結果
問題 | No.1364 [Renaming] Road to Cherry from Zelkova |
ユーザー |
![]() |
提出日時 | 2021-08-08 12:43:23 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 714 ms / 2,500 ms |
コード長 | 2,045 bytes |
コンパイル時間 | 238 ms |
コンパイル使用メモリ | 82,304 KB |
実行使用メモリ | 134,400 KB |
最終ジャッジ日時 | 2024-09-19 08:18:35 |
合計ジャッジ時間 | 16,454 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
(要ログイン)
ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 45 |
ソースコード
from collections import defaultdict, deque, Counter from heapq import heappush, heappop, heapify import math import bisect import random from itertools import permutations, accumulate, combinations, product import sys import string from bisect import bisect_left, bisect_right from math import factorial, ceil, floor from operator import mul from functools import reduce import pprint sys.setrecursionlimit(10 ** 9) INF = 10 ** 20 def LI(): return list(map(int, sys.stdin.readline().split())) def I(): return int(sys.stdin.readline()) def LS(): return sys.stdin.buffer.readline().rstrip().decode('utf-8').split() def S(): return sys.stdin.buffer.readline().rstrip().decode('utf-8') def IR(n): return [I() for i in range(n)] def LIR(n): return [LI() for i in range(n)] def SR(n): return [S() for i in range(n)] def LSR(n): return [LS() for i in range(n)] def SRL(n): return [list(S()) for i in range(n)] def MSRL(n): return [[int(j) for j in list(S())] for i in range(n)] mod = 10**9+7 n,m=LI() G=[[]for _ in range(n+1)] for _ in range(m): u,v,l,a=LI() G[u]+=[(v,l,a)] def topological_sort(G): n = len(G) in_degree = [0] * n for u in range(n): for v,_,_ in G[u]: in_degree[v] += 1 topological_order = [] que = deque() for i in range(n): if in_degree[i] == 0: que += [i] while que: u = que.pop() topological_order += [u] for v,_,_ in G[u]: in_degree[v] -= 1 if in_degree[v] == 0: que += [v] return topological_order q=deque([0]) D=[0]*(n+1) D2=[0]*(n+1) D2[0]=1 D[0]=0 order=topological_sort(G) s=set() for ui in order: s.add(ui) for vi,li,ai in G[ui]: D[vi]+=(D[ui]+D2[ui]*li)*ai%mod D[vi]%=mod D2[vi]+=D2[ui]*ai D2[vi]%=mod qq=[0] D3=[0]*(n+1) D3[0]=1 while qq: uk=qq.pop() for vk,_,_ in G[uk]: if D3[vk]: continue D3[vk]=1 qq+=[vk] if not D2[n] and D3[n]: print("INF") else: print(D[n])