結果
問題 | No.1717 Levi-Civita Triangle |
ユーザー | zkou |
提出日時 | 2021-08-04 16:58:00 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 127 ms / 2,000 ms |
コード長 | 2,002 bytes |
コンパイル時間 | 381 ms |
コンパイル使用メモリ | 82,132 KB |
実行使用メモリ | 104,064 KB |
最終ジャッジ日時 | 2024-09-23 03:44:32 |
合計ジャッジ時間 | 4,532 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 42 |
ソースコード
# 想定解 def solve(N, As): assert len(As) == 2 * N + 1 def LeviCivitaSymbol(i, j, k): if (i, j, k) in ((0, 1, 2), (1, 2, 0), (2, 0, 1)): return 1 elif (i, j, k) in ((2, 1, 0), (1, 0, 2), (0, 2, 1)): return 2 else: return 0 As = [LeviCivitaSymbol(As[i], As[i + 1], As[i + 2]) for i in range(len(As) - 2)] As.reverse() ans_one = ([1, 0, 2, 0] * ((len(As) + 3) // 4))[:len(As)] ans_two = ([2, 0, 1, 0] * ((len(As) + 3) // 4))[:len(As)] if As == ans_one: return 1 elif As == ans_two: return 2 else: return 0 def slow(N, As): assert len(As) == 2 * N + 1 def LeviCivitaSymbol(i, j, k): if (i, j, k) in ((0, 1, 2), (1, 2, 0), (2, 0, 1)): return 1 elif (i, j, k) in ((2, 1, 0), (1, 0, 2), (0, 2, 1)): return 2 else: return 0 for _ in range(N): As = [LeviCivitaSymbol(As[i], As[i + 1], As[i + 2]) for i in range(len(As) - 2)] assert len(As) == 1 return As[0] def test1(t): import random for _ in range(t): N = random.randint(1, 100) As = [random.randint(0, 2) for _ in range(2 * N + 1)] ans_slow = slow(N, As.copy()) ans_solve = solve(N, As.copy()) # print(ans_slow, ans_solve, As) assert ans_slow == ans_solve print("test1 passed") def test2(Nmax): from itertools import permutations for N in range(1, Nmax + 1): for As in permutations(range(3), 2 * N + 1): As = list(As) ans_slow = slow(N, As.copy()) ans_solve = solve(N, As.copy()) # print(ans_slow, ans_solve, As) assert ans_slow == ans_solve print("test2 passed") def main(): #""" N = int(input()) As = list(map(int, input().split())) """ import random N = 5 * 10 ** 5 As = [random.randint(0, 2) for _ in range(2 * N + 1)] #""" print(solve(N, As)) main()