結果

問題 No.1666 累乗数
ユーザー stoqstoq
提出日時 2021-09-03 22:03:54
言語 C++17
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 263 ms / 2,000 ms
コード長 5,380 bytes
コンパイル時間 4,617 ms
コンパイル使用メモリ 269,204 KB
実行使用メモリ 27,140 KB
最終ジャッジ日時 2023-08-21 21:55:43
合計ジャッジ時間 10,960 ms
ジャッジサーバーID
（参考情報） 		judge11 / judge12
このコードへのチャレンジ（β）

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 254 ms
25,612 KB
testcase_01 AC 259 ms
25,704 KB
testcase_02 AC 260 ms
26,624 KB
testcase_03 AC 259 ms
25,804 KB
testcase_04 AC 260 ms
25,624 KB
testcase_05 AC 260 ms
26,556 KB
testcase_06 AC 259 ms
26,320 KB
testcase_07 AC 260 ms
25,808 KB
testcase_08 AC 258 ms
25,644 KB
testcase_09 AC 259 ms
25,788 KB
testcase_10 AC 261 ms
26,040 KB
testcase_11 AC 260 ms
25,340 KB
testcase_12 AC 260 ms
26,476 KB
testcase_13 AC 260 ms
26,416 KB
testcase_14 AC 262 ms
27,140 KB
testcase_15 AC 262 ms
26,696 KB
testcase_16 AC 261 ms
26,048 KB
testcase_17 AC 258 ms
25,576 KB
testcase_18 AC 263 ms
26,424 KB
testcase_19 AC 261 ms
25,344 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#define MOD_TYPE 1

#pragma region Macros

#include <bits/stdc++.h>
using namespace std;

#include <atcoder/all>
using namespace atcoder;

#if 0
#include <boost/multiprecision/cpp_dec_float.hpp>
#include <boost/multiprecision/cpp_int.hpp>
using Int = boost::multiprecision::cpp_int;
using lld = boost::multiprecision::cpp_dec_float_100;
#endif

#if 1
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#endif

using ll = long long int;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using pld = pair<ld, ld>;
template <typename Q_type>
using smaller_queue = priority_queue<Q_type, vector<Q_type>, greater<Q_type>>;

#if MOD_TYPE == 1
constexpr ll MOD = ll(1e9 + 7);
#else
#if MOD_TYPE == 2
constexpr ll MOD = 998244353;
#else
constexpr ll MOD = 1000003;
#endif
#endif

using mint = static_modint<MOD>;
constexpr int INF = (int)1e9 + 10;
constexpr ll LINF = (ll)4e18;
constexpr double PI = acos(-1.0);
constexpr double EPS = 1e-11;
constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0};
constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0};

#define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i)
#define rep(i, n) REP(i, 0, n)
#define REPI(i, m, n) for (int i = m; i < (int)(n); ++i)
#define repi(i, n) REPI(i, 0, n)
#define MP make_pair
#define MT make_tuple
#define YES(n) cout << ((n) ? "YES" : "NO") << "\n"
#define Yes(n) cout << ((n) ? "Yes" : "No") << "\n"
#define possible(n) cout << ((n) ? "possible" : "impossible") << "\n"
#define Possible(n) cout << ((n) ? "Possible" : "Impossible") << "\n"
#define Yay(n) cout << ((n) ? "Yay!" : ":(") << "\n"
#define all(v) v.begin(), v.end()
#define NP(v) next_permutation(all(v))
#define dbg(x) cerr << #x << ":" << x << "\n";
#define UNIQUE(v) v.erase(unique(all(v)), v.end())

struct io_init {
  io_init() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    cout << setprecision(30) << setiosflags(ios::fixed);
  };
} io_init;
template <typename T>
inline bool chmin(T &a, T b) {
  if (a > b) {
    a = b;
    return true;
  }
  return false;
}
template <typename T>
inline bool chmax(T &a, T b) {
  if (a < b) {
    a = b;
    return true;
  }
  return false;
}
inline ll CEIL(ll a, ll b) { return (a + b - 1) / b; }
template <typename A, size_t N, typename T>
inline void Fill(A (&array)[N], const T &val) {
  fill((T *)array, (T *)(array + N), val);
}
template <typename T>
vector<T> compress(vector<T> &v) {
  vector<T> val = v;
  sort(all(val)), val.erase(unique(all(val)), val.end());
  for (auto &&vi : v) vi = lower_bound(all(val), vi) - val.begin();
  return val;
}
template <typename T, typename U>
constexpr istream &operator>>(istream &is, pair<T, U> &p) noexcept {
  is >> p.first >> p.second;
  return is;
}
template <typename T, typename U>
constexpr ostream &operator<<(ostream &os, pair<T, U> p) noexcept {
  os << p.first << " " << p.second;
  return os;
}
ostream &operator<<(ostream &os, mint m) {
  os << m.val();
  return os;
}

random_device seed_gen;
mt19937_64 engine(seed_gen());

struct BiCoef {
  vector<mint> fact_, inv_, finv_;
  BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {
    fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);
    for (int i = 2; i < n; i++) {
      fact_[i] = fact_[i - 1] * i;
      inv_[i] = -inv_[MOD % i] * (MOD / i);
      finv_[i] = finv_[i - 1] * inv_[i];
    }
  }
  mint C(ll n, ll k) const noexcept {
    if (n < k || n < 0 || k < 0) return 0;
    return fact_[n] * finv_[k] * finv_[n - k];
  }
  mint P(ll n, ll k) const noexcept { return C(n, k) * fact_[k]; }
  mint H(ll n, ll k) const noexcept { return C(n + k - 1, k); }
  mint Ch1(ll n, ll k) const noexcept {
    if (n < 0 || k < 0) return 0;
    mint res = 0;
    for (int i = 0; i < n; i++)
      res += C(n, i) * mint(n - i).pow(k) * (i & 1 ? -1 : 1);
    return res;
  }
  mint fact(ll n) const noexcept {
    if (n < 0) return 0;
    return fact_[n];
  }
  mint inv(ll n) const noexcept {
    if (n < 0) return 0;
    return inv_[n];
  }
  mint finv(ll n) const noexcept {
    if (n < 0) return 0;
    return finv_[n];
  }
};

BiCoef bc(500010);

#pragma endregion

ll sqrti(ll n) {
  assert(n >= 0);
  ll lo = 0, hi = INF;
  while (hi - lo > 1) {
    ll mi = (lo + hi) / 2;
    if (mi * mi <= n)
      lo = mi;
    else
      hi = mi;
  }
  return lo;
}

bool is_sq(ll n) {
  ll sq = sqrti(n);
  return n == sq * sq;
}

void solve() {
  vector<ll> v;
  for (ll i = 3; i <= 60; i++) {
    ll j = 2;
    while (1) {
      __int128 p = 1;
      bool valid = true;
      rep(jj, i) {
        p *= j;
        if (p > ll(2e18)) {
          valid = false;
          break;
        }
      }
      if (not valid) break;
      if (not is_sq(p)) v.push_back(ll(p));
      j++;
    }
  }
  sort(all(v));
  UNIQUE(v);

  auto sq = [](ll n) {
    ll lo = 0, hi = 1e9 + 10;
    while (hi - lo > 1) {
      ll mi = (lo + hi) / 2;
      if (mi * mi <= n)
        lo = mi;
      else
        hi = mi;
    }
    return lo;
  };

  auto f = [&](ll k) {
    ll lo = 0, hi = LINF;
    while (hi - lo > 1) {
      ll mi = (lo + hi) / 2;
      ll t = upper_bound(all(v), mi) - v.begin();
      t += sqrti(mi);
      if (t >= k)
        hi = mi;
      else
        lo = mi;
    }
    return hi;
  };

  int test;
  cin >> test;
  rep(i, test) {
    ll k;
    cin >> k;
    cout << f(k) << "\n";
  }
}

int main() { solve(); }
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