結果
| 問題 |
No.1717 Levi-Civita Triangle
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-08-04 21:54:50 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,094 bytes |
| コンパイル時間 | 1,624 ms |
| コンパイル使用メモリ | 173,348 KB |
| 実行使用メモリ | 10,624 KB |
| 最終ジャッジ日時 | 2024-09-23 03:45:05 |
| 合計ジャッジ時間 | 6,010 ms |
|
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 4 TLE * 1 -- * 37 |
ソースコード
// 高速化愚直解 想定 TLE
#include <bits/stdc++.h>
using namespace std;
int main(){
int N;
scanf("%d", &N);
bitset<200010> bit_0, bit_1, bit_2;
int a;
for (int i = 0; i < 2 * N + 1; i++) {
scanf("%d", &a);
// cout << a << endl;
if (a == 0) {
bit_0.set(i);
} else if (a == 1) {
bit_1.set(i);
} else {
bit_2.set(i);
}
}
// cout << -1 << " 0 " << bit_0.any() << endl;
// cout << -1 << " 1 " << bit_1.any() << endl;
// cout << -1 << " 2 " << bit_2.any() << endl;
for (int i = 0; i < N; i++) {
bitset<200010> new_bit_0, new_bit_1, new_bit_2;
bitset<200010> bit_01 = bit_0 & (bit_1 >> 1);
new_bit_1 |= bit_01 & (bit_2 >> 2);
new_bit_1 |= bit_1 & (bit_2 >> 1) & (bit_0 >> 2);
new_bit_1 |= bit_2 & (bit_01 >> 1);
bitset<200010> bit_10 = bit_1 & (bit_0 >> 1);
new_bit_2 |= bit_0 & (bit_2 >> 1) & (bit_1 >> 2);
new_bit_2 |= bit_2 & (bit_10 >> 1);
new_bit_2 |= bit_10 & (bit_2 >> 2);
bit_1 = new_bit_1;
bit_2 = new_bit_2;
bit_0 = (bit_1 ^ bit_2).flip();
// cout << i << " 0 " << bit_0.any() << endl;
// cout << i << " 1 " << bit_1.any() << endl;
// cout << i << " 2 " << bit_2.any() << endl;
}
if (bit_1.any()) putchar('1');
else if (bit_2.any()) putchar('2');
else putchar('0');
return 0;
}
// for i in range(N):
// l = 2 * (N - i) - 1
// bit_10 = bit_1 & (bit_0 >> 1)
// new_bit_1 = 0
// new_bit_1 |= bit_0 & (bit_2 >> 1) & (bit_1 >> 2)
// new_bit_1 |= bit_2 & (bit_10 >> 1)
// new_bit_1 |= bit_10 & (bit_2 >> 2)
// bit_01 = bit_0 & (bit_1 >> 1)
// new_bit_2 = 0
// new_bit_2 |= bit_01 & (bit_2 >> 2)
// new_bit_2 |= bit_1 & (bit_2 >> 1) & (bit_0 >> 2)
// new_bit_2 |= bit_2 & (bit_01 >> 1)
// bit_1 = new_bit_1
// bit_2 = new_bit_2
// bit_0 = (-1) ^ bit_1 ^ bit_2
// if bit_1:
// print(1)
// elif bit_2:
// print(2)
// else:
// print(0)