結果
| 問題 |
No.674 n連勤
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2021-09-21 20:36:08 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 26 ms / 2,000 ms |
| コード長 | 4,270 bytes |
| コンパイル時間 | 885 ms |
| コンパイル使用メモリ | 78,140 KB |
| 最終ジャッジ日時 | 2025-01-24 16:10:18 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 17 |
ソースコード
#define PROBLEM "https://yukicoder.me/problems/no/674"
#include <iostream>
#include <map>
namespace suisen {
template <typename T, bool merge_adjacent_segment = true>
struct RangeSet : public std::map<T, T> {
public:
RangeSet() : _size(0) {}
// returns the number of intergers in this set (not the number of ranges). O(1)
T size() const { return number_of_elements(); }
// returns the number of intergers in this set (not the number of ranges). O(1)
T number_of_elements() const { return _size; }
// returns the number of ranges in this set (not the number of integers). O(1)
int number_of_ranges() const { return std::map<T, T>::size(); }
// returns whether the given integer is in this set or not. O(log N)
bool contains(T x) const {
auto it = this->upper_bound(x);
return it != this->begin() and x <= std::prev(it)->second;
}
/**
* returns the iterator pointing to the range [l, r] in this set s.t. l <= x <= r.
* if such a range does not exist, returns `end()`.
* O(log N)
*/
auto find_range(T x) const {
auto it = this->upper_bound(x);
return it != this->begin() and x <= (--it)->second ? it : this->end();
}
// returns whether `x` and `y` is in this set and in the same range. O(log N)
bool in_the_same_range(T x, T y) const {
auto it = get_containing_range(x);
return it != this->end() and it->first <= y and y <= it->second;
}
// inserts the range [x, x] and returns the number of integers inserted to this set. O(log N)
T insert(T x) {
return insert(x, x);
}
// inserts the range [l, r] and returns the number of integers inserted to this set. amortized O(log N)
T insert(T l, T r) {
if (l > r) return 0;
auto it = this->upper_bound(l);
if (it != this->begin() and is_mergeable(std::prev(it)->second, l)) {
it = std::prev(it);
l = std::min(l, it->first);
}
T inserted = 0;
for (; it != this->end() and is_mergeable(r, it->first); it = std::map<T, T>::erase(it)) {
auto [cl, cr] = *it;
r = std::max(r, cr);
inserted -= cr - cl + 1;
}
inserted += r - l + 1;
(*this)[l] = r;
_size += inserted;
return inserted;
}
// erases the range [x, x] and returns the number of intergers erased from this set. O(log N)
T erase(T x) {
return erase(x, x);
}
// erases the range [l, r] and returns the number of intergers erased from this set. amortized O(log N)
T erase(T l, T r) {
if (l > r) return 0;
T tl = l, tr = r + 1;
auto it = this->upper_bound(l);
if (it != this->begin() and l <= std::prev(it)->second) {
it = std::prev(it);
tl = it->first;
}
T erased = 0;
for (; it != this->end() and it->first <= r; it = std::map<T, T>::erase(it)) {
auto [cl, cr] = *it;
tr = cr;
erased += cr - cl + 1;
}
if (tl < l) {
(*this)[tl] = l - 1;
erased -= l - tl;
}
if (r < tr) {
(*this)[r + 1] = tr;
erased -= tr - r;
}
_size -= erased;
return erased;
}
private:
T _size;
bool is_mergeable(T cur_r, T next_l) {
return next_l <= cur_r + merge_adjacent_segment;
}
};
} // namespace suisen
using suisen::RangeSet;
int main() {
std::ios::sync_with_stdio(false);
std::cin.tie(nullptr);
long long d;
int q;
std::cin >> d >> q;
long long ans = 0;
RangeSet<long long> set;
while (q --> 0) {
long long l, r;
std::cin >> l >> r;
set.insert(l, r);
auto [nl, nr] = *set.find_range(l);
ans = std::max(ans, nr - nl + 1);
std::cout << ans << '\n';
}
return 0;
}