#668554 (C) No.1615 Double Down

提出ソース

結果

問題	No.1615 Double Down
ユーザー	ygussany
提出日時	2021-06-20 13:49:15
言語	C (gcc 12.3.0)
結果	RE
実行時間	-
コード長	5,522 bytes
コンパイル時間	588 ms
コンパイル使用メモリ	35,068 KB
実行使用メモリ	13,144 KB
最終ジャッジ日時	2024-07-17 15:15:23
合計ジャッジ時間	10,739 ms
ジャッジサーバーID （参考情報）	judge1 / judge3

このコードへのチャレンジ
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テストケース

テストケース表示

入力	結果	実行時間実行使用メモリ
testcase_00	RE	-
testcase_01	RE	-
testcase_02	RE	-
testcase_03	RE	-
testcase_04	RE	-
testcase_05	RE	-
testcase_06	RE	-
testcase_07	RE	-
testcase_08	RE	-
testcase_09	RE	-
testcase_10	RE	-
testcase_11	RE	-
testcase_12	RE	-
testcase_13	RE	-
testcase_14	RE	-
testcase_15	RE	-
testcase_16	RE	-
testcase_17	RE	-
testcase_18	RE	-
testcase_19	RE	-
testcase_20	RE	-
testcase_21	RE	-
testcase_22	RE	-
testcase_23	RE	-
testcase_24	RE	-
testcase_25	RE	-
testcase_26	RE	-
testcase_27	AC	26 ms 6,940 KB
testcase_28	AC	26 ms 6,940 KB
testcase_29	AC	44 ms 7,412 KB
testcase_30	AC	44 ms 6,948 KB
testcase_31	AC	46 ms 6,944 KB
testcase_32	AC	45 ms 6,944 KB
testcase_33	AC	72 ms 7,728 KB
testcase_34	AC	69 ms 6,940 KB
testcase_35	AC	71 ms 6,940 KB
testcase_36	WA	-
testcase_37	AC	3 ms 6,944 KB
testcase_38	AC	3 ms 6,940 KB
testcase_39	AC	4 ms 6,944 KB
testcase_40	AC	3 ms 6,940 KB
testcase_41	AC	3 ms 6,940 KB
testcase_42	WA	-
testcase_43	WA	-
testcase_44	WA	-
testcase_45	AC	1 ms 6,944 KB
testcase_46	AC	1 ms 6,940 KB
testcase_47	AC	2 ms 6,944 KB
testcase_48	AC	1 ms 6,940 KB
testcase_49	AC	2 ms 6,940 KB
testcase_50	AC	1 ms 6,940 KB
testcase_51	AC	1 ms 6,944 KB
testcase_52	AC	1 ms 6,940 KB
testcase_53	AC	1 ms 6,940 KB
testcase_54	AC	1 ms 6,944 KB
testcase_55	AC	1 ms 6,940 KB
testcase_56	AC	2 ms 6,944 KB

権限があれば一括ダウンロードができます

ソースコード

raw source code

#include <stdio.h>
#include <stdlib.h>

typedef struct {
	int id, head, tail, flow, cap, cost;
} edge;

typedef struct List {
	struct List *next;
	edge *e;
} list;

const int sup = 1 << 30;

void chmin(int* a, int b)
{
	if (*a > b) *a = b;
}

int DFS(list *aux[], edge f[], int par[], int u)
{
	int i, w, c, argmin;
	for (; aux[u] != NULL; aux[u] = aux[u]->next) {
		if (aux[u]->e->flow == aux[u]->e->cap) continue;
		w = aux[u]->e->head;
		if (par[w] == -3) {
			for (i = aux[u]->e->id, c = sup; par[w] != -2; i = par[w]) {
				chmin(&c, f[i].cap - f[i].flow);
				w = f[i].tail;
				if (f[i].cap - f[i].flow == c) argmin = w;
			}
			for (i = aux[u]->e->id, w = aux[u]->e->head; par[w] != -2; i = par[w]) {
				f[i].flow += c;
				w = f[i].tail;
			}
			if (argmin != u) {
				par[u] = -1;
				return argmin;
			}
		} else if (par[w] == -1) {
			par[w] = aux[u]->e->id;
			w = DFS(aux, f, par, w);
			if (w > 0 && w != u) {
				par[u] = -1;
				return w;
			}
		}
	}
	return 0;
}

int Dinic(int N, int M, list* adj[], edge e[], int s, int t)
{
	int i, u, w, ans = 0, add, *par = (int*)malloc(sizeof(int) * (N + 1)), *dist = (int*)malloc(sizeof(int) * (N + 1)), *q = (int*)malloc(sizeof(int) * (N + 1)), head, tail;
	list **aux = (list**)malloc(sizeof(list*) * (N + 1)), *df = (list*)malloc(sizeof(list) * (M + 1)), *p;
	edge *f = (edge*)malloc(sizeof(edge) * (M + 1));
	for (i = 0; i < M; i++) f[i].flow = 0;
	do {
		for (u = 1; u <= N; u++) {
			dist[u] = -1;
			aux[u] = NULL;
		}
		dist[s] = 0;
		q[0] = s;
		for (head = 0, tail = 1; head < tail; head++) {
			u = q[head];
			for (p = adj[u]; p != NULL; p = p->next) {
				if (p->e->flow == p->e->cap) continue;
				w = p->e->head;
				if (dist[w] == -1) {
					dist[w] = dist[u] + 1;
					q[tail++] = w;
				}
				if (dist[w] == dist[u] + 1) {
					i = p->e->id;
					f[i].id = i;
					f[i].tail = u;
					f[i].head = w;
					f[i].flow = 0;
					f[i].cap = p->e->cap - p->e->flow;
					df[i].e = &(f[i]);
					df[i].next = aux[u];
					aux[u] = &(df[i]);
				}
			}
		}
		for (u = 1; u <= N; u++) par[u] = -1;
		par[s] = -2;
		par[t] = -3;
		DFS(aux, f, par, s);

		for (i = 0, add = 0; i < M; i++) {
			if (e[i].flow == e[i].cap || dist[e[i].head] != dist[e[i].tail] + 1 || f[i].flow == 0) continue;
			if (f[i].tail == s) add += f[i].flow;
			if (e[i^1].flow > 0) {
				e[i^1].flow -= f[i].flow;
				e[i].cap -= f[i].flow;
			} else {
				e[i].flow += f[i].flow;
				e[i^1].cap += f[i].flow;
			}
		}
		ans += add;
	} while (add != 0);
	
	free(par);
	free(dist);
	free(q);
	free(aux);
	free(df);
	free(f);
	return ans;
}

long long solve(int N, int M, int K, int L, int X[], int Y[], int Z[])
{
	int i, k, m = 0, F = 0, F_tmp, u, w, s = N + M + 1, t = N + M + 2, bit[31], flag[10003] = {}, tmp[10003], q[10003], head, tail;
	long long ans = 0;
	list *adj[10003] = {}, d[220001], *p, *pp;
    edge e[220001];
	for (i = 1, bit[0] = 1; i <= K; i++) bit[i] = bit[i-1] << 1;
	for (i = 1; i <= N; i++) {
		u = s;
		w = i;
		e[m].id = m;
		e[m].tail = u;
		e[m].head = w;
		e[m].flow = 0;
		e[m].cap = 1;
		e[m].cost = K;
		d[m].e = &(e[m]);
		d[m].next = adj[u];
		adj[u] = &(d[m++]);
		e[m].id = m;
		e[m].tail = w;
		e[m].head = u;
		e[m].flow = 0;
		e[m].cap = 0;
		e[m].cost = K;
		d[m].e = &(e[m]);
		d[m].next = adj[w];
		adj[w] = &(d[m++]);
	}
	for (i = 1; i <= M; i++) {
		u = i + N;
		w = t;
		e[m].id = m;
		e[m].tail = u;
		e[m].head = w;
		e[m].flow = 0;
		e[m].cap = 1;
		e[m].cost = K;
		d[m].e = &(e[m]);
		d[m].next = adj[u];
		adj[u] = &(d[m++]);
		e[m].id = m;
		e[m].tail = w;
		e[m].head = u;
		e[m].flow = 0;
		e[m].cap = 0;
		e[m].cost = K;
		d[m].e = &(e[m]);
		d[m].next = adj[w];
		adj[w] = &(d[m++]);
	}
	for (k = K; k >= 0; k--) {
		for (i = 1; i <= L; i++) {
			u = X[i];
			w = Y[i] + N;
			if (Z[i] != k || flag[u] != 0 || flag[w] != 0) continue;
			e[m].id = m;
			e[m].tail = u;
			e[m].head = w;
			e[m].flow = 0;
			e[m].cap = 1;
			e[m].cost = k;
			d[m].e = &(e[m]);
			d[m].next = adj[u];
			adj[u] = &(d[m++]);
			e[m].id = m;
			e[m].tail = w;
			e[m].head = u;
			e[m].flow = 0;
			e[m].cap = 0;
			e[m].cost = k;
			d[m].e = &(e[m]);
			d[m].next = adj[w];
			adj[w] = &(d[m++]);
		}
		F_tmp = Dinic(t, m, adj, e, s, t);
		ans += (long long)(F_tmp - F) * bit[k];
		F = F_tmp;
		
		for (u = 1; u <= t; u++) tmp[u] = 0;
		q[0] = s;
		tmp[s] = 1;
		for (head = 0, tail = 1; head < tail; head++) {
			u = q[head];
			for (pp = adj[u]; pp != NULL; pp = pp->next) {
				if (pp->e->flow == pp->e->cap || pp->e->head >= s) continue;
				w = pp->e->head;
				if (tmp[w] == 0) {
					tmp[w] = -tmp[u];
					q[tail++] = w;
				}
			}
		}
		q[0] = t;
		tmp[t] = 1;
		for (head = 0, tail = 1; head < tail; head++) {
			u = q[head];
			for (pp = adj[u]; pp != NULL; pp = pp->next) {
				if (pp->e->flow != pp->e->cap || pp->e->head >= s) continue;
				w = pp->e->head;
				if (tmp[w] == 0) {
					tmp[w] = -tmp[u];
					q[tail++] = w;
				}
			}
		}
		for (i = 0; i < m; i += 2) {
			u = e[i].tail;
			w = e[i].head;
			if (tmp[u] >= 0 && tmp[w] >= 0 && e[i].flow == 0) {
				e[i].cap = 0;
				e[i^1].cap = 0;
			} else {
				e[i].flow = 0;
				e[i].cap = 1;
				e[i^1].cap = 0;
			}
		}
		for (u = 1; u <= N + M; u++) if (flag[u] == 0 && tmp[u] >= 0) flag[u] = k;
	}
	return ans;
}

int main()
{
	int i, j, N, M, K, L, r, X[100001], Y[100001], Z[100001];
	scanf("%d %d %d %d", &N, &M, &K, &L);
	for (i = 1; i <= L; i++) scanf("%d %d %d", &(X[i]), &(Y[i]), &(Z[i]));
	printf("%lld\n", solve(N, M, K, L, X, Y, Z));
	fflush(stdout);
	return 0;
}

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結果

テストケース

ソースコード