結果
| 問題 | No.1640 簡単な色塗り |
| コンテスト | |
| ユーザー |
mkawa2
|
| 提出日時 | 2021-08-07 00:18:54 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 343 ms / 2,000 ms |
| コード長 | 2,529 bytes |
| 記録 | |
| コンパイル時間 | 222 ms |
| コンパイル使用メモリ | 82,352 KB |
| 実行使用メモリ | 111,728 KB |
| 最終ジャッジ日時 | 2024-06-29 16:38:57 |
| 合計ジャッジ時間 | 18,693 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 53 |
ソースコード
import sys
# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = 10**16
# md = 998244353
md = 10**9+7
class UnionFind:
def __init__(self, n):
self.state = [-1]*n
self.e = [0]*n
self.size_table = [1]*n
# cntはグループ数
self.cnt = n
def root(self, u):
stack = []
while self.state[u] >= 0:
stack.append(u)
u = self.state[u]
for v in stack: self.state[v] = u
return u
def merge(self, u, v):
u = self.root(u)
v = self.root(v)
self.e[u] += 1
if u == v: return
du = -self.state[u]
dv = -self.state[v]
if du < dv: u, v = v, u
if du == dv: self.state[u] -= 1
self.state[v] = u
self.cnt -= 1
self.size_table[u] += self.size_table[v]
self.e[u] += self.e[v]
return
# グループの要素数
def size(self, u):
return self.size_table[self.root(u)]
def cnt_egde(self, u):
u = self.root(u)
return self.e[u]
n = II()
uf = UnionFind(n)
to = [[] for _ in range(n)]
for i in range(n):
a, b = LI1()
to[a].append((b, i))
to[b].append((a, i))
uf.merge(a, b)
fin = set()
for u in range(n):
u = uf.root(u)
if u in fin: continue
fin.add(u)
if uf.size(u) != uf.cnt_egde(u):
print("No")
exit()
def dfs(u):
stack = [(u, -1)]
while stack:
u, par = stack.pop()
for v, i in to[u]:
if v == par: continue
if vis[v]:
ans[i] = v+1
ee[i] = True
return v
vis[v] = True
stack.append((v, u))
def match(u):
stack = [u]
while stack:
u = stack.pop()
for v, i in to[u]:
if ee[i]: continue
ee[i] = True
ans[i] = v+1
stack.append(v)
ans = [-1]*n
ee = [False]*n
vis = [False]*n
for u in fin:
r = dfs(u)
match(r)
print("Yes")
print(*ans, sep="\n")
mkawa2