結果

問題 No.1634 Sorting Integers (Multiple of K) Hard
ユーザー karinohito
提出日時 2021-07-30 22:58:03
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,054 ms / 3,000 ms
コード長 1,990 bytes
コンパイル時間 2,337 ms
コンパイル使用メモリ 194,972 KB
実行使用メモリ 5,376 KB
最終ジャッジ日時 2024-09-16 02:50:16
合計ジャッジ時間 21,319 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 28
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

//#include <atcoder/all>
#include <bits/stdc++.h>
using namespace std;
//using namespace atcoder;
using ll = long long;
#define all(A) A.begin(),A.end()
using vll = vector<ll>;
#define rep(i, n) for (long long i = 0; i < (long long)(n); i++)
using Graph = vector<vector<ll>>;
vector<vll> BOX;
//max C size
void next_combination(ll size, ll max, vll now_vector) {
ll now_size = now_vector.size();
if (now_size == size) {
BOX.push_back(now_vector);
}
else {
vll next = now_vector;
if (now_size == 0) {
for (ll i = 0; i < max; i++) {
next.push_back(i);
next_combination(size, max, next);
next.pop_back();
}
}
else {
ll LAST = next[now_size - 1];
for (ll i = LAST + 1; i < max; i++) {
next.push_back(i);
next_combination(size, max, next);
next.pop_back();
}
}
}
return;
}
int main() {
ll N, K;
cin >> N >> K;
vll C(9);
vll D;
vll per(15, 1);
rep(i, 14) {
per[i + 1] = per[i] * (i + 1);
}
ll PPP = 1;
rep(i, 9) {
cin >> C[i];
PPP *= per[C[i]];
rep(j, C[i])D.push_back(i + 1);
}
ll pp = 1;
rep(i, N / 2) {
pp *= 10;
}
next_combination(N / 2, N, {});
ll an = 0;
set<vll> Poo;
rep(i, BOX.size()) {
map<ll, ll> M1;
map<ll, ll> M2;
vll AUU = BOX[i];
vll AU;
set<ll> S;
rep(k, AUU.size()) {
S.insert(AUU[k]);
AU.push_back(D[AUU[k]]);
}
if (Poo.count(AU))continue;
Poo.insert(AU);
vll BU;
rep(k, N) {
if (!S.count(k))BU.push_back(D[k]);
}
ll kk = 1;
do {
kk = 1;
ll x = 0;
rep(u, AU.size()) {
x += AU[u] * kk;
kk *= 10;
kk %= K;
x %= K;
}
M1[x]++;
} while (next_permutation(all(AU)));
ll pp = kk;
do {
kk = pp;
ll x = 0;
rep(u, BU.size()) {
x += BU[u] * kk;
kk *= 10;
kk %= K;
x %= K;
}
if (x == 0)x += K;
M2[x]++;
} while (next_permutation(all(BU)));
for (auto w : M1) {
if (M2.count(K - w.first)) {
an += w.second * M2[K - w.first];
}
}
}
cout << an << endl;
}
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