結果
| 問題 | No.654 Air E869120 |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-07-03 16:05:43 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.89.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 4,194 bytes |
| 記録 | |
| コンパイル時間 | 2,706 ms |
| コンパイル使用メモリ | 217,928 KB |
| 最終ジャッジ日時 | 2025-01-22 17:16:30 |
|
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 5 |
| other | AC * 32 TLE * 3 |
コンパイルメッセージ
main.cpp: In function ‘int main()’:
main.cpp:112:14: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result]
112 | scanf("%lld %lld %lld %lld %lld", &u, &v, &p, &q, &w);
| ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
ソースコード
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
#define REP(i, n) for(int i=0; i<n; i++)
#define REPi(i, a, b) for(int i=int(a); i<int(b); i++)
#define MEMS(a,b) memset(a,b,sizeof(a))
#define mp make_pair
#define MOD(a, m) ((a % m + m) % m)
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
const ll MOD = 1e9+7;
ll V;
const ll INF = 1LL << 60;
const int MAX_V = 2100;
using P = pair<ll, ll>;
//// {行き先, 容量, 逆辺}
//// {to, cap, rev}
//// G[v][to] <-> G[to][rev]
//using Edge = tuple<int, ll, int>;
//vector<Edge> G[MAX_V];
//bool used[MAX_V];
struct edge { int to, rev; long long cap; };
vector<edge> g[2009];
bool vis[2009];
const long long inf = 1LL << 55;
////// G に辺と逆辺を追加
//void add_edge(int from, int to, ll cap){
// G[from].push_back(Edge(to, cap, G[to].size()));
// G[to].push_back(Edge(from, 0, G[from].size()-1));
//}
//
////// 増加パスをdfsで探索
////ll find_path(int v, int t, ll f, auto& used){
//ll find_path(int v, int t, ll f){
// if(v == t) return f;
// used[v] = true;
// for(auto& [to, cap, rev] : G[v]){
// if(!used[to] && cap > 0){
// //ll d = find_path(to, t, min(f, cap), used);
// ll d = find_path(to, t, min(f, cap));
// if(d > 0){
// cap -= d;
// get<1>(G[to][rev]) += d;
// return d;
// }
// }
// }
// return 0;
//}
//
////// sからtへの最大流を求める
//ll max_flow(int s, int t){
// ll flow = 0;
// //array<bool, MAX_V> used;
// while(1){
// //fill(used.begin(), used.end(), false);
// fill(used, used+V, false);
// //ll f = find_path(s, t, INF, used);
// ll f = find_path(s, t, INF);
// if(f == 0) break;
// flow += f;
// }
// return flow;
//}
void add_edge(int v1, int v2, long long cost) {
g[v1].push_back(edge{ v2, (int)g[v2].size(), cost });
g[v2].push_back(edge{ v1, (int)g[v1].size() - 1, 0LL });
}
long long find_augment(int pos, int tar, long long curflow) {
if (pos == tar) return curflow;
vis[pos] = true;
for (edge &e : g[pos]) {
if (!vis[e.to] && e.cap > 0) {
long long newflow = find_augment(e.to, tar, min(e.cap, curflow));
if (newflow > 0) {
e.cap -= newflow;
g[e.to][e.rev].cap += newflow;
return newflow;
}
}
}
return 0;
}
long long max_flow(int src, int dst) {
long long ret = 0;
while (true) {
fill(vis, vis + V, false);
long long res = find_augment(src, dst, inf);
if (res == 0) break;
ret += res;
}
return ret;
}
int main(){
ll N, M, D;
cin >> N >> M >> D;
using T = tuple<ll, ll, ll, ll, ll>;
vector<T> X;
REP(i,M){
ll u, v, p, q, w;
//cin >> u >> v >> p >> q >> w;
scanf("%lld %lld %lld %lld %lld", &u, &v, &p, &q, &w);
u--, v--;
X.push_back(T(u, v, p, q, w));
}
vector<vector<int>> vertex(N);
vertex[0].push_back(0);
vertex[N-1].push_back(1000000000LL);
for(auto& [u, v, p, q, w] : X){
vertex[u].push_back(p);
vertex[v].push_back(q+D);
}
map<P, int> pos2idx;
ll cnt = 0;
REP(v, N){
sort(vertex[v].begin(), vertex[v].end());
vertex[v].erase(unique(vertex[v].begin(), vertex[v].end()), vertex[v].end());
int size = vertex[v].size();
REP(i, size){
pos2idx[P(v, vertex[v][i])] = cnt++;
}
}
for(auto& [u, v, p, q, w] : X){
auto v0 = pos2idx[P(u, p)];
auto v1 = pos2idx[P(v, q+D)];
add_edge(v0, v1, w);
}
REP(v, N){
int size = vertex[v].size();
REP(i, size-1){
auto v0 = pos2idx[P(v, vertex[v][i])];
auto v1 = pos2idx[P(v, vertex[v][i+1])];
add_edge(v0, v1, INF);
}
}
V = cnt;
//cout << V << endl;
ll ans = max_flow(0, cnt-1);
cout << ans << endl;
return 0;
}