結果
問題 | No.1649 Manhattan Square |
ユーザー | PCTprobability |
提出日時 | 2021-08-13 23:08:01 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 7,159 bytes |
コンパイル時間 | 7,757 ms |
コンパイル使用メモリ | 320,840 KB |
実行使用メモリ | 348,324 KB |
最終ジャッジ日時 | 2024-10-03 22:36:07 |
合計ジャッジ時間 | 74,586 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 24 ms
11,008 KB |
testcase_03 | AC | 24 ms
10,880 KB |
testcase_04 | AC | 24 ms
11,008 KB |
testcase_05 | AC | 24 ms
11,008 KB |
testcase_06 | AC | 23 ms
10,880 KB |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | WA | - |
testcase_21 | WA | - |
testcase_22 | WA | - |
testcase_23 | WA | - |
testcase_24 | WA | - |
testcase_25 | WA | - |
testcase_26 | WA | - |
testcase_27 | WA | - |
testcase_28 | WA | - |
testcase_29 | WA | - |
testcase_30 | WA | - |
testcase_31 | WA | - |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | WA | - |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | WA | - |
testcase_40 | WA | - |
testcase_41 | WA | - |
testcase_42 | AC | 998 ms
347,552 KB |
testcase_43 | AC | 2 ms
5,248 KB |
testcase_44 | AC | 2 ms
5,248 KB |
ソースコード
#pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #pragma GCC optimize("Ofast") #include <bits/stdc++.h> #include <unistd.h> using namespace std; #if __has_include(<atcoder/all>) #include <atcoder/all> using namespace atcoder; #endif using ll = long long; using ld = long double; using ull = unsigned long long; #define endl "\n" typedef pair<int, int> Pii; #define REP3(i, m, n) for (int i = (m); (i) < int(n); ++ (i)) #define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++) #define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++) #define ALL(x) begin(x), end(x) #define all(s) (s).begin(),(s).end() //#define rep2(i, m, n) for (int i = (m); i < (n); ++i) //#define rep(i, n) rep2(i, 0, n) #define PB push_back #define drep2(i, m, n) for (int i = (m)-1; i >= (n); --i) #define drep(i, n) drep2(i, n, 0) #define rever(vec) reverse(vec.begin(), vec.end()) #define sor(vec) sort(vec.begin(), vec.end()) //#define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++) #define fi first #define se second #define pb push_back #define P pair<ll,ll> #define NP next_permutation //const ll mod = 1000000009; const ll mod = 998244353; //const ll mod = 1000000007; const ll inf = 9100000000000000000ll; const ld eps = ld(0.0000000000001); static const long double pi = 3.141592653589793; template<class T>void vcin(vector<T> &n){for(int i=0;i<int(n.size());i++) cin>>n[i];} template<class T,class K>void vcin(vector<T> &n,vector<K> &m){for(int i=0;i<int(n.size());i++) cin>>n[i]>>m[i];} template<class T>void vcout(vector<T> &n){for(int i=0;i<int(n.size());i++){cout<<n[i]<<" ";}cout<<endl;} template<class T>void vcin(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cin>>n[i][j];}}} template<class T>void vcout(vector<vector<T>> &n){for(int i=0;i<int(n.size());i++){for(int j=0;j<int(n[i].size());j++){cout<<n[i][j]<<" ";}cout<<endl;}cout<<endl;} void yes(bool a){cout<<(a?"yes":"no")<<endl;} void YES(bool a){cout<<(a?"YES":"NO")<<endl;} void Yes(bool a){cout<<(a?"Yes":"No")<<endl;} void possible(bool a){ cout<<(a?"possible":"impossible")<<endl; } void Possible(bool a){ cout<<(a?"Possible":"Impossible")<<endl; } void POSSIBLE(bool a){ cout<<(a?"POSSIBLE":"IMPOSSIBLE")<<endl; } template<class T>auto min(const T& a){ return *min_element(all(a)); } template<class T>auto max(const T& a){ return *max_element(all(a)); } template<class T,class F>void print(pair<T,F> a){cout<<a.fi<<" "<<a.se<<endl;} template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0;} template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0;} template<class T> void ifmin(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} template<class T> void ifmax(T t,T u){if(t>u){cout<<-1<<endl;}else{cout<<t<<endl;}} template<typename T,typename ...Args>auto make_vector(T x,int arg,Args ...args){if constexpr(sizeof...(args)==0)return vector<T>(arg,x);else return vector(arg,make_vector<T>(x,args...));} ll fastgcd(ll u,ll v){ll shl=0;while(u&&v&&u!=v){bool eu=!(u&1);bool ev=!(v&1);if(eu&&ev){++shl;u>>=1;v>>=1;}else if(eu&&!ev){u>>=1;}else if(!eu&&ev){v>>=1;}else if(u>=v){u=(u-v)>>1;}else{ll tmp=u;u=(v-u)>>1;v=tmp;}}return !u?v<<shl:u<<shl;} ll modPow(ll a, ll n, ll mod) { if(mod==1) return 0;ll ret = 1; ll p = a % mod; while (n) { if (n & 1) ret = ret * p % mod; p = p * p % mod; n >>= 1; } return ret; } vector<ll> divisor(ll x){ vector<ll> ans; for(ll i = 1; i * i <= x; i++){ if(x % i == 0) {ans.push_back(i); if(i*i!=x){ ans.push_back(x / ans[i]);}}}sor(ans); return ans; } ll pop(ll x){return __builtin_popcountll(x);} ll poplong(ll x){ll y=-1;while(x){x/=2;y++;}return y;} template<class T> struct Sum{ vector<T> data; Sum(const vector<T>& v):data(v.size()+1){ for(ll i=0;i<v.size();i++) data[i+1]=data[i]+v[i]; } T get(ll l,ll r) const { return data[r]-data[l]; } }; template<class T> struct Sum2{ vector<vector<T>> data; Sum2(const vector<vector<T>> &v):data(v.size()+1,vector<T>(v[0].size()+1)){ for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]=data[i][j+1]+v[i][j]; for(int i=0;i<v.size();i++) for(int j=0;j<v[i].size();j++) data[i+1][j+1]+=data[i+1][j]; } T get(ll x1,ll y1,ll x2,ll y2) const { return data[x2][y2]+data[x1][y1]-data[x1][y2]-data[x2][y1]; } }; void cincout(){ ios::sync_with_stdio(false); std::cin.tie(nullptr); cout<< fixed << setprecision(10); } using mint = modint998244353; struct Node { Node *left, *right; mint v; Node() : left(nullptr), right(nullptr), v(0) {} }; // Dynamic Segment Tree class SegmentTree { Node *root; int n, n0; mint query(int a, int b, Node *n, int l, int r) { if(a <= l && r <= b) { return n->v; } if(r <= a || b <= l) { return 0; } mint lv = n->left ? query(a, b, n->left, l, (l + r) >> 1) : 0; mint rv = n->right ? query(a, b, n->right, (l + r) >> 1, r) : 0; return (lv + rv) ; } public: SegmentTree(int n) : n(n) { n0 = 1; while(n0 < n) n0 <<= 1; root = new Node(); } ~SegmentTree() { delete root; root = nullptr; } void update(int k, mint x) { Node *n = root; int l = 0, r = n0; n->v = (n->v + x) ; while(r-l > 1) { int m = (l + r) >> 1; if(k < m) { if(!n->left) n->left = new Node(); n = n->left; r = m; } else { if(!n->right) n->right = new Node(); n = n->right; l = m; } n->v = (n->v + x) ; } } mint query(int a, int b) { return query(a, b, root, 0, n0); } }; int main() { cincout(); ll n; cin>>n; vector<ll> a(n),b(n); for(int i=0;i<n;i++){ ll x,y; cin>>x>>y; a[i]=x; b[i]=y; } mint ans=0; for(int i=0;i<n;i++){ ans+=mint(mint(a[i]*a[i])+mint(b[i]*b[i]))*mint(n); } mint sum=0,sum2=0; for(int i=0;i<n;i++){ sum+=a[i]; sum2+=b[i]; } ans-=(sum*sum+sum2*sum2); mint ans2=0; vector<P> s; for(int i=0;i<n;i++) s.pb({a[i],b[i]}); vector<mint> x(n),y(n); vector<ll> z(n); sor(s); for(int i=0;i<n;i++){ x[i]=s[i].fi; y[i]=s[i].se; z[i]=s[i].se; } SegmentTree seg(1001000000),seg2(1001000000),seg3(1001000000),seg4(1001000000); for(int i=0;i<n;i++){ ans2-=x[i]*seg2.query(0,z[i]); ans2-=y[i]*seg.query(0,z[i]); ans2+=x[i]*seg2.query(z[i],1001000000); ans2+=y[i]*seg.query(z[i],1001000000); // cout<<x[i].val()<<" "<<y[i].val()<<" "<<seg.query(0,y[i].val()).val()<<" "<<seg.query(y[i].val(),1001000000).val()<<endl; // cout<<ans2.val()<<endl; ans2+=seg3.query(0,z[i])*(x[i]*y[i])+(seg4.query(0,z[i])); // cout<<ans2.val()<<" "<<seg3.query(0,y[i])*(seg4.query(0,y[i])+x[i]*y[i])<<endl; ans2-=seg3.query(z[i],1001000000)*(x[i]*y[i])+(seg4.query(z[i],1001000000)); // cout<<ans2.val()<<" "<<seg3.query(y[i],1001000000)<<endl; seg.update(z[i],seg.query(z[i],z[i]+1)+x[i]); seg2.update(z[i],seg2.query(z[i],z[i]+1)+y[i]); seg3.update(z[i],seg3.query(z[i],z[i]+1)+1); seg4.update(z[i],seg4.query(z[i],z[i]+1)+x[i]*y[i]); // cout<<ans2.val()<<endl; } // cout<<ans2.val()<<endl; cout<<(ans+ans2*2).val()<<endl; }