結果

問題 No.1666 累乗数
ユーザー miscalc
提出日時 2021-09-03 22:39:04
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 946 ms / 2,000 ms
コード長 1,874 bytes
コンパイル時間 2,215 ms
コンパイル使用メモリ 196,596 KB
最終ジャッジ日時 2025-01-24 06:29:15
ジャッジサーバーID
(参考情報)
judge5 / judge5
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ファイルパターン 結果
sample AC * 1
other AC * 19
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <atcoder/modint>
using namespace std;
using namespace atcoder;
using mint = modint998244353;
//using mint = modint1000000007;
using ll = long long;
using ld = long double;
using pll = pair<ll, ll>;
using tlll = tuple<ll, ll, ll>;
constexpr ll INF = 1LL << 60;
template<class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;}
template<class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;}
ll safemod(ll A, ll M) {return (A % M + M) % M;}
ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;}
ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);}
#define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false)
ll isok(ll a, ll b, ll c)
{
ll tmp = 1;
for (ll i = 0; i < b; i++)
{
if (tmp > c / a)
return false;
tmp *= a;
}
return true;
}
ll rt(ll b, ll c)
{
ll ok = 0, ng = 1e9 + 10;
while (abs(ok - ng) > 1)
{
ll mid = (ok + ng) / 2;
if (isok(mid, b, c))
ok = mid;
else
ng = mid;
}
return ok;
}
vector<ll> mb = {0, 1, -1, -1, 0, -1, 1, -1, 0, 0, 1, -1, 0, -1, 1, 1, 0, -1, 0, -1, 0, 1, 1, -1, 0, 0, 1, 0, 0, -1, -1, -1, 0, 1, 1, 1, 0, -1, 1, 1,
    0, -1, -1, -1, 0, 0, 1, -1, 0, 0, 0, 1, 0, -1, 0, 1, 0, 1, 1, -1, 0, -1, 1, 0, 0, 1, -1, -1, 0, 1, -1, -1, 0, -1, 1, 0, 0, 1, -1};
ll count(ll c)
{
ll ret = 0;
for (ll b = 2; b < 64; b++)
{
ll tmp = -mb.at(b) * rt(b, c);
ret += tmp;
}
return ret;
}
int main()
{
cerr << count(10) << endl;
ll T;
cin >> T;
for (ll t = 0; t < T; t++)
{
ll K;
cin >> K;
ll ok = 0, ng = 1e18 + 10;
while (abs(ok - ng) > 1)
{
ll mid = (ok + ng) / 2;
if (count(mid) <= K)
ok = mid;
else
ng = mid;
}
cout << ok + 1 << '\n';
}
}
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