u) for u in et])
self.first = first
def get_lca(self, u, v):
l, r = self.first[u], self.first[v]
if l > r: l, r = r, l
return self.sp.min(l, r+1)[1]
def DFS(to, root=0):
stack = [root << 1 | 1]
while stack:
u, f = divmod(stack.pop(), 2)
euler.append(u)
if f:
first[u] = len(euler)-1
for v, c in to[u]:
if v == parent[u]: continue
parent[v] = u
depth[v] = depth[u]+1
cost[v] = cost[u]+c
stack.append(u << 1)
stack.append(v << 1 | 1)
n = II()
to = [[] for _ in range(n)]
for _ in range(n-1):
u, v, c = LI1()
to[u].append((v, c+1))
to[v].append((u, c+1))
cost = [0]*n
euler = []
depth = [0]*n
first = [0]*n
parent = [-1]*n
DFS(to)
lca = LCA(euler, depth, first)
# print(euler)
for _ in range(II()):
u, v = LI1()
w = lca.get_lca(u, v)
# print(u,v,w)
print(cost[u]+cost[v]-cost[w]*2)
mkawa2