結果
問題 | No.1545 [Cherry 2nd Tune N] Anthem |
ユーザー |
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提出日時 | 2021-06-11 22:41:12 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 205 ms / 3,000 ms |
コード長 | 2,643 bytes |
コンパイル時間 | 3,573 ms |
コンパイル使用メモリ | 264,108 KB |
最終ジャッジ日時 | 2025-01-22 06:22:17 |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 67 |
ソースコード
#include<bits/stdc++.h>#include<atcoder/all>using namespace std;using namespace atcoder;#define rep(i,n)for (int i = 0; i < int(n); ++i)#define rrep(i,n)for (int i = int(n)-1; i >= 0; --i)#define all(x) (x).begin(), (x).end()#define rall(x) (x).rbegin(), (x).rend()template<class T> void chmax(T& a, const T& b) {a = max(a, b);}template<class T> void chmin(T& a, const T& b) {a = min(a, b);}using ll = long long;using P = pair<int,int>;using VI = vector<int>;using VVI = vector<VI>;using VL = vector<ll>;using VVL = vector<VL>;const unsigned long long INF = 1002003004005006007;template<class T>std::pair<std::vector<unsigned long long>, std::vector<int>> dijkstra(std::vector<std::vector<std::pair<int,T>>>& to, int s=0) {struct QueElem {int v;unsigned long long c;bool operator<(const QueElem a) const {return c > a.c;}QueElem(int v, unsigned long long c): v(v), c(c) {}};std::pair<std::vector<unsigned long long>, std::vector<int>> res;std::vector<unsigned long long>& dist = res.first;std::vector<int>& pre = res.second;dist.resize(to.size(), INF);pre.resize(to.size(), -1);std::priority_queue<QueElem> q;dist[s] = 0;pre[s] = -1;q.emplace(s, 0);while(!q.empty()) {QueElem qe = q.top(); q.pop();int u = qe.v;unsigned long long c = qe.c;if (c > dist[u]) continue;for(auto vc: to[u]) {int v = vc.first;unsigned long long nc = c + vc.second;if (nc < dist[v]) {dist[v] = nc;pre[v] = u;q.emplace(v, nc);}}}return res;}int main() {ios::sync_with_stdio(false);cin.tie(0);int n, s, t, k;cin >> n >> s >> t >> k;s--, t--; k--;VI x(n);rep(i, n) cin >> x[i];int m;cin >> m;vector<vector<P>> to(n * (k + 1));rep(_, m) {int a, b, y;cin >> a >> b >> y;--a, --b;rep(j, k) {to[(k + 1) * a + j].emplace_back((k + 1) * b + j + 1, y + x[b]);}to[(k + 1) * a + k].emplace_back((k + 1) * b + k, y + x[b]);}auto [dist, pre] = dijkstra(to, (k + 1) * s);if (dist[(k + 1) * t + k] == INF) {cout << "Impossible" << '\n';return 0;}cout << "Possible" << '\n';cout << x[s] + dist[(k + 1) * t + k] << '\n';VI ps;for(int v = (k + 1) * t + k; v != -1; v = pre[v]) {ps.push_back(v / (k + 1));}int sz = ps.size();cout << sz << '\n';rrep(i, sz) cout << ps[i] + 1 << " \n"[i == 0];}