結果
| 問題 |
No.1638 Robot Maze
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2021-08-06 21:43:30 |
| 言語 | Lua (LuaJit 2.1.1734355927) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 3,018 bytes |
| コンパイル時間 | 99 ms |
| コンパイル使用メモリ | 6,688 KB |
| 実行使用メモリ | 6,948 KB |
| 最終ジャッジ日時 | 2024-09-17 01:36:01 |
| 合計ジャッジ時間 | 1,725 ms |
|
ジャッジサーバーID (参考情報) |
judge6 / judge2 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 41 WA * 8 |
ソースコード
local mfl, mce = math.floor, math.ceil
local mmi, mma = math.min, math.max
local pow2 = {1}
for i = 2, 28 do pow2[i] = pow2[i - 1] * 2 end
local SegTree = {}
SegTree.updateAll = function(self)
for i = self.stagenum - 1, 1, -1 do
local cnt = pow2[i]
for j = 0, cnt - 1 do
self.stage[cnt + j] = self.func(self.stage[(cnt + j) * 2], self.stage[(cnt + j) * 2 + 1])
end
end
end
SegTree.create = function(self, n, func, emptyvalue)
self.func, self.emptyvalue = func, emptyvalue
local stagenum, mul = 1, 1
self.stage = {} -- use 1D Tree (stage[], not stage[][])
while mul < n do
mul, stagenum = mul * 2, stagenum + 1
end
self.stagenum = stagenum
for i = 1, mul * 2 - 1 do self.stage[i] = emptyvalue end
for i = 1, n do self.stage[mul + i - 1] = i end
self:updateAll()
end
SegTree.update = function(self, idx, force)
idx = idx + pow2[self.stagenum] - 1
for i = self.stagenum - 1, 1, -1 do
local dst = mfl(idx / 2)
local rem = dst * 4 + 1 - idx
self.stage[dst] = self.func(self.stage[idx], self.stage[rem])
if not force and self.stage[dst] ~= self.stage[idx] then break end
idx = dst
end
end
SegTree.new = function(n, func, emptyvalue)
local obj = {}
setmetatable(obj, {__index = SegTree})
obj:create(n, func, emptyvalue)
return obj
end
local h, w = io.read("*n", "*n")
assert(1 < h and 1 < w)
local c_up, c_down, c_right, c_left = io.read("*n", "*n", "*n", "*n")
local klim, p = io.read("*n", "*n")
local xs, ys = io.read("*n", "*n")
local xt, yt = io.read("*n", "*n", "*l")
local map = {}
for i = 1, h do
local s = io.read()
map[i] = {}
for j = 1, w do
map[i][j] = s:sub(j, j)
end
end
local n = h * w
local inf = klim + 1
local len = {}
local asked = {}
for i = 1, n do
len[i] = inf
asked[i] = false
end
local spos = (xs - 1) * w + ys
len[1] = 0
asked[n + 1] = true
local function mergefunc(x, y)
if asked[x] then return y
elseif asked[y] then return x
else
return len[x] < len[y] and x or y
end
end
local st = SegTree.new(n, mergefunc, n + 1)
local function walk(src, dst)
local dst_row = mce(dst / w)
local dst_col = dst - (dst_row - 1) * w
local cost = 0
if src + 1 == dst then cost = c_right
elseif src - 1 == dst then cost = c_left
elseif src + w == dst then cost = c_down
elseif src - w == dst then cost = c_up
else
assert(false)
end
-- print(dst_row, dst_col)
if map[dst_row][dst_col] == "#" then return end
if map[dst_row][dst_col] == "@" then cost = cost + p end
if len[src] + cost < len[dst] then
len[dst] = len[src] + cost
st:update(dst)
end
end
for i = 1, n do
local src = st.stage[1]
if asked[src] then break end
if inf <= len[src] then break end
asked[src] = true
st:update(src, true)
if src % w ~= 1 then walk(src, src - 1) end
if src % w ~= 0 then walk(src, src + 1) end
if w < src then walk(src, src - w) end
if src <= (h - 1) * w then walk(src, src + w) end
end
local tpos = (xt - 1) * w + yt
print(len[tpos] <= klim and "Yes" or "No")