結果

問題 No.1630 Sorting Integers (Greater than K)
ユーザー tanimani364
提出日時 2021-07-30 22:40:19
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 9 ms / 2,000 ms
コード長 4,970 bytes
コンパイル時間 2,106 ms
コンパイル使用メモリ 197,364 KB
最終ジャッジ日時 2025-01-23 12:21:09
ジャッジサーバーID
(参考情報)
judge5 / judge4
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 5
other AC * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
//#include<boost/multiprecision/cpp_int.hpp>
//#include<boost/multiprecision/cpp_dec_float.hpp>
//#include <atcoder/all>
using namespace std;
#define rep(i, a) for (int i = (int)0; i < (int)a; ++i)
#define rrep(i, a) for (int i = (int)a; i > -1; --i)
#define REP(i, a, b) for (int i = (int)a; i < (int)b; ++i)
#define RREP(i, a, b) for (int i = (int)a; i > b; --i)
#define repl(i, a) for (ll i = (ll)0; i < (ll)a; ++i)
#define pb push_back
#define eb emplace_back
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define popcount __builtin_popcount
#define popcountll __builtin_popcountll
#define fi first
#define se second
using ll = long long;
constexpr ll mod = 1e9 + 7;
constexpr ll mod_998244353 = 998244353;
constexpr ll INF = 1LL << 60;
// #pragma GCC target("avx2")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")
// using lll=boost::multiprecision::cpp_int;
// using
// Double=boost::multiprecision::number<boost::multiprecision::cpp_dec_float<128>>;//1024
template <class T>
inline bool chmin(T &a, T b)
{
if (a > b)
{
a = b;
return true;
}
return false;
}
template <class T>
inline bool chmax(T &a, T b)
{
if (a < b)
{
a = b;
return true;
}
return false;
}
ll mypow(ll x, ll n, const ll &p = -1)
{ // x^nmod
if (p != -1)
{
x = (x % p + p) % p;
}
ll ret = 1;
while (n > 0)
{
if (n & 1)
{
if (p != -1)
ret = (ret * x) % p;
else
ret *= x;
}
if (p != -1)
x = (x * x) % p;
else
x *= x;
n >>= 1;
}
return ret;
}
struct myrand{
random_device seed;
mt19937 mt;
myrand():mt(seed()){}
int operator()(int a,int b){//[a,b)
uniform_int_distribution<int>dist(a,b-1);
return dist(mt);
}
};
//using namespace atcoder;
//------------------------
//------------------------
//------------------------
//------------------------
//------------------------
template<int mod>
struct Modint{
int x;
Modint():x(0){}
Modint(int64_t y):x((y%mod+mod)%mod){}
Modint &operator+=(const Modint &p){
if((x+=p.x)>=mod)
x -= mod;
return *this;
}
Modint &operator-=(const Modint &p){
if((x+=mod-p.x)>=mod)
x -= mod;
return *this;
}
Modint &operator*=(const Modint &p){
x = (1LL * x * p.x) % mod;
return *this;
}
Modint &operator/=(const Modint &p){
*this *= p.inverse();
return *this;
}
Modint operator-() const { return Modint(-x); }
Modint operator+(const Modint &p) const{
return Modint(*this) += p;
}
Modint operator-(const Modint &p) const{
return Modint(*this) -= p;
}
Modint operator*(const Modint &p) const{
return Modint(*this) *= p;
}
Modint operator/(const Modint &p) const{
return Modint(*this) /= p;
}
bool operator==(const Modint &p) const { return x == p.x; }
bool operator!=(const Modint &p) const{return x != p.x;}
Modint inverse() const{//
int a = x, b = mod, u = 1, v = 0;
while(b>0){
int t = a / b;
swap(a -= t * b, b);
swap(u -= t * v, v);
}
return Modint(u);
}
Modint pow(int64_t n) const{//
Modint ret(1), mul(x);
while(n>0){
if(n&1)
ret *= mul;
mul *= mul;
n >>= 1;
}
return ret;
}
friend ostream &operator<<(ostream &os,const Modint &p){
return os << p.x;
}
};
using modint = Modint<mod>;
using modint2= Modint<mod_998244353>;
void solve()
{
ll n;
string k;
cin>>n>>k;
string ans;
ll c[9];
rep(i,9)cin>>c[i];
int m=k.size();
int pos=m-1;
while(pos>=0&&k[pos]=='9'){
k[pos]='0';
pos--;
}
if(pos==-1){
k="1"+k;
++m;
}else{
k[pos]++;
}
if(n>m){
rep(i,9){
while(c[i]>0)ans+=char('1'+i),c[i]--;
}
cout<<ans<<"\n";
return;
}else if(n<m){
cout<<-1<<"\n";
return;
}
rep(i,m){
if(k[i]=='0'){
rep(j,9){
if(c[j]>0){
ans+=char('1'+j);
c[j]--;
break;
}
}
break;
}
else if(c[k[i]-'1']>0)ans+=k[i],c[k[i]-'1']--;
else{
bool ok=false;
for(int j=k[i]-'1';j<9;++j){
if(c[j]>0){
c[j]--;
ans+=char('1'+j);
ok=true;
break;
}
}
if(!ok){
for(int j=i-1;j>=0;--j){
for(int k=ans[j]-'0';k<9;++k){
if(c[k]>0){
c[ans[j]-'1']++;
c[k]--;
ans[j]=char('1'+k);
ok=true;
break;
}
}
if(ok)break;
c[ans[j]-'1']++;
ans.pop_back();
}
}if(!ok){
cout<<-1<<"\n";
return;
}else break;
}
}
rep(i,9){
while(c[i]>0)ans+=char('1'+i),c[i]--;
}
cout<<ans<<"\n";
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout << fixed << setprecision(15);
solve();
return 0;
}
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