結果

問題 No.1545 [Cherry 2nd Tune N] Anthem
ユーザー sten_san
提出日時 2021-06-11 22:04:01
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 124 ms / 3,000 ms
コード長 2,586 bytes
コンパイル時間 2,174 ms
コンパイル使用メモリ 216,144 KB
最終ジャッジ日時 2025-01-22 05:54:09
ジャッジサーバーID
(参考情報)
judge3 / judge5
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ファイルパターン 結果
other AC * 67
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
struct iofast_t {
iofast_t() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
}
} iofast;
struct uns_t {} uns;
template <typename Element, typename Head, typename ...Args>
auto vec(Element init, Head arg, Args ...args) {
if constexpr (sizeof...(Args) == 0) return std::vector(arg, init);
else return std::vector(arg, vec(init, args...));
}
template <typename Element, typename Head, typename ...Args>
auto vec(uns_t, Head arg, Args ...args) {
return vec(Element(), arg, args...);
}
template <typename T, typename Compare = less<T>>
T &chmin(T &l, T r, Compare &&f = less<T>()) { return l = min(l, r, f); }
template <typename T, typename Compare = less<T>>
T &chmax(T &l, T r, Compare &&f = less<T>()) { return l = max(l, r, f); }
template <typename T>
using pqueue = priority_queue<T, vector<T>, greater<T>>;
int main() {
constexpr int64_t inf = INT64_MAX / 4;
constexpr auto inv = make_tuple(-1, -1);
int n, s, t, k;
cin >> n >> s >> t >> k;
--s; --t;
auto x = vec<int>(uns, n);
for (auto &e : x) cin >> e;
int m; cin >> m;
auto g = vec<tuple<int, int>>(uns, n, 0);
for (int i = 0; i < m; ++i) {
int a, b, y; cin >> a >> b >> y; --a; --b;
g[a].push_back({ b, x[b] + y });
}
pqueue<tuple<int64_t, int, int>> que;
auto dist = vec<int64_t>(inf, n, k + 1);
auto prev = vec<tuple<int, int>>(inv, n, k + 1);
que.push({ x[s], s, 1 });
dist[s][1] = x[s];
while (!empty(que)) {
auto [d, v, c] = que.top(); que.pop();
if (dist[v][c] < d) {
continue;
}
for (auto [u, w] : g[v]) {
if (dist[u][min(k, c + 1)] <= d + w) {
continue;
}
dist[u][min(k, c + 1)] = d + w;
prev[u][min(k, c + 1)] = { v, c };
que.push({ dist[u][min(k, c + 1)], u, min(k, c + 1) });
}
}
if (dist[t][k] == inf) {
cout << "Impossible" << endl;
return 0;
}
auto path = [&] {
auto path = vec<int>(uns, 0);
int v = t, c = k;
while (0 <= v && 0 <= c) {
path.push_back(v);
auto [pv, pc] = prev[v][c];
v = pv; c = pc;
}
reverse(begin(path), end(path));
return path;
}();
cout << "Possible" << endl;
cout << dist[t][k] << endl;
cout << size(path) << endl;
cout << path[0] + 1;
for (int i = 1; i < size(path); ++i) {
cout << ' ' << path[i] + 1;
}
cout << endl;
}
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