結果

問題 No.1695 Mirror Mirror
ユーザー chineristAC
提出日時 2021-10-01 22:54:03
言語 PyPy3
(7.3.15)
結果
RE  
(最新)
AC  
(最初)
実行時間 -
コード長 2,714 bytes
コンパイル時間 337 ms
コンパイル使用メモリ 82,304 KB
実行使用メモリ 180,412 KB
最終ジャッジ日時 2024-12-29 20:07:22
合計ジャッジ時間 16,567 ms
ジャッジサーバーID
(参考情報)
judge5 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 60 RE * 1
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class SegmentTree:
def __init__(self, init_val, segfunc, ide_ele):
n = len(init_val)
self.segfunc = segfunc
self.ide_ele = ide_ele
self.num = 1 << (n - 1).bit_length()
self.tree = [ide_ele] * 2 * self.num
self.size = n
for i in range(n):
self.tree[self.num + i] = init_val[i]
for i in range(self.num - 1, 0, -1):
self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])
def update(self, k, x):
k += self.num
self.tree[k] = x
while k > 1:
k >>= 1
self.tree[k] = self.segfunc(self.tree[2*k], self.tree[2*k+1])
def query(self, l, r):
if r==self.size:
r = self.num
res = self.ide_ele
l += self.num
r += self.num
right = []
while l < r:
if l & 1:
res = self.segfunc(res, self.tree[l])
l += 1
if r & 1:
right.append(self.tree[r-1])
l >>= 1
r >>= 1
for e in right[::-1]:
res = self.segfunc(res,e)
return res
from math import radians
import sys,random
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
"""
from:https://tjkendev.github.io/procon-library/python/string/manacher.html
"""
#
# R[2*i] = L: S[i]
# R[2*i+1] = L: S[i:i+2]
# R[i]
def manacher(S):
C = []
for a in S:
C.append(a)
C.append(0)
C.pop()
L = len(C)
R = [0]*L
i = j = 0
while i < L:
while j <= i < L-j and C[i-j] == C[i+j]:
j += 1
R[i] = j
k = 1
while j-R[i-k] > k <= i < L-k:
R[i+k] = R[i-k]
k += 1
i += k; j -= k
return R
N,M = mi()
S = input()
T = input()
if M&1:
exit(print(-1))
if any(T[i]!=T[-i-1] for i in range(M)):
exit(print(-1))
R = manacher(T)
m = M//2
INF = 10**9
dp = [INF for i in range(M)]
dp[-1] = 0
dp = SegmentTree([INF]*M,min,INF)
dp.update(M-1,0)
for i in range(M-2,-1,-1):
l = i
r = i + (R[2*i+1]//2)
tmp = dp.query(l+1,r+1) + 1
if tmp < INF:
dp.update(i,tmp)
dp = dp.tree[dp.num:]
res = INF
for i in range(N):
if S[i]==T[i]:
res = min(res,dp[i])
else:
break
for i in range(N-1,-1,-1):
if S[i]==T[M-1-(N-1-i)]:
res = min(res,dp[N-1-i])
else:
break
if res==INF:
print(-1)
else:
print(res)
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