結果

問題 No.1677 mæx
ユーザー stoqstoq
提出日時 2021-08-01 07:35:12
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 8 ms / 2,000 ms
コード長 5,889 bytes
コンパイル時間 2,428 ms
コンパイル使用メモリ 205,584 KB
実行使用メモリ 8,012 KB
最終ジャッジ日時 2024-06-11 21:29:57
合計ジャッジ時間 3,566 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,376 KB
testcase_02 AC 2 ms
5,376 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 6 ms
6,632 KB
testcase_05 AC 7 ms
6,656 KB
testcase_06 AC 6 ms
6,528 KB
testcase_07 AC 6 ms
6,628 KB
testcase_08 AC 7 ms
6,652 KB
testcase_09 AC 6 ms
6,784 KB
testcase_10 AC 6 ms
6,512 KB
testcase_11 AC 6 ms
6,912 KB
testcase_12 AC 7 ms
6,528 KB
testcase_13 AC 6 ms
6,620 KB
testcase_14 AC 7 ms
6,912 KB
testcase_15 AC 6 ms
6,784 KB
testcase_16 AC 6 ms
6,528 KB
testcase_17 AC 7 ms
6,648 KB
testcase_18 AC 6 ms
6,784 KB
testcase_19 AC 2 ms
5,376 KB
testcase_20 AC 2 ms
5,376 KB
testcase_21 AC 8 ms
8,012 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#define MOD_TYPE 2

#pragma region Macros

#include <bits/stdc++.h>
using namespace std;

#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif

#if 0
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
#include <ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
template <typename T>
using extset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#endif

#if 0
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename T>
using smaller_queue = priority_queue<T, vector<T>, greater<T>>;

constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353);
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr ld PI = acos(-1.0);
constexpr ld EPS = 1e-7;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};

#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";

struct io_init
{
  io_init()
  {
    cin.tie(0);
    ios::sync_with_stdio(false);
    cout << setprecision(30) << setiosflags(ios::fixed);
  };
} io_init;
template <typename T>
inline bool chmin(T &a, T b)
{
  if (a > b)
  {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
inline bool chmax(T &a, T b)
{
  if (a < b)
  {
    a = b;
    return true;
  }
  return false;
}
inline ll CEIL(ll a, ll b)
{
  return (a + b - 1) / b;
}
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T &val)
{
  fill((T *)array, (T *)(array + N), val);
}
template <typename T, typename U>
constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept
{
  is >> p.first >> p.second;
  return is;
}
template <typename T, typename U>
constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept
{
  os << p.first << " " << p.second;
  return os;
}
#pragma endregion

random_device seed_gen;
mt19937_64 engine(seed_gen());

// --------------------------------------

#pragma region mint
template <int MOD>
struct Fp
{
  long long val;

  constexpr Fp(long long v = 0) noexcept : val(v % MOD)
  {
    if (val < 0)
      v += MOD;
  }

  constexpr int getmod()
  {
    return MOD;
  }

  constexpr Fp operator-() const noexcept
  {
    return val ? MOD - val : 0;
  }

  constexpr Fp operator+(const Fp &r) const noexcept
  {
    return Fp(*this) += r;
  }

  constexpr Fp operator-(const Fp &r) const noexcept
  {
    return Fp(*this) -= r;
  }

  constexpr Fp operator*(const Fp &r) const noexcept
  {
    return Fp(*this) *= r;
  }

  constexpr Fp operator/(const Fp &r) const noexcept
  {
    return Fp(*this) /= r;
  }

  constexpr Fp &operator+=(const Fp &r) noexcept
  {
    val += r.val;
    if (val >= MOD)
      val -= MOD;
    return *this;
  }

  constexpr Fp &operator-=(const Fp &r) noexcept
  {
    val -= r.val;
    if (val < 0)
      val += MOD;
    return *this;
  }

  constexpr Fp &operator*=(const Fp &r) noexcept
  {
    val = val * r.val % MOD;
    if (val < 0)
      val += MOD;
    return *this;
  }

  constexpr Fp &operator/=(const Fp &r) noexcept
  {
    long long a = r.val, b = MOD, u = 1, v = 0;
    while (b)
    {
      long long t = a / b;
      a -= t * b;
      swap(a, b);
      u -= t * v;
      swap(u, v);
    }
    val = val * u % MOD;
    if (val < 0)
      val += MOD;
    return *this;
  }

  constexpr bool operator==(const Fp &r) const noexcept
  {
    return this->val == r.val;
  }

  constexpr bool operator!=(const Fp &r) const noexcept
  {
    return this->val != r.val;
  }

  friend constexpr ostream &operator<<(ostream &os, const Fp<MOD> &x) noexcept
  {
    return os << x.val;
  }

  friend constexpr istream &operator>>(istream &is, Fp<MOD> &x) noexcept
  {
    return is >> x.val;
  }
};

Fp<MOD> modpow(const Fp<MOD> &a, long long n) noexcept
{
  if (n == 0)
    return 1;
  auto t = modpow(a, n / 2);
  t = t * t;
  if (n & 1)
    t = t * a;
  return t;
}

using mint = Fp<MOD>;
#pragma endregion

int mex[3][3];

array<mint, 3> f(int &i, string &s)
{
  if (s[i] != 'm')
  {
    array<mint, 3> res;
    if (isdigit(s[i]))
      res[s[i] - '0'] = 1;
    else
      res[0] = res[1] = res[2] = 1;
    i++;
    return res;
  }
  assert(s[i++] == 'm');
  int type; // 1:max 2:mex 3:m?x
  if (s[i] == 'a')
    type = 1;
  else if (s[i] == 'e')
    type = 2;
  else
    type = 3;
  i++;
  assert(s[i++] == 'x');
  assert(s[i++] == '(');
  array<mint, 3> a = f(i, s);
  assert(s[i++] == ',');
  array<mint, 3> b = f(i, s);
  assert(s[i++] == ')');

  array<mint, 3> res;
  // max
  if (type & 1)
  {
    rep(i, 3) rep(j, 3)
    {
      res[max(i, j)] += a[i] * b[j];
    }
  }
  // mex
  if (type & 2)
  {
    rep(i, 3) rep(j, 3)
    {
      res[mex[i][j]] += a[i] * b[j];
    }
  }
  return res;
}

void solve()
{
  mex[0][0] = 1, mex[0][1] = 2, mex[0][2] = 1;
  mex[1][0] = 2, mex[1][1] = 0, mex[1][2] = 0;
  mex[2][0] = 1, mex[2][1] = 0, mex[2][2] = 0;
  string s;
  int k;
  cin >> s >> k;
  int i = 0;
  array<mint, 3> a = f(i, s);
  cout << a[k] << "\n";
}

int main()
{
  solve();
}
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