結果

問題 No.1638 Robot Maze
ユーザー kimiyuki
提出日時 2021-08-06 21:35:21
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
WA  
実行時間 -
コード長 1,999 bytes
コンパイル時間 2,242 ms
コンパイル使用メモリ 207,592 KB
最終ジャッジ日時 2025-01-23 14:46:31
ジャッジサーバーID
（参考情報） 		judge4 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 36 WA * 13
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#define REP(i, n) for (int i = 0; (i) < (int)(n); ++(i))
#define REP3(i, m, n) for (int i = (m); (i) < (int)(n); ++(i))
#define REP_R(i, n) for (int i = (int)(n)-1; (i) >= 0; --(i))
#define REP3R(i, m, n) for (int i = (int)(n)-1; (i) >= (int)(m); --(i))
#define ALL(x) ::std::begin(x), ::std::end(x)
using namespace std;
template <class T> using reversed_priority_queue = priority_queue<T, vector<T>, greater<T> >;
// generated by oj-template v4.8.0 (https://github.com/online-judge-tools/template-generator)
const std::string YES = "Yes";
const std::string NO = "No";
int main() {
    // input
    int h, w, up, down, left, right;
    int64_t k, p;
    cin >> h >> w >> up >> down >> left >> right >> k >> p;
    int sx, sy, tx, ty;
    cin >> sx >> sy >> tx >> ty;
    -- sx;
    -- sy;
    -- tx;
    -- ty;
    vector<string> c(h);
    REP (y, h) { cin >> c[y]; }
    // solve
    vector<vector<int64_t>> dist(h, vector<int64_t>(w, INT64_MAX));
    reversed_priority_queue<tuple<int64_t, int, int>> que;
    dist[sy][sx] = 0;
    que.emplace(0, sy, sx);
    while (not que.empty()) {
        auto [dist_y_x, y, x] = que.top();
        que.pop();
        if (dist_y_x > dist[y][x]) {
            continue;
        }
        REP (i, 4) {
            const int dy[4] = {-1, 1, 0, 0};
            const int dx[4] = {0, 0, 1, -1};
            int ny = y + dy[i];
            int nx = x + dx[i];
            if (0 <= ny and ny < h and 0 <= nx and nx < w) {
                if (c[ny][nx] == '#') {
                    continue;
                }
                const int cost[4] = {up, down, right, left};
                int64_t ndist = dist[y][x] + cost[i] + (c[ny][nx] == '@' ? p : 0);
                if (ndist < dist[ny][nx]) {
                    dist[ny][nx] = ndist;
                    que.emplace(ndist, ny, nx);
                }
            }
        }
    }
    bool ans = dist[ty][tx] <= k;
    // output
    cout << (ans ? YES : NO) << '\n';
    return 0;
}
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