結果

問題 No.1578 A × B × C
ユーザー noya2
提出日時 2021-07-02 21:48:15
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,877 bytes
コンパイル時間 5,066 ms
コンパイル使用メモリ 262,588 KB
最終ジャッジ日時 2025-01-22 15:53:21
ジャッジサーバーID
（参考情報） 		judge2 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
/*
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
namespace mp = boost::multiprecision;
using bint = mp::cpp_int;
*/
#include <atcoder/all>
#include <iostream>
#include <queue>
#include <stack>
#include <vector>
#include <string>
#include <set>
#include <map>
#include <random>
#include <bitset>
#define rep(i,n) for (int i = 0; i < int(n); ++i)
#define repp(i,n,m) for (int i = m; i < int(n); ++i)
#define repb(i,n) for (int i = int(n)-1; i >= 0; --i)
using namespace std;
using namespace atcoder;
using namespace internal;
//alias g++='g++ -I/mnt/c/Users/Owner/Desktop/ac-library'
using ll = long long;
using ld = long double;
using P = pair<int, int>;
using PI = pair<pair<int,int>,int>;
using PL = pair<long long, long long>;
using PLL = pair<pair<long long, long long>, long long>;
using Pxy = pair<long double, long double>;
const int INF = 1001001007;
const int modd = 1000000007;
const long long modl = 1000000007LL;
const long long mod = 998244353LL;
const ll inf = 2e18;
template <typename SA>
void priv(vector<SA> &ar){
    if (ar.size() == 0) cout << endl;
    else {
        rep(i,ar.size()-1) cout << ar[i] << " ";
        cout << ar[ar.size()-1] << endl;
    } 
}
template <typename SB>
void privv(vector<vector<SB>> &ar){
    rep(i,ar.size()){
        rep(j,ar[i].size()-1) cout << ar[i][j] << " ";
        cout << ar[i][ar[i].size()-1] << endl;
    }
}
template <typename SC>
bool range(SC a, SC b, SC x){return (a <= x && x < b);}
bool rrange(P a, P b, P xy){
    bool s = range(a.first,b.first,xy.first);
    bool t = range(a.second,b.second,xy.second);
    return (s && t);
}
template <typename SE>
void rev(vector<SE> &ar){reverse(ar.begin(),ar.end());}
template <typename SD>
void sor(vector<SD> &ar, int f = 0){sort(ar.begin(),ar.end()); if (f!=0) rev(ar);}
template <typename SF>
bool chmin(SF &a, const SF &b){if(a>b){a = b; return true;} return false;}
template <typename SG>
bool chmax(SG &a, const SG &b){if(a<b){a = b; return true;} return false;}
template <typename SH>
void eru(vector<SH> &ar){sor(ar);ar.erase(unique(ar.begin(),ar.end()),ar.end());}
template <typename SI>
SI   last(vector<SI> &ar){return ar[ar.size()-1];}
template <typename SJ>
SJ   cel(SJ a, SJ b){if (a % b == 0) return a/b; return a/b +1;}
template <typename SK, typename SL>
void pout(pair<SK,SL> p) {cout << p.first << " " << p.second << endl;}
void yes(){cout << "Yes" << endl;}
void no (){cout << "No" << endl;}
void yn (bool t){if(t)yes();else no();}
void Yes(){cout << "YES" << endl;}
void No (){cout << "NO" << endl;}
void YN (bool t){if(t)Yes();else No();}
void dout() {cout << setprecision(20);}
void deb(int h = 123456789) {cout << h << endl;}
vector<int> dx = {0,1,0,-1};
vector<int> dy = {1,0,-1,0};
const string ALP = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string alp = "abcdefghijklmnopqrstuvwxyz";
ll gcds(ll a, ll b){
    a = abs(a); b = abs(b);
    if (b == 0) return a;
    ll c = a % b;
    while (c != 0){
        a = b;
        b = c;
        c = a % b;
    }
    return b;
}
ll tentou(vector<ll> ar){
    int n = ar.size();
    set<ll> st;
    rep(i,n) st.insert(ar[i]);
    map<ll,int> mp;
    int ind = 0;
    for (ll x : st){
        mp[x] = ind;
        ind++;
    }
    fenwick_tree<ll> fw(ind);
    ll ans = 0;
    rep(i,n){
        int a = mp[ar[i]];
        ans += i - fw.sum(0,a+1);
        fw.add(a,1);
    }
    return ans;
}
struct vs {
    vector<int> to;
};
ll ku(ll a, ll x, ll p){
    a %= p;
    if (x == 1) return a;
    ll ans = ku(a, x/2, p);
    ans *= ans;
    ans %= p;
    if (x % 2 == 1) ans *= a;
    return ans % p;
}
int main(){
    ll a, b, c; cin >> a >> b >> c;
    ll k; cin >> k;
    using mint = modint1000000007;
    mint ans = a;
    ans *= b * c;
    ll x = ku(2LL, k, modl-1);
    x += modl - 1;
    cout << ans.pow(x).val() << endl;
}
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