結果
問題 | No.1653 Squarefree |
ユーザー |
![]() |
提出日時 | 2021-08-20 22:10:35 |
言語 | Rust (1.83.0 + proconio) |
結果 |
AC
|
実行時間 | 728 ms / 2,000 ms |
コード長 | 4,223 bytes |
コンパイル時間 | 12,622 ms |
コンパイル使用メモリ | 392,160 KB |
実行使用メモリ | 77,184 KB |
最終ジャッジ日時 | 2024-10-14 08:18:23 |
合計ジャッジ時間 | 32,233 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 38 |
ソースコード
// ---------- begin enumerate prime ----------fn enumerate_prime<F>(n: usize, mut f: F)whereF: FnMut(usize),{assert!(1 <= n && n <= 5 * 10usize.pow(8));let batch = (n as f64).sqrt().ceil() as usize;let mut is_prime = vec![true; batch + 1];for i in (2..).take_while(|p| p * p <= batch) {if is_prime[i] {let mut j = i * i;while let Some(p) = is_prime.get_mut(j) {*p = false;j += i;}}}let mut prime = vec![];for (i, p) in is_prime.iter().enumerate().skip(2) {if *p && i <= n {f(i);prime.push(i);}}let mut l = batch + 1;while l <= n {let r = std::cmp::min(l + batch, n + 1);is_prime.clear();is_prime.resize(r - l, true);for &p in prime.iter() {let mut j = (l + p - 1) / p * p - l;while let Some(is_prime) = is_prime.get_mut(j) {*is_prime = false;j += p;}}for (i, _) in is_prime.iter().enumerate().filter(|p| *p.1) {f(i + l);}l += batch;}}// ---------- end enumerate prime ----------// floor(a ^ (1 / k))fn kth_root(a: u64, k: u64) -> u64 {assert!(k > 0);if a == 0 {return 0;}if k >= 64 {return 1;}if k == 1 {return a;}let valid = |x: u64| -> bool {let mut t = x;for _ in 1..k {let (val, ok) = t.overflowing_mul(x);if !(!ok && val <= a) {return false;}t = val;}true};let mut ok = 1;let mut ng = 2;while valid(ng) {ok = ng;ng *= 2;}while ng - ok > 1 {let mid = ok + (ng - ok) / 2;if valid(mid) {ok = mid;} else {ng = mid;}}ok}// ---------- begin input macro ----------// reference: https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8macro_rules! input {(source = $s:expr, $($r:tt)*) => {let mut iter = $s.split_whitespace();input_inner!{iter, $($r)*}};($($r:tt)*) => {let s = {use std::io::Read;let mut s = String::new();std::io::stdin().read_to_string(&mut s).unwrap();s};let mut iter = s.split_whitespace();input_inner!{iter, $($r)*}};}macro_rules! input_inner {($iter:expr) => {};($iter:expr, ) => {};($iter:expr, $var:ident : $t:tt $($r:tt)*) => {let $var = read_value!($iter, $t);input_inner!{$iter $($r)*}};}macro_rules! read_value {($iter:expr, ( $($t:tt),* )) => {( $(read_value!($iter, $t)),* )};($iter:expr, [ $t:tt ; $len:expr ]) => {(0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()};($iter:expr, chars) => {read_value!($iter, String).chars().collect::<Vec<char>>()};($iter:expr, bytes) => {read_value!($iter, String).bytes().collect::<Vec<u8>>()};($iter:expr, usize1) => {read_value!($iter, usize) - 1};($iter:expr, $t:ty) => {$iter.next().unwrap().parse::<$t>().expect("Parse error")};}// ---------- end input macro ----------fn run() {input!(l: usize, r: usize);let mut factor = vec![vec![]; r - l + 1];enumerate_prime(1000000, |p| {let mut x = (l + p - 1) / p * p - l;while x < factor.len() {factor[x].push(p);x += p;}});let mut ans = 0;for (i, f) in factor.iter().enumerate() {let mut n = i + l;if n == 1 {ans += 1;continue;}let mut add = true;for &p in f.iter() {add &= n % (p * p) != 0;while n % p == 0 {n /= p;}}if n > 1 {let r = kth_root(n as u64, 2) as usize;add &= r * r != n;}if add {ans += 1;}}println!("{}", ans);}fn main() {run();}