結果

問題 No.1711 Divide LCM
ユーザー chineristAC
提出日時 2021-08-13 04:05:16
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 596 ms / 4,000 ms
コード長 1,223 bytes
コンパイル時間 245 ms
コンパイル使用メモリ 82,700 KB
実行使用メモリ 188,184 KB
最終ジャッジ日時 2024-09-17 17:01:41
合計ジャッジ時間 14,461 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 42
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
from collections import deque
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
N = int(input())
LCM = {}
all_divisors = set()
A = [1 for i in range(N)]
for i in range(N):
m = int(input())
D = [1]
for _ in range(m):
p,e = mi()
t = pow(p,e)
A[i] *= t
D = [d for d in D] + [d*t for d in D]
if p in LCM:
LCM[p] = max(LCM[p],t)
else:
LCM[p] = t
for d in D:
all_divisors.add(d)
prime_pow = [LCM[p] for p in LCM]
n = len(prime_pow)
deq = deque([(1,-1)])
prod = -1
while deq:
v,k = deq.popleft()
for i in range(k+1,n):
if v * prime_pow[i] not in all_divisors:
prod = v * prime_pow[i]
deq = []
break
deq.append((v*prime_pow[i],i))
if prod==-1:
exit(print(-1))
selected_p = []
for i in range(n):
if prod%prime_pow[i]==0:
selected_p.append(prime_pow[i])
k = len(selected_p)
S = [[] for i in range(k)]
for a in A:
for i in range(k):
if a%selected_p[i]:
S[i].append(a)
break
print(k)
for i in range(k):
S[i] = [len(S[i])] + S[i]
print(*S[i])
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