結果
| 問題 | No.1667 Forest | 
| コンテスト | |
| ユーザー |  keijak | 
| 提出日時 | 2021-09-03 22:52:44 | 
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 719 ms / 3,000 ms | 
| コード長 | 3,678 bytes | 
| コンパイル時間 | 2,260 ms | 
| コンパイル使用メモリ | 205,640 KB | 
| 最終ジャッジ日時 | 2025-01-24 06:41:35 | 
| ジャッジサーバーID (参考情報) | judge4 / judge4 | 
(要ログイン)
| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 15 | 
ソースコード
#include <bits/stdc++.h>
#define REP_(i, a_, b_, a, b, ...) \
  for (int i = (a), END_##i = (b); i < END_##i; ++i)
#define REP(i, ...) REP_(i, __VA_ARGS__, __VA_ARGS__, 0, __VA_ARGS__)
#define ALL(x) std::begin(x), std::end(x)
using i64 = long long;
#include <atcoder/modint>
using Mint = atcoder::dynamic_modint<0>;
std::ostream &operator<<(std::ostream &os, const Mint &m) {
  return os << m.val();
}
template<typename T, typename U>
inline bool chmax(T &a, U b) {
  return a < b and ((a = std::move(b)), true);
}
template<typename T, typename U>
inline bool chmin(T &a, U b) {
  return a > b and ((a = std::move(b)), true);
}
template<typename T>
inline int ssize(const T &a) {
  return (int) std::size(a);
}
template<typename T>
std::istream &operator>>(std::istream &is, std::vector<T> &a) {
  for (auto &x: a) is >> x;
  return is;
}
template<typename T, typename U>
std::ostream &operator<<(std::ostream &os, const std::pair<T, U> &a) {
  return os << "(" << a.first << ", " << a.second << ")";
}
template<typename Container>
std::ostream &print_seq(const Container &a, std::string_view sep = " ",
                        std::string_view ends = "\n",
                        std::ostream &os = std::cout) {
  auto b = std::begin(a), e = std::end(a);
  for (auto it = std::begin(a); it != e; ++it) {
    if (it != b) os << sep;
    os << *it;
  }
  return os << ends;
}
template<typename T, typename = void>
struct is_iterable : std::false_type {};
template<typename T>
struct is_iterable<T, std::void_t<decltype(std::begin(std::declval<T>())),
                                  decltype(std::end(std::declval<T>()))>>
    : std::true_type {
};
template<typename T, typename = std::enable_if_t<
    is_iterable<T>::value &&
        !std::is_same<T, std::string_view>::value &&
        !std::is_same<T, std::string>::value>>
std::ostream &operator<<(std::ostream &os, const T &a) {
  return print_seq(a, ", ", "", (os << "{")) << "}";
}
void print() { std::cout << "\n"; }
template<class T>
void print(const T &x) {
  std::cout << x << "\n";
}
template<typename Head, typename... Tail>
void print(const Head &head, Tail... tail) {
  std::cout << head << " ";
  print(tail...);
}
struct Input {
  template<typename T>
  operator T() const {
    T x;
    std::cin >> x;
    return x;
  }
} in;
#ifdef MY_DEBUG
#include "debug_dump.hpp"
#else
#define DUMP(...)
#endif
using namespace std;
// mod: prime
template<class T = Mint>
struct Factorials {
  // factorials and inverse factorials.
  std::vector<T> fact, ifact;
  // n: max cached value.
  Factorials(int n) : fact(n + 1), ifact(n + 1) {
    assert(n >= 0);
    assert(n < T::mod());
    fact[0] = 1;
    for (int i = 1; i <= n; ++i) {
      fact[i] = fact[i - 1] * i;
    }
    ifact[n] = fact[n].inv();
    for (int i = n; i >= 1; --i) {
      ifact[i - 1] = ifact[i] * i;
    }
  }
  // Combination (nCk)
  T C(int n, int k) const {
    if (k < 0 || k > n) return 0;
    return fact[n] * ifact[k] * ifact[n - k];
  }
};
int main() {
  ios_base::sync_with_stdio(false), cin.tie(nullptr);
  int n = in;
  int mod = in;
  Mint::set_mod(mod);
  Factorials<Mint> fs(n);
  auto g = [&](int n) -> Mint {
    if (n <= 2) return 1;
    return Mint(n).pow(n - 2);
  };
  vector memo(n + 1, vector(n + 1, optional<Mint>()));
  auto f = [&](auto &f, int n, int m) -> Mint {
    if (m < 0) return 0;
    if (n <= 1) return (m == 0) ? 1 : 0;
    if (memo[n][m].has_value()) return memo[n][m].value();
    Mint ret = 0;
    for (int i = 1; i <= n; ++i) {
      ret += fs.C(n - 1, i - 1) * g(i) * f(f, n - i, m - i + 1);
    }
    memo[n][m] = ret;
    return ret;
  };
  REP(j, n) {
    print(f(f, n, j));
  }
}
            
            
            
        