結果

問題 No.1595 The Final Digit
ユーザー BSerBSer
提出日時 2021-07-09 22:24:23
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2 ms / 2,000 ms
コード長 3,853 bytes
コンパイル時間 3,910 ms
コンパイル使用メモリ 235,328 KB
実行使用メモリ 6,944 KB
最終ジャッジ日時 2024-07-01 17:01:02
合計ジャッジ時間 4,625 ms
ジャッジサーバーID
(参考情報)
judge1 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,812 KB
testcase_01 AC 2 ms
6,816 KB
testcase_02 AC 2 ms
6,940 KB
testcase_03 AC 2 ms
6,940 KB
testcase_04 AC 2 ms
6,944 KB
testcase_05 AC 2 ms
6,944 KB
testcase_06 AC 2 ms
6,940 KB
testcase_07 AC 2 ms
6,944 KB
testcase_08 AC 2 ms
6,940 KB
testcase_09 AC 2 ms
6,940 KB
testcase_10 AC 2 ms
6,940 KB
testcase_11 AC 2 ms
6,944 KB
testcase_12 AC 2 ms
6,940 KB
testcase_13 AC 2 ms
6,944 KB
testcase_14 AC 2 ms
6,944 KB
testcase_15 AC 1 ms
6,940 KB
testcase_16 AC 2 ms
6,944 KB
testcase_17 AC 2 ms
6,944 KB
testcase_18 AC 1 ms
6,944 KB
testcase_19 AC 2 ms
6,944 KB
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ソースコード

diff #

#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using ll = long long;
struct Edge
{
    ll to;
    ll cost;
};
using Graph = vector<vector<ll>>;
using P = pair<ll, ll>;
#define mp make_pair
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define SORT(v) sort((v).begin(), (v).end())
#define RSORT(v) sort((v).rbegin(), (v).rend())
#define ALL(v) (v).begin(), v.end()
ll MOD = 998244353;
const ll nmax = 8;
const ll INF = 1e10;
const int MAX = 510000;
bool graph[nmax][nmax];
long long fac[MAX], finv[MAX], inv[MAX];
void Case(int i) { printf("Case #%d: ", i); }
void COMinit()
{
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++)
    {
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

ll COM(int n, int k)
{
    if (n < k)
        return 0;
    if (n < 0 || k < 0)
        return 0;

    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

vector<vector<ll>> dist = vector<vector<ll>>(nmax, vector<ll>(nmax, INF));
void warshall_floyd(ll n)
{
    for (size_t i = 0; i < n; i++)
    {
        for (size_t j = 0; j < n; j++)
        {
            for (size_t k = 0; k < n; k++)
            {
                dist[j][k] = min(dist[j][k], dist[j][i] + dist[i][k]);
            }
        }
    }
}

ll gcd(ll a, ll b)
{
    if (b == 0)
        return a;
    return gcd(b, a % b);
}

ll lcm(ll a, ll b)
{
    ll g = gcd(a, b);
    return a / g * b;
}

ll mulMod(ll a, ll b)
{
    return (((a % MOD) * (b % MOD)) % MOD);
}

ll powMod(ll a, ll p)
{
    if (p == 0)
    {
        return 1;
    }
    else if (p % 2 == 0)
    {
        ll half = powMod(a, p / 2);
        return mulMod(half, half);
    }
    else
    {
        return mulMod(powMod(a, p - 1), a);
    }
}

ll ceil(ll a, ll b)
{
    return (a + b - 1) / b;
}

bool isPrime(ll N)
{
    for (int i = 2; i * i <= N; i++)
    {
        if (N % i == 0)
            return false;
    }
    return true;
}

ll cntbit(ll i)
{
    if (i == 0)
        return 0;

    ll ret = 0;
    i++;
    while (i != 0)
    {
        i = i >> 1;
        ret++;
    }
    return ret - 1;
}

ll getSize(ll a)
{
    ll ret = 0;
    while (a != 0)
    {
        ret++;
        a /= 10;
    }
    return ret;
}

vector<pair<long long, long long>> prime_factorize(long long N)
{
    vector<pair<long long, long long>> res;
    for (long long a = 2; a * a <= N; ++a)
    {
        if (N % a != 0)
            continue;
        long long ex = 0;

        while (N % a == 0)
        {
            ++ex;
            N /= a;
        }

        res.push_back({a, ex});
    }

    if (N != 1)
        res.push_back({N, 1});
    return res;
}

using mint = atcoder::modint998244353;
vector<ll> dp;

void dfs(Graph &G, int v, int p)
{
    dp[v] = 1;
    for (auto &&i : G[v])
    {
        if (i != p)
        {
            dfs(G, i, v);
            dp[v] += dp[i];
        }
    }
}
int main()
{
    ll p, q, r, K;
    cin >> p >> q >> r >> K;
    p %= 10;
    q %= 10;
    r %= 10;
    vector<ll> loop(1000, -1);
    ll now = p * 100 + q * 10 + r;
    ll cnt = 3;
    while (loop[now] == -1 && cnt < K)
    {
        loop[now] = cnt;
        ll sum = (now % 10) + (now / 100) + ((now / 10) % 10);
        sum %= 10;
        now *= 10;
        now += sum;
        now %= 1000;
        cnt++;
    }

    if (cnt == K)
    {
        cout << now % 10 << endl;
    }
    else
    {
        ll loop_cnt = cnt - loop[now];
        K -= loop[now];
        K %= loop_cnt;
        for (int i = 0; i < K; i++)
        {

            ll sum = (now % 10) + (now / 100) + ((now / 10) % 10);
            sum %= 10;
            now *= 10;
            now += sum;
            now %= 1000;
            cnt++;
        }
        cout << now % 10 << endl;
    }
    return 0;
}
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