結果
問題 |
No.1640 簡単な色塗り
|
ユーザー |
![]() |
提出日時 | 2021-06-19 15:21:53 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 630 ms / 2,000 ms |
コード長 | 2,645 bytes |
コンパイル時間 | 207 ms |
コンパイル使用メモリ | 82,224 KB |
実行使用メモリ | 119,336 KB |
最終ジャッジ日時 | 2024-06-29 14:49:50 |
合計ジャッジ時間 | 27,386 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 53 |
ソースコード
class dsu: def __init__(self,n): assert n>0,"n must be Natural" self.n=n self.parents=[-1]*n return def find(self,x): assert x<self.n,"warning!! this is 0 index" if self.parents[x]<0: return x self.parents[x]=self.find(self.parents[x]) return self.parents[x] def merge(self,x,y): assert x<self.n and y<self.n,"warning!! this is 0 index" x=self.find(x) y=self.find(y) if x==y: return if self.parents[x]>self.parents[y]: x,y=y,x self.parents[x]+=self.parents[y] self.parents[y]=x return def size(self,x): assert x<self.n,"warning!! this is 0 index" return -self.parents[self.find(x)] def same(self,x,y): assert x<self.n and y<self.n,"warning!! this is 0 index" return self.find(x)==self.find(y) def leader(self,x): assert x<self.n,"warning!! this is 0 index" if self.parents[x]<0: return x self.parents[x]=self.leader(self.parents[x]) return self.parents[x] def groups(self): ld=[self.leader(i) for i in range(self.n)] res=[[] for _ in range(self.n)] for i in range(self.n): res[ld[i]].append(i) return list(filter(lambda a:a !=[],res)) from collections import deque def main(): N=int(input()) uf=dsu(N) to=[[]for _ in[0]*N] for i in range(N): A,B=map(int,input().split()) uf.merge(A-1,B-1) to[A-1].append([B-1,i]) if A!=B: to[B-1].append([A-1,i]) seen=[0]*N ans=[-1]*N gr=uf.groups() for linked in gr: is_cycle=True root=-1 cycle_cnt=0 for point in linked: link_size=len(to[point]) for k in range(link_size): if to[point][k][0]==point: cycle_cnt+=1 is_cycle=False ans[to[point][k][1]]=point+1 root=point if cycle_cnt>1: print("No") return if is_cycle: next_point=-1 que=deque() que.append([linked[0],-1]) while que: q=que.pop() for j in to[q[0]]: if j[1]==q[1]: continue if seen[j[0]]: root=j[0] next_point=q[0] ans[j[1]]=root+1 que.clear() break que.append([j[0],j[1]]) seen[q[0]]=1 if next_point==-1: print("No") return dq=deque() dq.append(root) while dq: q=dq.pop() for j in to[q]: if ans[j[1]]==-1: ans[j[1]]=j[0]+1 dq.append(j[0]) for i in ans: if i==-1: print("No") return print("Yes") for i in ans: print(i) return main()