結果
| 問題 |
No.1639 最小通信路
|
| コンテスト | |
| ユーザー |
stoq
|
| 提出日時 | 2021-08-06 21:44:08 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
RE
|
| 実行時間 | - |
| コード長 | 4,334 bytes |
| コンパイル時間 | 9,169 ms |
| コンパイル使用メモリ | 547,680 KB |
| 最終ジャッジ日時 | 2025-01-23 14:57:24 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge6 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 32 RE * 11 |
ソースコード
#define MOD_TYPE 1
#pragma region Macros
#include <bits/stdc++.h>
using namespace std;
#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif
#if 0
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/tag_and_trait.hpp>
#include <ext/rope>
using namespace __gnu_pbds;
using namespace __gnu_cxx;
template <typename T>
using extset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#endif
#if 1
#include <boost/multiprecision/cpp_int.hpp>
#include <boost/multiprecision/cpp_dec_float.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif
using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename T>
using smaller_queue = priority_queue<T, vector<T>, greater<T>>;
constexpr ll MOD = (MOD_TYPE == 1 ? (ll)(1e9 + 7) : 998244353);
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr ld PI = acos(-1.0);
constexpr ld EPS = 1e-7;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};
#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";
struct io_init
{
io_init()
{
cin.tie(0);
ios::sync_with_stdio(false);
cout << setprecision(30) << setiosflags(ios::fixed);
};
} io_init;
template <typename T>
inline bool chmin(T &a, T b)
{
if (a > b)
{
a = b;
return true;
}
return false;
}
template <typename T>
inline bool chmax(T &a, T b)
{
if (a < b)
{
a = b;
return true;
}
return false;
}
inline ll CEIL(ll a, ll b)
{
return (a + b - 1) / b;
}
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T &val)
{
fill((T *)array, (T *)(array + N), val);
}
template <typename T, typename U>
constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept
{
is >> p.first >> p.second;
return is;
}
template <typename T, typename U>
constexpr ostream &operator<<(ostream &os, pair<T, U> &p) noexcept
{
os << p.first << " " << p.second;
return os;
}
#pragma endregion
random_device seed_gen;
mt19937_64 engine(seed_gen());
// --------------------------------------
struct UnionFind
{
vector<int> par, rank_;
UnionFind() {}
UnionFind(int n) : par(n), rank_(n, 0) { iota(begin(par), end(par), 0); }
int root(int x) { return par[x] == x ? x : par[x] = root(par[x]); }
bool same(int x, int y) { return root(x) == root(y); }
void unite(int x, int y)
{
x = root(x);
y = root(y);
if (x == y)
return;
if (rank_[x] < rank_[y])
{
par[x] = y;
}
else
{
par[y] = x;
if (rank_[x] == rank_[y])
rank_[x]++;
}
}
};
template <typename T>
struct kruskal
{
UnionFind uf;
kruskal(int n = 200010) : uf(n) {}
struct edge
{
int u, v;
T cost;
int num;
};
vector<edge> E;
set<int> used_num;
void add_E(int s, int t, T w, int i) { E.push_back({s, t, w, i}); }
T calc()
{
sort(E.begin(), E.end(), [](edge &e1, edge &e2)
{ return e1.cost < e2.cost; });
T res = 0;
for (auto e : E)
{
if (!uf.same(e.u, e.v))
{
uf.unite(e.u, e.v);
res += e.cost;
used_num.insert(e.num);
}
}
return res;
}
bool used(int i) { return used_num.count(i); }
};
void solve()
{
int n;
cin >> n;
int m = n * (n - 1) / 2;
vector<int> a(m), b(m);
vector<Int> c(m);
kruskal<Int> ks(n);
repi(i, m)
{
cin >> a[i] >> b[i] >> c[i];
ks.E.push_back({a[i], b[i], c[i], i});
}
ks.calc();
Int ans = 0;
for (auto i : ks.used_num)
{
chmax(ans, c[i]);
}
cout << ans << "\n";
}
int main()
{
solve();
}
stoq