結果
| 問題 | No.1324 Approximate the Matrix |
| コンテスト | |
| ユーザー |
hitonanode
|
| 提出日時 | 2021-08-19 00:22:26 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.89.0) |
| 結果 |
AC
|
| 実行時間 | 66 ms / 2,000 ms |
| コード長 | 15,127 bytes |
| 記録 | |
| コンパイル時間 | 1,687 ms |
| コンパイル使用メモリ | 145,140 KB |
| 最終ジャッジ日時 | 2025-01-23 22:58:54 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 42 |
ソースコード
#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios {
fast_ios() { cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); };
} fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for (int i = (begin), i##_end_ = (end); i < i##_end_; i++)
#define IFOR(i, begin, end) for (int i = (end)-1, i##_begin_ = (begin); i >= i##_begin_; i--)
#define REP(i, n) FOR(i, 0, n)
#define IREP(i, n) IFOR(i, 0, n)
template <typename T, typename V> void ndarray(vector<T> &vec, const V &val, int len) {
vec.assign(len, val);
}
template <typename T, typename V, typename... Args>
void ndarray(vector<T> &vec, const V &val, int len, Args... args) {
vec.resize(len), for_each(begin(vec), end(vec), [&](T &v) { ndarray(v, val, args...); });
}
template <typename T> bool chmax(T &m, const T q) {
if (m < q) {
m = q;
return true;
} else
return false;
}
template <typename T> bool chmin(T &m, const T q) {
if (m > q) {
m = q;
return true;
} else
return false;
}
int floor_lg(long long x) { return x <= 0 ? -1 : 63 - __builtin_clzll(x); }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) {
return make_pair(l.first + r.first, l.second + r.second);
}
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) {
return make_pair(l.first - r.first, l.second - r.second);
}
template <typename T> vector<T> sort_unique(vector<T> vec) {
sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end());
return vec;
}
template <typename T> int arglb(const std::vector<T> &v, const T &x) {
return std::distance(v.begin(), std::lower_bound(v.begin(), v.end(), x));
}
template <typename T> int argub(const std::vector<T> &v, const T &x) {
return std::distance(v.begin(), std::lower_bound(v.begin(), v.end(), x));
}
template <typename T> istream &operator>>(istream &is, vector<T> &vec) {
for (auto &v : vec) is >> v;
return is;
}
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) {
os << '[';
for (auto v : vec) os << v << ',';
os << ']';
return os;
}
template <typename T, size_t sz> ostream &operator<<(ostream &os, const array<T, sz> &arr) {
os << '[';
for (auto v : arr) os << v << ',';
os << ']';
return os;
}
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) {
std::apply([&is](auto &&...args) { ((is >> args), ...); }, tpl);
return is;
}
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) {
std::apply([&os](auto &&...args) { ((os << args << ','), ...); }, tpl);
return os;
}
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) {
os << "deq[";
for (auto v : vec) os << v << ',';
os << ']';
return os;
}
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) {
os << '{';
for (auto v : vec) os << v << ',';
os << '}';
return os;
}
template <typename T, typename TH> ostream &operator<<(ostream &os, const unordered_set<T, TH> &vec) {
os << '{';
for (auto v : vec) os << v << ',';
os << '}';
return os;
}
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) {
os << '{';
for (auto v : vec) os << v << ',';
os << '}';
return os;
}
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) {
os << '{';
for (auto v : vec) os << v << ',';
os << '}';
return os;
}
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) {
os << '(' << pa.first << ',' << pa.second << ')';
return os;
}
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) {
os << '{';
for (auto v : mp) os << v.first << "=>" << v.second << ',';
os << '}';
return os;
}
template <typename TK, typename TV, typename TH>
ostream &operator<<(ostream &os, const unordered_map<TK, TV, TH> &mp) {
os << '{';
for (auto v : mp) os << v.first << "=>" << v.second << ',';
os << '}';
return os;
}
#ifdef HITONANODE_LOCAL
const string COLOR_RESET = "\033[0m", BRIGHT_GREEN = "\033[1;32m", BRIGHT_RED = "\033[1;31m", BRIGHT_CYAN = "\033[1;36m", NORMAL_CROSSED = "\033[0;9;37m", RED_BACKGROUND = "\033[1;41m", NORMAL_FAINT = "\033[0;2m";
#define dbg(x) \
cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl
#else
#define dbg(x) (x)
#endif
/*
MinCostFlow: Minimum-cost flow problem solver WITH NO NEGATIVE CYCLE (just negative cost edge is allowed)
Verified by SRM 770 Div1 Medium <https://community.topcoder.com/stat?c=problem_statement&pm=15702>
*/
template <typename CAP = long long, typename COST = long long> struct MinCostFlow {
const COST INF_COST = std::numeric_limits<COST>::max() / 2;
struct edge {
int to, rev;
CAP cap;
COST cost;
friend std::ostream &operator<<(std::ostream &os, const edge &e) {
os << '(' << e.to << ',' << e.rev << ',' << e.cap << ',' << e.cost << ')';
return os;
}
};
int V;
std::vector<std::vector<edge>> g;
std::vector<COST> dist;
std::vector<int> prevv, preve;
std::vector<COST> dual; // dual[V]: potential
std::vector<std::pair<int, int>> pos;
bool _calc_distance_bellman_ford(int s) { // O(VE), able to detect negative cycle
dist.assign(V, INF_COST);
dist[s] = 0;
bool upd = true;
int cnt = 0;
while (upd) {
upd = false;
cnt++;
if (cnt > V) return false; // Negative cycle existence
for (int v = 0; v < V; v++)
if (dist[v] != INF_COST) {
for (int i = 0; i < (int)g[v].size(); i++) {
edge &e = g[v][i];
COST c = dist[v] + e.cost + dual[v] - dual[e.to];
if (e.cap > 0 and dist[e.to] > c) {
dist[e.to] = c, prevv[e.to] = v, preve[e.to] = i;
upd = true;
}
}
}
}
return true;
}
bool _calc_distance_dijkstra(int s) { // O(ElogV)
dist.assign(V, INF_COST);
dist[s] = 0;
using P = std::pair<COST, int>;
std::priority_queue<P, std::vector<P>, std::greater<P>> q;
q.emplace(0, s);
while (!q.empty()) {
P p = q.top();
q.pop();
int v = p.second;
if (dist[v] < p.first) continue;
for (int i = 0; i < (int)g[v].size(); i++) {
edge &e = g[v][i];
COST c = dist[v] + e.cost + dual[v] - dual[e.to];
if (e.cap > 0 and dist[e.to] > c) {
dist[e.to] = c, prevv[e.to] = v, preve[e.to] = i;
q.emplace(dist[e.to], e.to);
}
}
}
return true;
}
MinCostFlow(int V = 0) : V(V), g(V) {}
void add_edge(int from, int to, CAP cap, COST cost) {
assert(0 <= from and from < V);
assert(0 <= to and to < V);
pos.emplace_back(from, g[from].size());
g[from].emplace_back(edge{to, (int)g[to].size() + (from == to), cap, cost});
g[to].emplace_back(edge{from, (int)g[from].size() - 1, (CAP)0, -cost});
}
std::pair<CAP, COST> flow(int s, int t, const CAP &f) {
/*
Flush amount of `f` from `s` to `t` using the Dijkstra's algorithm
works for graph with no negative cycles (negative cost edges are allowed)
retval: (flow, cost)
*/
COST ret = 0;
dual.assign(V, 0);
prevv.assign(V, -1);
preve.assign(V, -1);
CAP frem = f;
while (frem > 0) {
_calc_distance_dijkstra(s);
if (dist[t] == INF_COST) break;
for (int v = 0; v < V; v++) dual[v] = std::min(dual[v] + dist[v], INF_COST);
CAP d = frem;
for (int v = t; v != s; v = prevv[v]) { d = std::min(d, g[prevv[v]][preve[v]].cap); }
frem -= d;
ret += d * dual[t];
for (int v = t; v != s; v = prevv[v]) {
edge &e = g[prevv[v]][preve[v]];
e.cap -= d;
g[v][e.rev].cap += d;
}
}
return std::make_pair(f - frem, ret);
}
friend std::ostream &operator<<(std::ostream &os, const MinCostFlow &mcf) {
os << "[MinCostFlow]V=" << mcf.V << ":";
for (int i = 0; i < (int)mcf.g.size(); i++)
for (auto &e : mcf.g[i]) {
os << "\n" << i << "->" << e.to << ": cap=" << e.cap << ", cost=" << e.cost;
}
return os;
}
};
// https://people.orie.cornell.edu/dpw/orie633/
template <class Cap, class Cost, int SCALING = 1, int REFINEMENT_ITER = 20> struct mcf_costscaling {
mcf_costscaling() = default;
mcf_costscaling(int n) : _n(n), to(n), b(n), p(n) {}
int _n;
std::vector<Cap> cap;
std::vector<Cost> cost;
std::vector<int> opposite;
std::vector<std::vector<int>> to;
std::vector<Cap> b;
std::vector<Cost> p;
int add_edge(int from_, int to_, Cap cap_, Cost cost_) {
assert(0 <= from_ and from_ < _n);
assert(0 <= to_ and to_ < _n);
assert(0 <= cap_);
cost_ *= (_n + 1);
const int e = int(cap.size());
to[from_].push_back(e);
cap.push_back(cap_);
cost.push_back(cost_);
opposite.push_back(to_);
to[to_].push_back(e + 1);
cap.push_back(0);
cost.push_back(-cost_);
opposite.push_back(from_);
return e / 2;
}
void add_supply(int v, Cap supply) { b[v] += supply; }
void add_demand(int v, Cap demand) { add_supply(v, -demand); }
template <typename RetCost = Cost> RetCost solve() {
Cost eps = 1;
std::vector<int> que;
for (const auto c : cost) {
while (eps <= -c) eps <<= SCALING;
}
for (; eps >>= SCALING;) {
auto no_admissible_cycle = [&]() -> bool {
for (int i = 0; i < _n; i++) {
if (b[i]) return false;
}
std::vector<Cost> pp = p;
for (int iter = 0; iter < REFINEMENT_ITER; iter++) {
bool flg = false;
for (int e = 0; e < int(cap.size()); e++) {
if (!cap[e]) continue;
int i = opposite[e ^ 1], j = opposite[e];
if (pp[j] > pp[i] + cost[e] + eps) pp[j] = pp[i] + cost[e] + eps, flg = true;
}
if (!flg) return p = pp, true;
}
return false;
};
if (no_admissible_cycle()) continue; // Refine
for (int e = 0; e < int(cap.size()); e++) {
const int i = opposite[e ^ 1], j = opposite[e];
const Cost cp_ij = cost[e] + p[i] - p[j];
if (cap[e] and cp_ij < 0) b[i] -= cap[e], b[j] += cap[e], cap[e ^ 1] += cap[e], cap[e] = 0;
}
que.clear();
int qh = 0;
for (int i = 0; i < _n; i++) {
if (b[i] > 0) que.push_back(i);
}
std::vector<int> iters(_n);
while (qh < int(que.size())) {
const int i = que[qh++];
for (; iters[i] < int(to[i].size()) and b[i]; ++iters[i]) { // Push
int e = to[i][iters[i]];
if (!cap[e]) continue;
int j = opposite[e];
Cost cp_ij = cost[e] + p[i] - p[j];
if (cp_ij >= 0) continue;
Cap f = b[i] > cap[e] ? cap[e] : b[i];
if (b[j] <= 0 and b[j] + f > 0) que.push_back(j);
b[i] -= f, b[j] += f, cap[e] -= f, cap[e ^ 1] += f;
}
if (b[i] > 0) { // Relabel
bool flg = false;
for (int e : to[i]) {
if (!cap[e]) continue;
Cost x = p[opposite[e]] - cost[e] - eps;
if (!flg or x > p[i]) flg = true, p[i] = x;
}
que.push_back(i), iters[i] = 0;
}
}
}
RetCost ret = 0;
for (int e = 0; e < int(cap.size()); e += 2) ret += RetCost(cost[e]) * cap[e ^ 1];
return ret / (_n + 1);
}
std::vector<Cost> potential() const {
std::vector<Cost> ret = p, c0 = cost;
for (auto &x : ret) x /= (_n + 1);
for (auto &x : c0) x /= (_n + 1);
while (true) {
bool flg = false;
for (int i = 0; i < _n; i++) {
for (const auto e : to[i]) {
if (!cap[e]) continue;
int j = opposite[e];
auto y = ret[i] + c0[e];
if (ret[j] > y) ret[j] = y, flg = true;
}
}
if (!flg) break;
}
return ret;
}
struct edge {
int from, to;
Cap cap, flow;
Cost cost;
};
edge get_edge(int e) const {
int m = cap.size() / 2;
assert(e >= 0 and e < m);
return {opposite[e * 2 + 1], opposite[e * 2], cap[e * 2] + cap[e * 2 + 1], cap[e * 2 + 1], cost[e * 2] / (_n + 1)};
}
std::vector<edge> edges() const {
int m = cap.size() / 2;
std::vector<edge> result(m);
for (int i = 0; i < m; i++) result[i] = get_edge(i);
return result;
}
};
int main() {
int N, K;
cin >> N >> K;
vector<int> A(N), B(N);
vector P(N, vector<int>(N));
cin >> A >> B >> P;
const int gs = N * 2, gt = gs + 1;
mcf_costscaling<int, lint> graph(gt + 1);
lint ret = 0;
REP(i, N) REP(j, N) {
ret += P[i][j] * P[i][j];
REP(a, A[i]) graph.add_edge(i, j + N, 1, 2 * (a - P[i][j]) + 1);
}
REP(i, N) {
graph.add_edge(gs, i, A[i], 0);
graph.add_edge(i + N, gt, B[i], 0);
}
graph.add_supply(gs, K);
graph.add_demand(gt, K);
cout << ret + graph.solve() << '\n';
}
hitonanode