結果
| 問題 | No.1566 All Even | 
| コンテスト | |
| ユーザー |  mkawa2 | 
| 提出日時 | 2021-06-28 10:42:50 | 
| 言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 122 ms / 2,000 ms | 
| コード長 | 1,863 bytes | 
| コンパイル時間 | 94 ms | 
| コンパイル使用メモリ | 12,928 KB | 
| 実行使用メモリ | 11,008 KB | 
| 最終ジャッジ日時 | 2024-06-25 12:05:00 | 
| 合計ジャッジ時間 | 2,383 ms | 
| ジャッジサーバーID (参考情報) | judge4 / judge2 | 
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| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 2 | 
| other | AC * 28 | 
ソースコード
import sys
# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.buffer.readline())
def LI(): return list(map(int, sys.stdin.buffer.readline().split()))
def LI1(): return list(map(int1, sys.stdin.buffer.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def BI(): return sys.stdin.buffer.readline().rstrip()
def SI(): return sys.stdin.buffer.readline().rstrip().decode()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = 10**16
md = 998244353
# md = 10**9+7
n,m=LI()
xyz=LLI(m)
if n>=7:
    for x,y,z in xyz:
        if z==0:
            print(0)
            exit()
    print(1)
    exit()
xyz=[(x-1,y-1,z) for x,y,z in xyz]
ans=0
for bit in range(1 << 2*n-1):
    tt = [[0]*n for _ in range(n)]
    for i in range(n):
        tt[i][0] = bit >> i & 1
    for j in range(1, n):
        tt[0][j] = bit >> j+n-1 & 1
    for i in range(1, n):
        for j in range(1, n):
            s = tt[i-1][j-1] ^ tt[i][j-1] ^ tt[i-1][j]
            tt[i][j] = s
    cs = [[0]*(n+1) for _ in range(n+1)]
    for i in range(n):
        for j in range(n):
            cs[i+1][j+1] = cs[i+1][j] ^ tt[i][j]
    for j in range(n):
        for i in range(n):
            cs[i+1][j+1] ^= cs[i][j+1]
    def ok():
        for x,y,z in xyz:
            if tt[x][y]==z:return False
        for d in range(3, n+1):
            for i in range(n-d+1):
                for j in range(n-d+1):
                    x = cs[i][j] ^ cs[i+d][j+d] ^ cs[i+d][j] ^ cs[i][j+d]
                    if x: return False
        return True
    # print("OK" if ok() else "NG")
    if ok():
        ans+=1
        # p2D(tt)
        # print()
print(ans)
            
            
            
        