結果
問題 | No.332 数列をプレゼントに |
ユーザー |
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提出日時 | 2015-12-25 00:41:03 |
言語 | C++11(廃止可能性あり) (gcc 13.3.0) |
結果 |
AC
|
実行時間 | 185 ms / 2,000 ms |
コード長 | 2,028 bytes |
コンパイル時間 | 878 ms |
コンパイル使用メモリ | 89,268 KB |
実行使用メモリ | 83,712 KB |
最終ジャッジ日時 | 2024-12-24 07:26:19 |
合計ジャッジ時間 | 8,047 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 5 |
other | AC * 42 |
コンパイルメッセージ
main.cpp: In function ‘int main()’: main.cpp:53:8: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 53 | scanf("%d%lld",&n,&x); | ~~~~~^~~~~~~~~~~~~~~~ main.cpp:54:17: warning: ignoring return value of ‘int scanf(const char*, ...)’ declared with attribute ‘warn_unused_result’ [-Wunused-result] 54 | rep(i,n) scanf("%d",&a[i]), id[i] = i; | ~~~~~^~~~~~~~~~~~
ソースコード
#include <cstdio>#include <algorithm>#include <stack>#include <queue>#include <deque>#include <vector>#include <string>#include <string.h>#include <cstdlib>#include <ctime>#include <cmath>#include <map>#include <set>#include <iostream>#include <sstream>#include <numeric>#include <cctype>#include <bitset>#define fi first#define se second#define rep(i,n) for(int i = 0; i < (n); ++i)#define rrep(i,n) for(int i = 1; i <= (n); ++i)#define drep(i,n) for(int i = (n)-1; i >= 0; --i)#define gep(i,g,j) for(int i = g.head[j]; i != -1; i = g.e[i].next)#define each(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++)#define rng(a) a.begin(),a.end()#define maxs(x,y) x = max(x,y)#define mins(x,y) x = min(x,y)#define pb push_back#define sz(x) (int)(x).size()#define pcnt __builtin_popcount#define snuke srand((unsigned)clock()+(unsigned)time(NULL));#define df(x) int x = in()using namespace std;typedef long long int ll;typedef pair<int,int> P;typedef vector<int> vi;typedef vector<vi> vvi;inline int in() { int x; scanf("%d",&x); return x;}inline void priv(vi a) { rep(i,sz(a)) printf("%d%c",a[i],i==sz(a)-1?'\n':' ');}const int MX = 105, MY = 8000005, INF = 1000010000;const ll LINF = 1000000000000000000ll;const double eps = 1e-10;int n;ll x;int a[MX], id[MX];bitset<MY> dp[81];map<int,int> mp;int main() {scanf("%d%lld",&n,&x);rep(i,n) scanf("%d",&a[i]), id[i] = i;sort(id,id+n,[&](int x, int y){return a[x]<a[y];});int m = min(20,n);vi s;rep(i,m) s.pb(id[n-i-1]);n -= m;dp[0][0] = true;rep(i,n) dp[i+1] = dp[i]<<a[id[i]]|dp[i];rep(i,1<<m) {ll sum = 0;rep(j,m) if (i>>j&1) sum += a[s[j]];ll r = x-sum;if (0 <= r && r <= MY && dp[n][r]) {string ans = string(n+m,'x');rep(j,m) if (i>>j&1) ans[s[j]] = 'o';drep(j,n) {int na = a[id[j]];if (na <= r && dp[j][r-na]) ans[id[j]] = 'o', r -= na;}cout<<ans<<endl;return 0;}}puts("No");return 0;}