結果

問題 No.1653 Squarefree
ユーザー akakimidori
提出日時 2021-08-20 22:10:35
言語 Rust
(1.83.0 + proconio)
結果
AC  
実行時間 728 ms / 2,000 ms
コード長 4,223 bytes
コンパイル時間 12,622 ms
コンパイル使用メモリ 392,160 KB
実行使用メモリ 77,184 KB
最終ジャッジ日時 2024-10-14 08:18:23
合計ジャッジ時間 32,233 ms
ジャッジサーバーID
(参考情報)
judge2 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 38
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

// ---------- begin enumerate prime ----------
fn enumerate_prime<F>(n: usize, mut f: F)
where
F: FnMut(usize),
{
assert!(1 <= n && n <= 5 * 10usize.pow(8));
let batch = (n as f64).sqrt().ceil() as usize;
let mut is_prime = vec![true; batch + 1];
for i in (2..).take_while(|p| p * p <= batch) {
if is_prime[i] {
let mut j = i * i;
while let Some(p) = is_prime.get_mut(j) {
*p = false;
j += i;
}
}
}
let mut prime = vec![];
for (i, p) in is_prime.iter().enumerate().skip(2) {
if *p && i <= n {
f(i);
prime.push(i);
}
}
let mut l = batch + 1;
while l <= n {
let r = std::cmp::min(l + batch, n + 1);
is_prime.clear();
is_prime.resize(r - l, true);
for &p in prime.iter() {
let mut j = (l + p - 1) / p * p - l;
while let Some(is_prime) = is_prime.get_mut(j) {
*is_prime = false;
j += p;
}
}
for (i, _) in is_prime.iter().enumerate().filter(|p| *p.1) {
f(i + l);
}
l += batch;
}
}
// ---------- end enumerate prime ----------
// floor(a ^ (1 / k))
fn kth_root(a: u64, k: u64) -> u64 {
assert!(k > 0);
if a == 0 {
return 0;
}
if k >= 64 {
return 1;
}
if k == 1 {
return a;
}
let valid = |x: u64| -> bool {
let mut t = x;
for _ in 1..k {
let (val, ok) = t.overflowing_mul(x);
if !(!ok && val <= a) {
return false;
}
t = val;
}
true
};
let mut ok = 1;
let mut ng = 2;
while valid(ng) {
ok = ng;
ng *= 2;
}
while ng - ok > 1 {
let mid = ok + (ng - ok) / 2;
if valid(mid) {
ok = mid;
} else {
ng = mid;
}
}
ok
}
// ---------- begin input macro ----------
// reference: https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8
macro_rules! input {
(source = $s:expr, $($r:tt)*) => {
let mut iter = $s.split_whitespace();
input_inner!{iter, $($r)*}
};
($($r:tt)*) => {
let s = {
use std::io::Read;
let mut s = String::new();
std::io::stdin().read_to_string(&mut s).unwrap();
s
};
let mut iter = s.split_whitespace();
input_inner!{iter, $($r)*}
};
}
macro_rules! input_inner {
($iter:expr) => {};
($iter:expr, ) => {};
($iter:expr, $var:ident : $t:tt $($r:tt)*) => {
let $var = read_value!($iter, $t);
input_inner!{$iter $($r)*}
};
}
macro_rules! read_value {
($iter:expr, ( $($t:tt),* )) => {
( $(read_value!($iter, $t)),* )
};
($iter:expr, [ $t:tt ; $len:expr ]) => {
(0..$len).map(|_| read_value!($iter, $t)).collect::<Vec<_>>()
};
($iter:expr, chars) => {
read_value!($iter, String).chars().collect::<Vec<char>>()
};
($iter:expr, bytes) => {
read_value!($iter, String).bytes().collect::<Vec<u8>>()
};
($iter:expr, usize1) => {
read_value!($iter, usize) - 1
};
($iter:expr, $t:ty) => {
$iter.next().unwrap().parse::<$t>().expect("Parse error")
};
}
// ---------- end input macro ----------
fn run() {
input!(l: usize, r: usize);
let mut factor = vec![vec![]; r - l + 1];
enumerate_prime(1000000, |p| {
let mut x = (l + p - 1) / p * p - l;
while x < factor.len() {
factor[x].push(p);
x += p;
}
});
let mut ans = 0;
for (i, f) in factor.iter().enumerate() {
let mut n = i + l;
if n == 1 {
ans += 1;
continue;
}
let mut add = true;
for &p in f.iter() {
add &= n % (p * p) != 0;
while n % p == 0 {
n /= p;
}
}
if n > 1 {
let r = kth_root(n as u64, 2) as usize;
add &= r * r != n;
}
if add {
ans += 1;
}
}
println!("{}", ans);
}
fn main() {
run();
}
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