結果
問題 | No.1666 累乗数 |
ユーザー | hamath |
提出日時 | 2021-09-03 22:12:49 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,614 bytes |
コンパイル時間 | 3,007 ms |
コンパイル使用メモリ | 215,344 KB |
実行使用メモリ | 5,376 KB |
最終ジャッジ日時 | 2024-05-09 04:23:12 |
合計ジャッジ時間 | 12,770 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 11 ms
5,248 KB |
testcase_01 | WA | - |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
ソースコード
#ifdef LOCAL //#define _GLIBCXX_DEBUG #endif //#pragma GCC target("avx512f,avx512dq,avx512cd,avx512bw,avx512vl") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef pair<ll, ll> P; typedef pair<int, int> Pi; typedef vector<ll> Vec; typedef vector<int> Vi; typedef vector<string> Vs; typedef vector<char> Vc; typedef vector<P> VP; typedef vector<vector<ll>> VV; typedef vector<vector<int>> VVi; typedef vector<vector<char>> VVc; typedef vector<vector<vector<ll>>> VVV; typedef vector<vector<vector<vector<ll>>>> VVVV; #define endl '\n' #define REP(i, a, b) for(ll i=(a); i<(b); i++) #define PER(i, a, b) for(ll i=(a); i>=(b); i--) #define rep(i, n) REP(i, 0, n) #define per(i, n) PER(i, n, 0) const ll INF=1e18+18; const ll MOD=1000000007; #define Yes(n) cout << ((n) ? "Yes" : "No") << endl; #define YES(n) cout << ((n) ? "YES" : "NO") << endl; #define ALL(v) v.begin(), v.end() #define rALL(v) v.rbegin(), v.rend() #define pb(x) push_back(x) #define mp(a, b) make_pair(a,b) #define Each(a,b) for(auto &a :b) #define rEach(i, mp) for (auto i = mp.rbegin(); i != mp.rend(); ++i) #ifdef LOCAL #define dbg(x_) cerr << #x_ << ":" << x_ << endl; #define dbgmap(mp) cerr << #mp << ":"<<endl; for (auto i = mp.begin(); i != mp.end(); ++i) { cerr << i->first <<":"<<i->second << endl;} #define dbgset(st) cerr << #st << ":"<<endl; for (auto i = st.begin(); i != st.end(); ++i) { cerr << *i <<" ";}cerr<<endl; #define dbgarr(n,m,arr) rep(i,n){rep(j,m){cerr<<arr[i][j]<<" ";}cerr<<endl;} #define dbgdp(n,arr) rep(i,n){cerr<<arr[i]<<" ";}cerr<<endl; #else #define dbg(...) #define dbgmap(...) #define dbgset(...) #define dbgarr(...) #define dbgdp(...) #endif #define out(a) cout<<a<<endl #define out2(a,b) cout<<a<<" "<<b<<endl #define vout(v) rep(i,v.size()){cout<<v[i]<<" ";}cout<<endl #define Uniq(v) v.erase(unique(v.begin(), v.end()), v.end()) #define fi first #define se second template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; } template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; } template<typename T1, typename T2> ostream &operator<<(ostream &s, const pair<T1, T2> &p) { return s<<"("<<p.first<<", "<<p.second<<")"; } template<typename T>istream& operator>>(istream&i,vector<T>&v) {rep(j,v.size())i>>v[j];return i;} // vector template<typename T> ostream &operator<<(ostream &s, const vector<T> &v) { int len=v.size(); for(int i=0; i<len; ++i) { s<<v[i]; if(i<len-1) s<<" "; } return s; } // 2 dimentional vector template<typename T> ostream &operator<<(ostream &s, const vector<vector<T> > &vv) { s<<endl; int len=vv.size(); for(int i=0; i<len; ++i) { s<<vv[i]<<endl; } return s; } vector< bool > prime_table(int n) { vector< bool > prime(n + 1, true); if(n >= 0) prime[0] = false; if(n >= 1) prime[1] = false; for(int i = 2; i * i <= n; i++) { if(!prime[i]) continue; for(int j = i + i; j <= n; j += i) { prime[j] = false; } } return prime; } int solve(){ ll K; cin>>K; vector<bool> pt = prime_table(100); ll L = 0; //ng ll R = 4e18; //ok if(K==1){ out(1); return 0; } auto f = [&](ll x)->bool{ //x以下の累乗数がK個以上 ll cnt = 1; REP(b, 2, 61){ if(!pt[b])continue; ll LL = 1;//ok ll RR = 4e18;//ng while(LL+1 < RR){ ll a = (LL+RR)/2; // a^b < x bool ok = true; ll val = 1; rep(_ , b){ if(val > INF/a){ ok = false; break; } val *= a; if(val >= x){ ok = false; break; } } if(ok){ LL = a; }else{ RR = a; } } //dbg(mp(LL,b)) cnt += LL-1; } //dbg(cnt); return cnt >= K; }; //dbg(f(50)); while(L+1 < R){ ll mid = (L+R)/2; if(f(mid)){ R = mid; }else{ L = mid; } } out(L); return 0; } int main() { cin.tie(nullptr); ios::sync_with_stdio(false); cout<<std::setprecision(10); ll T; cin>>T; while(T--) solve(); }