結果

問題 No.1615 Double Down
ユーザー 👑 ygussany
提出日時 2021-06-20 20:29:34
言語 C
(gcc 13.3.0)
結果
AC  
実行時間 1,386 ms / 10,000 ms
コード長 5,777 bytes
コンパイル時間 423 ms
コンパイル使用メモリ 35,456 KB
実行使用メモリ 21,584 KB
最終ジャッジ日時 2024-07-17 15:16:57
合計ジャッジ時間 18,738 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 54
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <stdio.h>
#include <stdlib.h>
typedef struct {
int id, head, tail, flow, cap, cost;
} edge;
typedef struct List {
struct List *next;
edge *e;
} list;
const int sup = 1 << 30;
void chmin(int* a, int b)
{
if (*a > b) *a = b;
}
int DFS(list *aux[], edge f[], int par[], int u)
{
int i, w, c, argmin;
for (; aux[u] != NULL; aux[u] = aux[u]->next) {
if (aux[u]->e->flow == aux[u]->e->cap) continue;
w = aux[u]->e->head;
if (par[w] == -3) {
for (i = aux[u]->e->id, c = sup; par[w] != -2; i = par[w]) {
chmin(&c, f[i].cap - f[i].flow);
w = f[i].tail;
if (f[i].cap - f[i].flow == c) argmin = w;
}
for (i = aux[u]->e->id, w = aux[u]->e->head; par[w] != -2; i = par[w]) {
f[i].flow += c;
w = f[i].tail;
}
if (argmin != u) {
par[u] = -1;
return argmin;
}
} else if (par[w] == -1) {
par[w] = aux[u]->e->id;
w = DFS(aux, f, par, w);
if (w > 0 && w != u) {
par[u] = -1;
return w;
}
}
}
return 0;
}
int Dinic(int N, int M, list* adj[], edge e[], int s, int t)
{
int i, u, w, ans = 0, add, *par = (int*)malloc(sizeof(int) * (N + 1)), *dist = (int*)malloc(sizeof(int) * (N + 1)), *q = (int*)malloc(sizeof(int)
        * (N + 1)), head, tail;
list **aux = (list**)malloc(sizeof(list*) * (N + 1)), *df = (list*)malloc(sizeof(list) * (M + 1)), *p;
edge *f = (edge*)malloc(sizeof(edge) * (M + 1));
for (i = 0; i < M; i++) f[i].flow = 0;
do {
for (u = 1; u <= N; u++) {
dist[u] = -1;
aux[u] = NULL;
}
dist[s] = 0;
q[0] = s;
for (head = 0, tail = 1; head < tail; head++) {
u = q[head];
for (p = adj[u]; p != NULL; p = p->next) {
if (p->e->flow == p->e->cap) continue;
w = p->e->head;
if (dist[w] == -1) {
dist[w] = dist[u] + 1;
q[tail++] = w;
}
if (dist[w] == dist[u] + 1) {
i = p->e->id;
f[i].id = i;
f[i].tail = u;
f[i].head = w;
f[i].flow = 0;
f[i].cap = p->e->cap - p->e->flow;
df[i].e = &(f[i]);
df[i].next = aux[u];
aux[u] = &(df[i]);
}
}
}
for (u = 1; u <= N; u++) par[u] = -1;
par[s] = -2;
par[t] = -3;
DFS(aux, f, par, s);
for (i = 0, add = 0; i < M; i++) {
if (e[i].flow == e[i].cap || dist[e[i].head] != dist[e[i].tail] + 1 || f[i].flow == 0) continue;
if (f[i].tail == s) add += f[i].flow;
if (e[i^1].flow > 0) {
e[i^1].flow -= f[i].flow;
e[i].cap -= f[i].flow;
} else {
e[i].flow += f[i].flow;
e[i^1].cap += f[i].flow;
}
}
ans += add;
} while (add != 0);
free(par);
free(dist);
free(q);
free(aux);
free(df);
free(f);
return ans;
}
long long solve(int N, int M, int K, int L, int X[], int Y[], int Z[])
{
int i, k, m = 0, F = 0, F_tmp, u, w, s = N + M + 1, t = N + M + 2, bit[31], flag[200003] = {}, tmp[200003], q[200003], head, tail;
long long ans = 0;
list *adj[200003] = {}, d[800001], *p, *pp;
edge e[800001];
for (i = 1, bit[0] = 1; i <= K; i++) bit[i] = bit[i-1] << 1;
for (i = 1; i <= N; i++) {
u = s;
w = i;
e[m].id = m;
e[m].tail = u;
e[m].head = w;
e[m].flow = 0;
e[m].cap = 1;
e[m].cost = K;
d[m].e = &(e[m]);
d[m].next = adj[u];
adj[u] = &(d[m++]);
e[m].id = m;
e[m].tail = w;
e[m].head = u;
e[m].flow = 0;
e[m].cap = 0;
e[m].cost = K;
d[m].e = &(e[m]);
d[m].next = adj[w];
adj[w] = &(d[m++]);
}
for (i = 1; i <= M; i++) {
u = i + N;
w = t;
e[m].id = m;
e[m].tail = u;
e[m].head = w;
e[m].flow = 0;
e[m].cap = 1;
e[m].cost = K;
d[m].e = &(e[m]);
d[m].next = adj[u];
adj[u] = &(d[m++]);
e[m].id = m;
e[m].tail = w;
e[m].head = u;
e[m].flow = 0;
e[m].cap = 0;
e[m].cost = K;
d[m].e = &(e[m]);
d[m].next = adj[w];
adj[w] = &(d[m++]);
}
for (k = K; k >= 0; k--) {
for (i = 1; i <= L; i++) {
u = X[i];
w = Y[i] + N;
if (Z[i] != k || flag[u] != 0 || flag[w] != 0) continue;
e[m].id = m;
e[m].tail = u;
e[m].head = w;
e[m].flow = 0;
e[m].cap = 1;
e[m].cost = k;
d[m].e = &(e[m]);
d[m].next = adj[u];
adj[u] = &(d[m++]);
e[m].id = m;
e[m].tail = w;
e[m].head = u;
e[m].flow = 0;
e[m].cap = 0;
e[m].cost = k;
d[m].e = &(e[m]);
d[m].next = adj[w];
adj[w] = &(d[m++]);
}
F_tmp = Dinic(t, m, adj, e, s, t);
ans += (long long)(F_tmp - F) * bit[k];
F = F_tmp;
for (u = 1; u <= t; u++) tmp[u] = 0;
q[0] = s;
tmp[s] = 1;
for (head = 0, tail = 1; head < tail; head++) {
u = q[head];
for (pp = adj[u]; pp != NULL; pp = pp->next) {
if (pp->e->flow == pp->e->cap || pp->e->head >= s) continue;
w = pp->e->head;
if (tmp[w] == 0) {
tmp[w] = -tmp[u];
q[tail++] = w;
}
}
}
q[0] = t;
tmp[t] = 1;
for (head = 0, tail = 1; head < tail; head++) {
u = q[head];
for (pp = adj[u]; pp != NULL; pp = pp->next) {
if (e[pp->e->id ^ 1].flow == e[pp->e->id ^ 1].cap || pp->e->head >= s) continue;
w = pp->e->head;
if (tmp[w] == 0) {
tmp[w] = -tmp[u];
q[tail++] = w;
}
}
}
for (i = 0; i < m; i += 2) {
u = e[i].tail;
w = e[i].head;
if (e[i].cap == 0 && e[i^1].cap == 0) continue;
if (u == s) {
if (tmp[w] == 0) {
e[i].cap = 0;
if (e[i].flow != 0) F--;
} else e[i].cap = 1;
} else if (w == t) {
if (tmp[u] == 0) e[i].cap = 0;
else e[i].cap = 1;
} else {
if (tmp[u] == 0 || tmp[w] == 0 || tmp[u] + tmp[w] == 2) e[i].cap = 0;
else e[i].cap = 1;
}
e[i].flow = 0;
e[i^1].cap = 0;
}
for (u = 1; u <= N + M; u++) if (flag[u] == 0 && tmp[u] >= 0) flag[u] = k;
}
return ans;
}
int main()
{
int i, j, N, M, K, L, r, X[200001], Y[200001], Z[200001];
scanf("%d %d %d %d", &N, &M, &K, &L);
for (i = 1; i <= L; i++) scanf("%d %d %d", &(X[i]), &(Y[i]), &(Z[i]));
printf("%lld\n", solve(N, M, K, L, X, Y, Z));
fflush(stdout);
return 0;
}
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