結果
| 問題 |
No.1612 I hate Construct a Palindrome
|
| コンテスト | |
| ユーザー |
SSRS
|
| 提出日時 | 2021-07-21 22:05:34 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 2,310 bytes |
| コンパイル時間 | 9,165 ms |
| コンパイル使用メモリ | 190,240 KB |
| 実行使用メモリ | 58,808 KB |
| 最終ジャッジ日時 | 2024-07-17 18:37:35 |
| 合計ジャッジ時間 | 7,635 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 32 WA * 4 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
int main(){
int N, M;
cin >> N >> M;
vector<vector<tuple<char, int, int>>> E(N);
for (int i = 0; i < M; i++){
int A, B;
char C;
cin >> A >> B >> C;
A--;
B--;
E[A].push_back(make_tuple(C, i, B));
E[B].push_back(make_tuple(C, i, A));
}
vector<vector<int>> d(27, vector<int>(N, -1));
vector<vector<int>> pv(27, vector<int>(N, -1));
vector<vector<int>> pe(27, vector<int>(N, -1));
vector<vector<int>> ps(27, vector<int>(N, -1));
vector<vector<char>> pc(27, vector<char>(N, -1));
queue<pair<int, int>> Q;
for (int i = 0; i < 26; i++){
d[i][0] = 0;
Q.push(make_pair(i, 0));
}
while (!Q.empty()){
int s = Q.front().first;
int v = Q.front().second;
Q.pop();
for (auto e : E[v]){
char c = get<0>(e);
if (!(v == 0 && s != c - 'a')){
int w = get<2>(e);
int s2 = s;
if (s != c - 'a'){
s2 = 26;
}
if (d[s2][w] == -1){
d[s2][w] = d[s][v] + 1;
pv[s2][w] = v;
pe[s2][w] = get<1>(e);
ps[s2][w] = s;
pc[s2][w] = c;
Q.push(make_pair(s2, w));
}
}
}
}
if (d[26][N - 1] == -1){
cout << -1 << endl;
} else {
string S;
vector<int> ans;
int c = N - 1;
int s = 26;
while (c != 0 || s == 26){
S += pc[s][c];
ans.push_back(pe[s][c]);
int c2 = pv[s][c];
int s2 = ps[s][c];
c = c2;
s = s2;
}
reverse(S.begin(), S.end());
reverse(ans.begin(), ans.end());
vector<int> F(26, 0);
int L = S.size();
for (int i = 0; i < L; i++){
F[S[i] - 'a']++;
}
int C = 0;
for (int i = 0; i < 26; i++){
if (F[i] > 0){
C++;
}
}
assert(C >= 2);
string S2 = S;
reverse(S2.begin(), S2.end());
if (S == S2){
while (S.size() + 2 <= N * 2){
char ch = pc[26][N - 1];
S += ch;
S += ch;
ans.push_back(pe[26][N - 1]);
ans.push_back(pe[26][N - 1]);
}
S2 = S;
reverse(S2.begin(), S2.end());
}
if (S == S2){
cout << -1 << endl;
} else {
int k = ans.size();
cout << k << endl;
for (int i = 0; i < k; i++){
cout << ans[i] + 1 << endl;
}
}
}
}
SSRS