結果

問題 No.1678 Coin Trade (Multiple)
ユーザー chineristACchineristAC
提出日時 2021-09-10 22:30:29
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 1,964 bytes
コンパイル時間 265 ms
コンパイル使用メモリ 82,364 KB
実行使用メモリ 105,868 KB
最終ジャッジ日時 2024-06-12 01:20:24
合計ジャッジ時間 7,113 ms
ジャッジサーバーID
(参考情報)
judge4 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other TLE * 1
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ソースコード

diff #
プレゼンテーションモードにする

from heapq import heappush, heappop
class MinCostFlow:
INF = 10**18
def __init__(self, N):
self.N = N
self.G = [[] for i in range(N)]
def add_edge(self, fr, to, cap, cost):
forward = [to, cap, cost, None]
backward = forward[3] = [fr, 0, -cost, forward]
self.G[fr].append(forward)
self.G[to].append(backward)
def flow(self, s, t, f):
N = self.N; G = self.G
INF = MinCostFlow.INF
res = 0
H = [0]*N
prv_v = [0]*N
prv_e = [None]*N
d0 = [INF]*N
dist = [INF]*N
while f:
dist[:] = d0
dist[s] = 0
que = [(0, s)]
while que:
c, v = heappop(que)
if dist[v] < c:
continue
r0 = dist[v] + H[v]
for e in G[v]:
w, cap, cost, _ = e
if cap > 0 and r0 + cost - H[w] < dist[w]:
dist[w] = r = r0 + cost - H[w]
prv_v[w] = v; prv_e[w] = e
heappush(que, (r, w))
if dist[t] == INF:
return None
for i in range(N):
H[i] += dist[i]
d = f; v = t
while v != s:
d = min(d, prv_e[v][1])
v = prv_v[v]
f -= d
res += d * H[t]
v = t
while v != s:
e = prv_e[v]
e[1] -= d
e[3][1] += d
v = prv_v[v]
return res
import sys,random
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
N,K = mi()
G = MinCostFlow(N)
A = [0 for i in range(N)]
for i in range(N):
A[i],M = mi()
B = li()
for pi in B:
G.add_edge(pi-1,i,1,A[pi-1]-A[i])
for i in range(N-1):
G.add_edge(i,i+1,K,0)
f = G.flow(0,N-1,K)
print(-f)
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